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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#727676#4384. WalkXfJbUhpyzgaWWA 1737ms16856kbC++174.9kb2024-11-09 13:32:532024-11-09 13:33:00

Judging History

你现在查看的是最新测评结果

  • [2024-11-09 13:33:00]
  • 评测
  • 测评结果:WA
  • 用时:1737ms
  • 内存:16856kb
  • [2024-11-09 13:32:53]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
#define F(i, a, b) for (int i = (a), iee = (b); i <= iee; i++)
#define FO(i, a, b) for (int i = (a), iee = (b); i < iee; i++)
#define R(i, a, b) for (int i = (a), iee = (b); i >= iee; i--)

const int N = 1 << 18, M = 998244353;
int power(int x, int y) {
    int ans = 1;
    for (; y; y >>= 1, x = 1ll * x * x % M) if (y & 1)
        ans = 1ll * ans * x % M;
    return ans;
}

int n, m, a[N], b[N], inva[N];

struct mint {
    int val;
    static int chk(int x) { return x < 0 ? x + M : x; }
    mint(): val() {}
    mint(ll v): val(chk(v % M)) {}
    mint(int v, int w): val(v) {}
    explicit operator int() const { return val; }
    mint &operator += (mint b) { return val = chk(val + b.val - M), *this; }
    mint &operator -= (mint b) { return val = chk(val - b.val), *this; }
    mint &operator *= (mint b) { return val = 1ll * val * b.val % M, *this; }
    friend mint operator + (mint a, mint b) { return a += b; }
    friend mint operator - (mint a, mint b) { return a -= b; }
    friend mint operator * (mint a, mint b) { return a *= b; }
    friend mint operator ^ (mint x, ll y) {
        if ((y %= M - 1) < 0) y += M - 1;
        mint ans(1);
        for (; y; y >>= 1, x *= x) if (y & 1) ans *= x;
        return ans;
    }
    mint inv() const { return (*this) ^ (M - 2); }
};

void upd(int &x, ll y) { x = (x + y) % M; }
void upd(int &x, int y) { x = x + y >= M ? x + y - M : x + y; }

void force() {
    static int f[N], g[N];
    F(i, 1, m) f[i] = a[i];
    for (int _ = 2; _ <= n; _++) {
        F(i, 1, m) g[i] = f[i], f[i] = 0;
        F(i, 1, m) upd(f[min(m, b[i])], g[i]);
        R(i, m, 1) upd(f[i - 1], f[i]);
        F(i, 1, m) f[i] = 1ll * f[i] * a[i] % M;
    }
    ll ans = 0;
    F(i, 1, m) ans += f[i];
    cout << ans % M << "\n";
}

void ntt(mint *a, int n, int typ) {
    for (int i = 0, j = 0; i < n; i++) {
        if (i < j) swap(a[i], a[j]);
        for (int l = n >> 1; (j ^= l) < l; l >>= 1);
    }
    for (int m = 1, k = 2; m < n; m <<= 1, k <<= 1) {
        mint g = mint(3) ^ ((M - 1) / k * typ), o(1);
        for (int j = 0; j < n; j += k, o = 1) {
            for (int i = 0; i < m; i++, o *= g) {
                mint x = o * a[i + j + m];
                a[i + j + m] = a[i + j] - x;
                a[i + j] += x;
            }
        }
    }
    if (!~typ) {
        mint invn = mint(n).inv();
        FO(i, 0, n) a[i] *= invn;
    }
}

using poly = vector<mint>;
int sup(int n) { return 1 << (32 - __builtin_clz(n - 1)); }

poly inv(poly g) {
    int tn = g.size(), n = sup(tn);
    g.resize(n);
    poly f(n);
    f[0] = g[0].inv();
    for (int m = 1, k = 2; m < n; m <<= 1, k <<= 1) {
        poly h(&g[0], &g[k]);
        ntt(&h[0], k, 1);
        poly f0(&f[0], &f[k]);
        ntt(&f0[0], k, 1);
        FO(i, 0, k) h[i] = mint() - h[i] * f0[i];
        ntt(&h[0], k, -1);
        fill(&h[0], &h[m], mint());
        ntt(&h[0], k, 1);
        FO(i, 0, k) h[i] *= f0[i];
        ntt(&h[0], k, -1);
        copy(&h[m], &h[k], &f[m]);
    }
    f.resize(tn);
    return f;
}

struct Matrix {
    poly f[3][3];
};

Matrix solve(int l, int r) {
    if (l == r) {
        Matrix ret;
        ret.f[1][0] = ret.f[2][1] = {1};
        ret.f[0][0] = {M - inva[l]};
        int t = b[l] - l;
        mint val(1);
        F(j, l + 1, b[l]) val *= M - inva[j];
        ret.f[0][t].resize(2);
        ret.f[0][t][1] = val;
        return ret;
    }
    int mid = (l + r) >> 1;
    Matrix A = solve(l, mid), B = solve(mid + 1, r), C;
    
    int n = 0, m = 0;
    F(i, 0, 2) F(j, 0, 2) n = max<int>(n, A.f[i][j].size()), m = max<int>(m, B.f[i][j].size());
    n = sup(n + m - 1);
    F(i, 0, 2) F(j, 0, 2) {
        A.f[i][j].resize(n), B.f[i][j].resize(n), C.f[i][j].resize(n);
        ntt(&A.f[i][j][0], n, 1);
        ntt(&B.f[i][j][0], n, 1);
    }
    F(i, 0, 2) F(j, 0, 2) F(k, 0, 2) FO(t, 0, n)
        C.f[i][j][t] += A.f[i][k][t] * B.f[k][j][t];
    F(i, 0, 2) F(j, 0, 2) {
        ntt(&C.f[i][j][0], n, -1);
        while (!C.f[i][j].empty() && (int)C.f[i][j].back() == 0) C.f[i][j].pop_back();
    }
    return C;
}

void solve() {
    F(i, 1, m) inva[i] = power(a[i], M - 2);
    poly g = solve(1, m).f[0][0];
    poly f(g.begin() + 1, g.end());
    g.resize(n);
    poly h = inv(g);
    mint ans;
    FO(i, 0, min<int>(n, f.size())) ans -= f[i] * h[n - 1 - i];
    cout << (int)ans;
}

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

int main() {
    cin >> n >> m;
    F(i, 1, m) cin >> a[i];
    static int rank[N];
    int cnt = 0;
    F(i, 1, m) {
        cnt += !!a[i];
        rank[i] = cnt;
        auto s = [](int x) { return 31 - __builtin_clz(max(x, 1)); };
        b[i] = min(m, i + s(s(s(i))));
    }
    F(i, 1, m) if (a[i]) a[rank[i]] = a[i], b[rank[i]] = rank[b[i]];
    m = cnt;
    solve();
}

详细

Test #1:

score: 0
Wrong Answer
time: 1737ms
memory: 16856kb

input:

99990 99987
757148 167851001 301413357 336971125 659598369 160567226 391749388 4890852 35766291 26239573 473038165 597007 3615545 326051437 392289611 118341523 170427799 37215529 675016434 168544291 683447134 950090227 82426873 116752252 194041605 706221269 71664782 257655784 84970744 21417563 37379...

output:

748098408

result:

wrong output format Extra information in the output file