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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#726273 | #9529. Farm Management | rdcamelot | WA | 0ms | 3532kb | C++20 | 1.3kb | 2024-11-08 22:40:37 | 2024-11-08 22:40:39 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
using i64=long long;
using u64=unsigned long long;
#define ll long long
const int inf=1e9;
const ll inff=1e18;
using i128=__int128;
void solve(){
int n,m;
cin>>n>>m;
vector<pair<int,pair<int,int>>> a(n);
for(int i=0;i<n;i++){
cin>>a[i].first>>a[i].second.first>>a[i].second.second;
}
sort(a.begin(),a.end(),greater());
vector<i64> del(n),l(n),delpro(n);
i64 sum=0ll;
for(int i=0;i<n;i++){
m-=a[i].second.first;
del[i]=a[i].second.second-a[i].second.first;
delpro[i]=1ll*a[i].first*del[i];
l[i]=1ll*a[i].first*a[i].second.first;
sum+=l[i];
}
for(int i=1;i<n;i++){
del[i]+=del[i-1];
delpro[i]+=delpro[i-1];
}
// sum 所有下限的和,del r-l的和,delpro 对应增量的和
// id是完全能加满的位置
i64 ans=sum+m*a[0].first;
for(int i=1;i<n;i++){
int id=upper_bound(del.begin(),del.end(),a[i].second.first+m)-del.begin()-1;
id=min(id,i-1);
ans=max(sum-l[i]+(a[i].second.first+m-del[id])*a[id+1].first+delpro[id],ans);
}
cout<<ans<<'\n';
}
int main(){
ios::sync_with_stdio(0);cin.tie(0);
int t=1;
// cin>>t;
while(t--){
solve();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3532kb
input:
5 17 2 3 4 6 1 5 8 2 4 4 3 3 7 5 5
output:
109
result:
ok single line: '109'
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3528kb
input:
12 62 503792 9 10 607358 1 3 600501 10 10 33249 4 4 774438 6 6 197692 3 6 495807 8 8 790225 5 9 77272 3 8 494819 4 9 894779 3 9 306279 5 6
output:
34859047
result:
wrong answer 1st lines differ - expected: '35204500', found: '34859047'