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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#736280#5421. Factories Once MoreeastcloudTL 8ms60436kbC++173.0kb2024-11-12 09:18:202024-11-12 09:18:20

Judging History

你现在查看的是最新测评结果

  • [2024-11-12 09:18:20]
  • 评测
  • 测评结果:TL
  • 用时:8ms
  • 内存:60436kb
  • [2024-11-12 09:18:20]
  • 提交

answer


#include<bits/stdc++.h>

#define ll long long
#define pi pair<ll,ll>
#define vi vector<ll>
#define cpy(x,y,s) memcpy(x,y,sizeof(x[0])*(s))
#define mset(x,v,s) memset(x,v,sizeof(x[0])*(s))
#define all(x) begin(x),end(x)
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define ary array
#define eb emplace_back

#define N 500005

using namespace std;
ll read(){
    ll x=0,f=1;char ch=getchar();
    while(ch<'0' || ch>'9')f=(ch=='-'?-1:f),ch=getchar();
    while(ch>='0' && ch<='9')x=(x<<1)+(x<<3)+(ch^48),ch=getchar();
    return x*f;
}
void write(ll x){
    if(x<0)x=-x,putchar('-');
    if(x/10)write(x/10);
    putchar(x%10+'0');
}

mt19937 rnd(20080623);

ll rt[N];
struct tg{
    ll k,b;
    tg(ll k=0,ll b=0):k(k),b(b){}
};

struct fhqtreap{
    ll ls[N<<2],rs[N<<2],pri[N<<2],v[N<<2],siz[N<<2];
    tg tag[N<<2];
    ll tot;
    stack<ll> st;
    ll newnode(ll w){
        ll pos=(st.size()?st.top():++tot);
        if(st.size())st.pop();
        tag[pos].k=tag[pos].b=0;ls[pos]=rs[pos]=0;
        v[pos]=w;pri[pos]=rnd();siz[pos]=1;return pos;
    }
    void ps(ll x,tg T){
        ll num=siz[ls[x]]+1;
        v[x]+=T.k*num+T.b;tag[x].k+=T.k;tag[x].b+=T.b;
    }
    void pd(ll x){
        tg T=tag[x];
        if(ls[x])ps(ls[x],T);
        if(rs[x])ps(rs[x],tg(T.k,T.b+(siz[ls[x]]+1)*T.k));
        tag[x].k=tag[x].b=0;
    }
    void upd(ll x){siz[x]=siz[ls[x]]+siz[rs[x]]+1;}
    ll merge(ll L,ll R){
        if(!L || !R)return L|R;
        pd(L);pd(R);
        if(pri[L]>pri[R]){rs[L]=merge(rs[L],R);upd(L);return L;}
        else {ls[R]=merge(L,ls[R]);upd(R);return R;}
    }
    void split(ll x,ll val,ll &L,ll &R){
        if(!x)return L=0,R=0,void();pd(x);
        if(val>v[x]){R=x;split(ls[x],val,L,ls[x]);upd(x);}
        else {L=x;split(rs[x],val,rs[x],R);upd(x);}
    }
    void insert(ll &p,ll x){
        ll L,R;split(p,v[x],L,R);
        L=merge(L,x);
        p=merge(L,R);
    }
    void flat(ll x,vector<ll> &res){
        pd(x);st.push(x);
        if(ls[x])flat(ls[x],res);
        res.pb(v[x]);
        if(rs[x])flat(rs[x],res);
    }
}T;

ll siz[N],n,k;
vector<pi> e[N];

void dfs(ll x,ll fa){
    siz[x]=1;ll son=0;
    for(auto _:e[x]){
        ll v=_.fi,w=_.se;
        if(v==fa)continue;dfs(v,x);
        if(siz[v]>siz[son])son=v;
        T.ps(rt[v],tg(-2*w,w*(k+1)));
    }
    if(son)rt[x]=rt[son];
    T.insert(rt[x],T.newnode(0));
    for(auto _:e[x]){
        ll v=_.fi,w=_.se;
        if(v==fa || v==son)continue;
        vector<ll> s;
        T.flat(rt[v],s);
        for(auto w:s)T.insert(rt[x],T.newnode(w));
    }
}

int main(){
    #ifdef EAST_CLOUD
    freopen("a.in","r",stdin);
    //freopen("a.out","w",stdout);
    #endif

    n=read(),k=read();
    for(ll i=1;i<n;i++){
        ll u=read(),v=read(),w=read();
        e[u].eb(v,w);e[v].eb(u,w);
    }
    dfs(1,0);
    vector<ll> res;
    T.flat(rt[1],res);
    ll ans=0;
    for(ll i=0;i<k;i++)ans+=res[i];
    write(ans);
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 60436kb

input:

6 3
1 2 3
2 3 2
2 4 1
1 5 2
5 6 3

output:

22

result:

ok 1 number(s): "22"

Test #2:

score: 0
Accepted
time: 8ms
memory: 59036kb

input:

4 3
1 2 2
1 3 3
1 4 4

output:

18

result:

ok 1 number(s): "18"

Test #3:

score: 0
Accepted
time: 8ms
memory: 48128kb

input:

2 2
1 2 1

output:

1

result:

ok 1 number(s): "1"

Test #4:

score: -100
Time Limit Exceeded

input:

100000 17
37253 35652 9892
56367 53643 1120
47896 49255 4547
93065 88999 1745
5251 6742 5031
49828 50972 8974
31548 46729 1032
56341 56287 4812
21896 22838 1682
82124 90557 7307
76289 76949 7028
33834 45380 6856
15499 15064 2265
10127 5251 9920
87208 93945 9487
68990 72637 6891
91640 85004 2259
4748...

output:


result: