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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#737549 | #9622. 有限小数 | fishcathu | RE | 0ms | 0kb | C++20 | 3.5kb | 2024-11-12 16:10:51 | 2024-11-12 16:10:52 |
answer
#include<bits/stdc++.h>
#define ls i<<1
#define rs i<<1|1
#define fi first
#define se second
#define min amin
#define max amax
#define eb emplace_back
using namespace std;
using ll=long long;
using LL=__int128;
using pii=pair<int,int>;
const int N=2E5+10;
const int inf=1E9;
const int p=998244353;
template<typename T=int>T read(){T x;cin>>x;return x;}
template<typename U,typename V>U min(const U &x,const V &y){return x<y?x:y;}
template<typename U,typename V>U max(const U &x,const V &y){return y<x?x:y;}
template<typename U,typename ...V>U min(const U &x,const V &...y){return min(x,min(y...));}
template<typename U,typename ...V>U max(const U &x,const V &...y){return max(x,max(y...));}
template<typename U,typename V>bool cmin(U &x,const V &y){return y<x?x=y,true:false;}
template<typename U,typename V>bool cmax(U &x,const V &y){return x<y?x=y,true:false;}
template<typename U,typename ...V>bool cmin(U &x,const V &...y){return cmin(x,min(y...));}
template<typename U,typename ...V>bool cmax(U &x,const V &...y){return cmax(x,max(y...));}
template<typename T>T qpow(T x,int n){T y(1);for(;n;n>>=1,x*=x)if(n&1)y*=x;return y;}
ll sqrt_floor(const ll &x){ll l=0,r=INT_MAX;while(l+1^r){ll mid=l+r>>1;(x<mid*mid?r:l)=mid;}return l;}
ll sqrt_ceil(const ll &x){ll l=-1,r=INT_MAX;while(l+1^r){ll mid=l+r>>1;(mid*mid<x?l:r)=mid;}return r;}
istream &operator>>(istream &is,LL &x){string a;is>>a;bool k=a[0]=='-';if(k)a=a.substr(1);x=0;for(char &t:a)x=x*10+t-48;if(k)x=-x;return is;}
ostream &operator<<(ostream &os,LL x){if(x<0)os<<'-',x=-x;string a;do a+=x%10|48;while(x/=10);reverse(a.begin(),a.end());return os<<a;}
mt19937 rng(time(0));
struct mint{
int x;
mint():x(){}
mint(const int &x):x(x<0?x+p:x){}
mint inv()const{return qpow(*this,p-2);}
mint operator-()const{return mint(x?p-x:x);}
mint &operator+=(const mint &t){return (x+=t.x)<p?0:x-=p,*this;}
mint &operator-=(const mint &t){return (x-=t.x)<0?x+=p:0,*this;}
mint &operator*=(const mint &t){return x=ll(x)*t.x%p,*this;}
mint &operator/=(const mint &t){return *this*=t.inv();}
mint operator+(const mint &t)const{return mint(*this)+=t;}
mint operator-(const mint &t)const{return mint(*this)-=t;}
mint operator*(const mint &t)const{return mint(*this)*=t;}
mint operator/(const mint &t)const{return mint(*this)/=t;}
friend mint operator+(const int &x,const mint &y){return mint(x)+=y;}
friend mint operator-(const int &x,const mint &y){return mint(x)-=y;}
friend mint operator*(const int &x,const mint &y){return mint(x)*=y;}
friend mint operator/(const int &x,const mint &y){return mint(x)/=y;}
friend istream &operator>>(istream &is,mint &t){return is>>t.x;}
friend ostream &operator<<(ostream &os,const mint &t){return os<<t.x;}
};
void solve(){
ll a,b;
cin>>a>>b;
ll c=1;
for(;b%2==0;b/=2)c*=2;
for(;b%5==0;b/=5)c*=5;
ll t=inf/b,mn=inf,res;
for(ll i=1;i<=t;i*=2){
for(ll j=i;j<=t;j*=5){
ll x=a*j;
if(x%c)continue;
x/=c;
ll u=((x-1)/b+1)*b-x,v=b*j,z=__gcd(u,v);
if(x%z||b*j%z)exit(1);
u/=z;
v/=z;
for(;z%2==0;z/=2);
for(;z%5==0;z/=5);
if(z^1)exit(1);
if(cmin(mn,u)){
res=v;
}
}
}
cout<<mn<<' '<<res<<'\n';
}
int main(){
ios::sync_with_stdio(false);
cin.tie(nullptr);
int T;
cin>>T;
while(T--){
solve();
}
return 0;
}
详细
Test #1:
score: 0
Runtime Error
input:
4 1 2 2 3 3 7 19 79