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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#731391 | #9568. Left Shifting 3 | ucup-team1766# | AC ✓ | 25ms | 4956kb | C++20 | 3.1kb | 2024-11-10 03:07:49 | 2024-11-10 03:07:49 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
// if you end up using long double, you need to set the floating point notation to fixed, and set the percision to be very high
typedef long double ld;
// contrsuct umaps like this, unordered_map<long long, int, custom_hash> safe_map;
// FIXED_RANDOM is static so it doesn not get redeclared between function calls
struct custom_hash {
static uint64_t splitmix64(uint64_t x) {
// http://xorshift.di.unimi.it/splitmix64.c
x += 0x9e3779b97f4a7c15;
x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;
x = (x ^ (x >> 27)) * 0x94d049bb133111eb;
return x ^ (x >> 31);
}
size_t operator()(uint64_t x) const {
static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();
return splitmix64(x + FIXED_RANDOM);
}
};
const ll INF = 2001001001;
const ll INF2 = 2e18;
const ll MOD = 1000000007;
#define max3(a, b, c) max(a, max(b, c))
#define min3(a, b, c) min(a, min(b, c))
#define pb push_back
#define pf push_front
#define f first
#define s second
#define mp make_pair
#define pll pair<ll, ll>
#define pint pair<int, int>
#define tp make_tuple
const bool testing = 0;
mt19937 rng(63);
// first four are north, west, east ,south
int dir1[] = {1, 0, -1, 0, 1, 1, -1, -1};
int dir2[] = {0, 1, 0, -1, 1, -1, 1, -1};
int main() {
// apparently this does fast i/o
cin.tie(0) , ios::sync_with_stdio(0);
// use this if you read in from a file
/*
freopen("in.txt", "r", stdin);
freopen("out.txt", "w", stdout);
*/
stringstream ss;
// Do it once. Do it right.
// Read the problem statement carefully
// Plan out the steps in words on a piece of paper before implementing
// after RTE(obviously) but also WA, run valgrind!!!
// Testing your solution on samples before coding is a great way to see if you read the problem correctly!!!
// Also take notes about key elements in the problem statement while reading the problem!!!
// If you're stuck, try small cases (not just a trick for math problems)
// When debugging, especially when it's not your code, go through the code line by line, don't just scan
// over sections, and if it's not your code, take notes on what each line does.
//cout << fixed << setprecision(12);
// if you use ld, use the above and don't use string stream
// use instead of ceil(a, b) if a and b are positive
// (a + b - 1) / b
int t;
cin >> t;
while(t > 0){
t--;
int n, k;
cin >> n >> k;
string str;
cin >> str;
if(n < 7){
cout << 0 << "\n";
continue;
}
vector<string> strs;
for(int i = 0; i <= min(6, k); i++){
strs.pb(str.substr(i) + str.substr(0, i));
}
/*
for(int i = 0; i < strs.size(); i++){
cout << strs[i] << " ";
}
cout << "\n";
*/
int maxAm = 0;
for(int i = 0; i < strs.size(); i++){
int sum = 0;
for(int j = 0; j + 6 < n; j++){
if(strs[i].substr(j, 7) == "nanjing") sum++;
}
maxAm = max(maxAm, sum);
}
cout << maxAm << "\n";
}
cout << ss.str();
return 0;
}
这程序好像有点Bug,我给组数据试试?
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3820kb
input:
4 21 10 jingicpcnanjingsuanan 21 0 jingicpcnanjingsuanan 21 3 nanjingnanjingnanjing 4 100 icpc
output:
2 1 3 0
result:
ok 4 number(s): "2 1 3 0"
Test #2:
score: 0
Accepted
time: 18ms
memory: 3996kb
input:
2130 39 7 nnananjingannanjingngnanjinganjinggjina 1 479084228 g 33 2 gqnanjinggrjdtktnanjingcvsenanjin 24 196055605 ginganjingnanjingnanjing 23 3 ngnanjinganjingjinnanji 40 3 njingaaznannanjingnananjingyonwpnanjinga 40 207842908 nanjinggphconanjingkonanjinannanjinglxna 46 3 ingjingnnanjingnanjinging...
output:
3 0 3 2 2 3 3 4 3 4 0 2 4 3 2 1 1 1 4 2 0 3 3 0 0 1 0 0 0 5 4 0 1 2 1 2 2 1 1 1 3 3 1 3 2 0 1 2 4 1 2 1 2 1 2 3 0 1 0 0 1 1 3 2 2 1 0 3 1 2 1 1 4 4 1 1 1 1 0 1 1 1 1 2 0 4 4 3 1 1 2 1 1 1 1 5 1 4 0 1 2 1 3 4 3 3 3 3 1 3 2 1 3 1 2 0 0 1 0 5 0 2 0 3 1 0 2 2 3 2 1 2 0 1 1 1 2 4 1 3 2 0 1 1 2 2 2 1 0 3 ...
result:
ok 2130 numbers
Test #3:
score: 0
Accepted
time: 25ms
memory: 4956kb
input:
3 100000 998244353 gbppzfsncqyzmuwrcvtxsciucxusskcjhaanwhqmyncytwhkubrvcqxgcehdxyewdyvpqjcmrnmlgrytrucexmmfulqbtfctehphmrzkosyvhtvjrromqncbgsjcwhmlqidkycaxyhsrduoxayntuhqubvboseeziwjvrfagsbvtxjjbexnajqapgxydwtztzbbdpoydnjipfizdfpmczgqvdmpvxbqubtygkfpdeonegfzsttirbhzkobbigwneyvtcxndfkljdvbbcfnadtfhgo...
output:
4 1649 3651
result:
ok 3 number(s): "4 1649 3651"
Extra Test:
score: 0
Extra Test Passed