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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#72793#4234. Tic Tac Toe CountingLinshey#WA 25ms4376kbC++231.8kb2023-01-19 13:27:122023-01-19 13:27:14

Judging History

This is the latest submission verdict.

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-01-19 13:27:14]
  • Judged
  • Verdict: WA
  • Time: 25ms
  • Memory: 4376kb
  • [2023-01-19 13:27:12]
  • Submitted

answer


#include <bits/stdc++.h>

using namespace std;

int f[1 << 18], g[1 << 18];

int mp[3][3], cov = 0;

inline void cons(int S)
{
    cov = 0;
    for (int i = 0; i < 3; i++) for (int j = 0; j < 3; j++) if (mp[i][j] = (S >> (i * 3 + j << 1) & 3)) cov ^= 1;
}

inline int Cons()
{
    int S = 0;
    for (int i = 0; i < 3; i++) for (int j = 0; j < 3; j++) S |= mp[i][j] << (i * 3 + j << 1);
    return S;
}

inline bool ck(int x)
{
    for (int i = 0; i < 3; i++)
    {
        bool is = 1;
        for (int j = 0; j < 3; j++) if (mp[i][j] != x) { is = 0; break; }
        if (is) return true;
    }
    for (int i = 0; i < 3; i++)
    {
        bool is = 1;
        for (int j = 0; j < 3; j++) if (mp[j][i] != x) { is = 0; break; }
        if (is) return true;
    }
    return (mp[0][0] == x && mp[1][1] == x && mp[2][2] == x) || (mp[2][0] == x && mp[1][1] == x && mp[0][2] == x);
}

int main()
{
    for (int S = (1 << 18) - 1; S >= 0; S--)
    {
        bool is = 0;
        for (int i = 0; i < 9; i++) if ((S >> (i << 1) & 3) == 3) { is = 1; break; }
        if (is) continue;
        cons(S);
        bool f1 = ck(1), f2 = ck(2);
        if (f1 && f2) continue;
        if (f1) { f[S] = 1; continue; }
        if (f2) { g[S] = 1; continue; }
        int t = cov + 1;
        for (int i = 0; i < 3; i++) for (int j = 0; j < 3; j++) if (!mp[i][j])
        {
            mp[i][j] = t;
            int T = Cons();
            f[S] += f[T], g[S] += g[T];
            mp[i][j] = 0;
        }
    }
    int Q; scanf("%d", &Q); while (Q--)
    {
        char s[11];
        scanf("%s", s);
        int S = 0;
        for (int i = 0; i < 9; i++) S |= (int(s[i] != '.') + int(s[i] == 'O')) << (i << 1);
        if (f[S] == 0 && g[S] == 0) puts("-1 -1");
        else printf("%d %d\n", f[S], g[S]);
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 4372kb

input:

4
XX..O....
X...OX...
OOOX.X.X.
OOOXXX...

output:

191 194
232 200
0 1
-1 -1

result:

ok 4 lines

Test #2:

score: 0
Accepted
time: 13ms
memory: 4212kb

input:

100000
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
.........
......

output:

131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
131184 77904
1...

result:

ok 100000 lines

Test #3:

score: -100
Wrong Answer
time: 25ms
memory: 4376kb

input:

100000
.........
X........
O........
.X.......
XX.......
OX.......
.O.......
XO.......
OO.......
..X......
X.X......
O.X......
.XX......
XXX......
OXX......
.OX......
XOX......
OOX......
..O......
X.O......
O.O......
.XO......
XXO......
OXO......
.OO......
XOO......
OOO......
...X.....
X..X.....
O.....

output:

131184 77904
14652 7896
3384 16044
14232 10176
1861 144
1798 1276
5904 16392
2048 756
624 1878
14652 7896
1751 0
1832 1132
1861 144
1 0
220 248
2048 756
268 144
136 316
3384 16044
1832 1132
120 1966
1798 1276
220 248
16 348
624 1878
136 316
0 1
14232 10176
1861 144
1798 1276
2728 288
286 36
264 188
...

result:

wrong answer 3rd lines differ - expected: '-1 -1', found: '3384 16044'