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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#728739#5978. Runaway Quaillittle_pinkpig23 ✓2702ms6620kbC++142.2kb2024-11-09 15:48:552024-11-09 15:48:56

Judging History

你现在查看的是最新测评结果

  • [2024-11-09 15:48:56]
  • 评测
  • 测评结果:23
  • 用时:2702ms
  • 内存:6620kb
  • [2024-11-09 15:48:55]
  • 提交

answer

#include<bits/stdc++.h>
#define MAXN (505)
#define ll long long
#define db double
#define ldb long double
#define pi pair<int,int>
#define fi first
#define se second
using namespace std;
const int lim=500000;
const ldb eps=1e-12,inf=1e18;
template<typename type>
void read(type &x)
{
    bool f=0;char ch=0;x=0;
    while(ch<'0'||ch>'9'){f|=!(ch^'-');ch=getchar();}
    while(ch>='0'&&ch<='9'){x=(x<<3)+(x<<1)+(ch^48);ch=getchar();}
    x=f?-x:x;
}
template<typename type,typename... Args>
void read(type &x,Args &... args)
{
    read(x);
    read(args...);
}
int test,vt,n,tota,totb,cas;
int pos[MAXN],v[MAXN];
ldb f[MAXN][MAXN];
struct node{
    int pos,vc;
    inline bool operator<(node rsh){return (vc^rsh.vc)?(vc<rsh.vc):(pos<rsh.pos);}
}a[MAXN],b[MAXN];
inline ldb getpos(node x,ldb tim){return x.pos+tim*x.vc;}
inline ldb gettim(node x,ldb tim){return getpos(x,tim)/(vt-x.vc);}
void solve()
{
    read(vt,n);
    for(int i=1;i<=n;i++) read(pos[i]);
    for(int i=1;i<=n;i++) read(v[i]);
    tota=totb=0;
    for(int i=1;i<=n;i++)
    {
        if(pos[i]<0) a[++tota]={-pos[i],v[i]};
        else b[++totb]={pos[i],v[i]};
    }
    sort(a+1,a+tota+1),sort(b+1,b+totb+1);
    for(int i=0;i<=tota;i++) fill(f[i],f[i]+totb+1,inf);
    f[tota][totb]=0;
    for(int i=tota;~i;i--)
    {
        for(int j=totb;~j;j--)
        {
            ldb t=f[i][j],pos1=getpos(a[i],t),pos2=getpos(b[j],t),mx=0;
            for(int k=i;k;k--)
            {
                if(pos1-getpos(a[k],t)<=eps) mx=max(mx,gettim(a[k],t));
                ldb ntim=t+mx*2;
                if(k==1&&!j) ntim-=mx;
                f[k-1][j]=min(f[k-1][j],ntim);
            }
            mx=0;
            for(int k=j;k;k--)
            {
                if(pos2-getpos(b[k],t)<=eps) mx=max(mx,gettim(b[k],t));
                ldb ntim=t+mx*2;
                if(k==1&&!i) ntim-=mx;
                f[i][k-1]=min(f[i][k-1],ntim);
            }
        }
    }
    printf("Case #%d: %.10Lf\n",++cas,f[0][0]);
}
int main()
{
#ifndef ONLINE_JUDGE
    freopen(".in","r",stdin);
    freopen(".out","w",stdout);
#endif
    read(test);
    for(int i=1;i<=test;i++) solve();
}

詳細信息

Subtask #1:

score: 8
Accepted

Test #1:

score: 8
Accepted
time: 1ms
memory: 4048kb

input:

50
4 3
-3 -6 -9
3 2 1
2 2
1 -1
1 1
1000 25
769234 -5735820 -524288 -5403090 -6429140 1574982 1 -9733628 -1407481 4093041 4117720 -3193501 -9765195 -3069520 1122216 -5799108 131072 -8482066 -256 -8021159 -8958386 -7027036 5370579 -3602534 -6834567
425 102 744 155 339 19 999 19 159 198 51 304 369 601 ...

output:

Case #1: 3.0000000000
Case #2: 5.0000000000
Case #3: 51133.9375000000
Case #4: 429262.3961421099
Case #5: 129368.0122795970
Case #6: 7801.8320312500
Case #7: 66656.8125000000
Case #8: 607220.6904235145
Case #9: 5725896.8763440860
Case #10: 129205.2852201258
Case #11: 64298.0000000000
Case #12: 61088...

result:

ok correct! (50 test cases)

Subtask #2:

score: 15
Accepted

Test #2:

score: 15
Accepted
time: 2702ms
memory: 6620kb

input:

50
4 3
-3 -6 -9
3 2 1
2 2
1 -1
1 1
1000 500
-9650379 9806301 -6495789 -1283284 5022779 4725553 9364178 -8123302 -9609729 7847458 -142364 6983908 8147008 -3186924 7339254 -8737645 8757174 7887319 3609962 5780915 -1752801 -1657946 -9511339 5113995 -7887160 -6093170 260267 -3837106 -356098 6676924 6210...

output:

Case #1: 3.0000000000
Case #2: 5.0000000000
Case #3: 205911250.0888888889
Case #4: 36298.0000000000
Case #5: 186002.2500000000
Case #6: 13741948.5000000000
Case #7: 109001.1250000000
Case #8: 38656.8125000000
Case #9: 128881.0561480552
Case #10: 8069407.9870967742
Case #11: 128881.0561480552
Case #1...

result:

ok correct! (50 test cases)

Extra Test:

score: 0
Extra Test Passed