QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#736331 | #9543. Good Partitions | RWeakest | TL | 0ms | 0kb | C++20 | 3.0kb | 2024-11-12 10:08:53 | 2024-11-12 10:08:54 |
answer
#include <cstdio>
#include <vector>
#include <cstring>
#include <climits>
#include <iostream>
#include <algorithm>
using namespace std;
const int MAXN = 2e5 + 100;
int ans[MAXN];
int cnt(int x)
{
int num = 1;
for (int i = 2; i * i <= x; ++i)
if (!(x % i))
{
int temp = 0;
while (!(x % i))
x /= i, temp++;
num *= (temp + 1);
}
return x == 1 ? num : num * 2;
}
void get_ans()
{
for (int i = 1; i <= 200000; ++i)
ans[i] = cnt(i);
return;
}
int tree[MAXN], a[MAXN], g[MAXN], n, m;
int ls(int x)
{
return x << 1;
}
int rs(int x)
{
return (x << 1) | 1;
}
int mid(int l, int r)
{
return l + ((r - l) >> 1);
}
int maintain(int x)
{
tree[x] = __gcd(tree[ls(x)], tree[rs(x)]);
}
void build(int l, int r, int x)
{
if (l == r)
{
tree[x] = g[l];
return;
}
int m = mid(l, r);
build(l, m, ls(x)), build(m + 1, r, rs(x));
maintain(x);
}
void modify(int l, int r, int x, int p, int num)
{
if (l == r && l == x)
{
tree[p] = num;
return;
}
if (mid(l, r) >= x)
modify(l, mid(l, r), x, ls(p), num);
if (x > mid(l, r))
modify(mid(l, r) + 1, r, x, rs(p), num);
maintain(p);
}
int query(int l, int r, int nl, int nr, int p)
{
if (l <= nl && nr <= r)
return tree[p];
int m = mid(nl, nr);
int tot = 0;
if (l <= m)
tot = __gcd(tot, query(l, r, nl, m, ls(p)));
if (r > m)
tot = __gcd(tot, query(l, r, m + 1, nr, rs(p)));
return tot;
}
void solve()
{
int n, m;
cin >> n >> m;
for (int i = 1; i <= n; ++i)
cin >> a[i];
for (int i = 1; i <= n - 1; ++i)
if (a[i] > a[i + 1])
g[i] = i;
build(1, n, 1);
cout << ans[query(1, n, 1, n, 1)] << "\n";
while (m--)
{
int x, w;
cin >> x >> w;
if (x == n)
continue;
a[x] = w;
if (!g[x])
{
if (a[x] > a[x + 1])
{
g[x] = x;
modify(1, n, x, 1, x);
}
}
else
{
if (a[x] <= a[x + 1])
{
g[x] = 0;
modify(1, n, x, 1, 0);
}
}
if (!g[x - 1])
{
if (a[x - 1] > a[x])
{
g[x - 1] = x - 1;
modify(1, n, x - 1, 1, x - 1);
}
}
else
{
if (a[x - 1] <= a[x])
{
g[x - 1] = 0;
modify(1, n, x - 1, 1, 0);
}
}
cout << ans[query(1, n, 1, n, 1)] << '\n';
}
}
signed main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
get_ans();
int t;
cin >> t;
while (t--)
{
solve();
}
return 0;
}
详细
Test #1:
score: 0
Time Limit Exceeded
input:
1 5 2 4 3 2 6 1 2 5 3 5