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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#726257#7900. Gifts from Knowledgesnow_mikumikuWA 20ms60264kbC++142.2kb2024-11-08 22:36:392024-11-08 22:36:40

Judging History

你现在查看的是最新测评结果

  • [2024-11-08 22:36:40]
  • 评测
  • 测评结果:WA
  • 用时:20ms
  • 内存:60264kb
  • [2024-11-08 22:36:39]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
using LL = long long;
const int N = 1e6 + 10;
const LL mod = 1e9 + 7;

string S[N];
vector <int> G[N];
int n, m, fa[N];
int find(int x) {
    if(fa[x] != x) fa[x] = find(fa[x]);
    return fa[x];
}

void solve()
{
    
    cin >> n >> m;
    for(int i = 1; i <= n; i++) cin >> S[i];

    vector <int> belo(m);
    for(int i = 1; i <= n; i++) fa[i] = i, G[i].clear();

    for(int i = 1; i <= n; i++) {
        for(int j = 0; j < m; j++) {
            if(S[i][j] == '1') {
                if(belo[j]) {
                    fa[belo[j]] = i;
                    belo[j] = i;
                }
                else belo[j] = i;
                if(belo[m - j - 1]) {
                    fa[belo[m - j - 1]] = i;
                    belo[m - j - 1] = i;
                }
                else belo[m - j - 1] = i;
            }
        }
    }

    for(int i = 1; i <= n; i++) {
        int ri = find(i);
        G[ri].push_back(i);
    }

    vector <int> ck(m);
    for(int i = 1; i <= n; i++) 
    {
        if(!G[i].size()) continue;
        for(int j = 0; j < G[i].size(); j++) 
        {
            int x = G[i][j];
            int f = 1;
            for(int k = 0; k < m; k++) {
                if(ck[k] && S[x][k] == '1') {
                    f = 0;
                    break;
                }
            }

            if(f) {
                for(int k = 0; k < m; k++) {
                    if(S[x][k] == '1') ck[k] = 1;
                }
            }
            else {
                for(int k = 0; k < m; k++) {
                    if(S[x][k] == '1' && ck[m - k - 1]) {
                        cout << 0 << '\n';
                        return;
                    }
                }

                for(int k = 0; k < m; k++) {
                    if(S[x][k] == '1') ck[m - k - 1] = 1;
                }
            }
        }
    }

    LL ans = 1;
    for(int i = 1; i <= n; i++) {
        if(find(i) == i) ans *= 2, ans %= mod;
    }
    cout << ans << '\n';
}
int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    int t;
    cin >> t;
    while(t--) solve();
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 3ms
memory: 60264kb

input:

3
3 5
01100
10001
00010
2 1
1
1
2 3
001
001

output:

4
0
2

result:

ok 3 number(s): "4 0 2"

Test #2:

score: 0
Accepted
time: 20ms
memory: 58788kb

input:

15613
10 10
0000000000
0000000000
0000000000
0000000000
0000000000
0000000000
0000000000
0000000000
0000000000
0000000000
15 8
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
00000000
1 5
00000
5 9
000000000
000000000
0000...

output:

1024
32768
2
32
32768
128
32
16
16
2
16384
16384
128
128
32768
8192
128
64
16384
2
4
2
4096
16
4096
1024
32768
32768
16384
8
128
2
16
4096
8192
32768
8192
8192
16
16384
16384
256
128
8
256
8
4096
512
2
4
32
32
2
64
512
1024
32768
32768
2
64
16384
16
8192
16
256
16
64
8192
8192
64
1024
2
32768
2
4
51...

result:

ok 15613 numbers

Test #3:

score: 0
Accepted
time: 10ms
memory: 58696kb

input:

15759
9 6
000000
000000
000000
000000
000000
000000
000000
000000
000000
5 15
010000000000000
000000000000000
000000000000000
000100000000000
000100000000000
14 12
000000000000
000000000000
000000000000
000000000000
000000000000
000000000000
000000000000
000000000000
000000000000
000000000000
000000...

output:

512
16
16384
512
1024
4096
32768
4
2
512
512
512
512
8
2
256
16
4096
512
64
16
4096
512
32
32768
8192
32
2048
128
16
4096
64
32768
256
32
16384
8
512
32
2048
8
16
1024
2048
128
64
32
8
512
8
8192
256
8192
32768
2
8
512
512
256
32
2
2048
8192
8
64
8
2
16384
32768
32768
1024
4096
16384
16384
128
256
4...

result:

ok 15759 numbers

Test #4:

score: -100
Wrong Answer
time: 16ms
memory: 58764kb

input:

15734
3 6
000101
010000
001110
5 7
0010010
1000000
0101000
0000000
0000000
10 9
000000000
100000000
000000000
000000000
000010000
000000001
000000000
000000000
000000000
000000000
5 14
10000000000000
00001001000000
00000100000000
00000000000000
00000100000000
5 14
00000000000000
00010000000100
00000...

output:

0
16
512
16
32
4096
0
256
0
0
0
0
4096
8
1024
128
8192
0
128
0
2
0
0
32
64
0
0
0
4096
128
8
8
32
128
64
4096
2
512
16384
4
2
0
0
32
0
4096
8
0
8192
256
256
64
0
32
0
32
0
256
4
16384
1024
4
0
16
256
0
2048
64
8
0
0
32768
2048
512
2048
2
0
8192
0
2
2048
16
512
256
1024
0
0
2
32
512
16384
0
32
1024
10...

result:

wrong answer 30th numbers differ - expected: '64', found: '128'