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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#725896 | #9528. New Energy Vehicle | yeah14 | RE | 12ms | 84808kb | C++17 | 4.6kb | 2024-11-08 20:33:22 | 2024-11-08 20:33:23 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define ull long long
#define PII pair<int ,int>
const int INF = 0x3f3f3f3f3f3f3f;
const int mod = 1e9 + 7;
const int N = 1e5 + 5;
int fp(int a, int x, int mod) {
int ans = 1;
while (x) {
if (x & 1)ans *= a;
ans %= mod;
a *= a;
a %= mod;
x >>= 1;
}
return ans;
}
bool check1(int n) {
for (int i = 2; i <= n / 2; i++) {
if (n % i == 0)return 0;
}
return 1;
}
struct tree {
int sum, pre, suf;
int tag = -1;
};
tree tr[4 * N];
int ls(int p) { return p << 1; }
int rs(int p) { return (p << 1) + 1; }
int history[N], tot = 0;
void add_tag(int p, int d, int pl, int pr) {
tr[p].tag += d;
tr[p].sum += d * (pr - pl + 1);
}
void push_down(int p, int len) {
if (tr[p].tag != -1) {
tr[ls(p)].tag = tr[rs(p)].tag = tr[p].tag;
tr[ls(p)].pre = tr[ls(p)].sum = (tr[p].tag == 0) ? 0 : (len - (len >> 1));
tr[rs(p)].pre = tr[rs(p)].sum = (tr[p].tag == 0) ? 0 : (len >> 1);
tr[p].tag = -1;
}
}
void push_up(int p, int len) {
tr[p].pre = tr[ls(p)].pre;
tr[p].suf = tr[rs(p)].suf;
if (tr[ls(p)].pre == (len - (len >> 1))) {
tr[p].pre = tr[ls(p)].pre + tr[rs(p)].pre;
}
if (tr[rs(p)].suf == (len >> 1)) {
tr[p].suf = tr[rs(p)].suf + tr[ls(p)].suf;
}
}
void build(int pl, int pr, int p) {
tr[p].tag = -1;
if (pl == pr) {
tr[p].sum = tr[p].pre = tr[p].suf = 1;
return;
}
int mid = (pl + pr) >> 1;
build(pl, mid, ls(p));
build(mid + 1, pr, rs(p));
push_up(p, pr - pl + 1);
}
void update(int L, int R, int c, int p, int pl, int pr) {
if (L <= pl && R >= pr) {
tr[p].pre = tr[p].suf = tr[p].sum = (c == 0) ? 0 : pr - pl + 1;
tr[p].tag = c;
return;
}
int mid = (pl + pr) >> 1;
if (L <= mid)update(L, R, c, ls(p), pl, mid);
if (R > mid)update(L, R, c, rs(p), mid + 1, pr);
//else update(x, c, rs(p), mid + 1, pr);
push_up(p, pr - pl + 1);
}
int query(int len, int p, int pl, int pr) {
if (pl == pr)return pl;
int mid = (pl + pr) >> 1;
if (len <= tr[ls(p)].sum) {
if (len <= tr[p].pre)return pl;
else return query(len, ls(p), pl, mid);
}
else if (len <= tr[rs(p)].pre + tr[ls(p)].suf) {
return mid - tr[ls(p)].suf + 1;
}
else if (len <= tr[rs(p)].sum) {
if (len <= tr[rs(p)].pre)return pl;
else return query(len, rs(p), mid + 1, pr);
}
}
struct strc {
int c, nxt, id;
bool operator<(const strc a)const {
return nxt > a.nxt;
}
};
int a[N];
queue<int>p[N];
PII b[N];
priority_queue<strc>q1, q2;
void solve() {
int n, m;
cin >> n >> m;
int sum = 0;
int ans = 0;
while (!q1.empty())q1.pop();
while (!q2.empty())q2.pop();
for (int i = 1; i <= n; i++) {
cin >> a[i];
while (!p[i].empty())p[i].pop();
}
for (int i = 1; i <= m; i++) {
cin >> b[i].first >> b[i].second;
}
sort(b + 1, b + 1 + m);
b[m + 1] = { INF,INF };
for (int i = 1; i <= m; i++) {
p[b[i].second].push(i);
}
for (int i = 1; i <= n; i++) {
p[i].push(m + 1);
q1.push({ a[i],p[i].front(),i});
p[i].pop();
}
int s = 0;
for (int i = 1; i <= m; i++) {
while (!q1.empty() && s < b[i].first) {
strc tt = q1.top(); q1.pop();
if (s + tt.c>b[i].first) {
tt.c = tt.c - (b[i].first - s);
q1.push(tt);
s = b[i].first;
}
else {
s += tt.c;
if (p[tt.id].empty())continue;
tt.nxt = p[tt.id].front();
tt.c = a[tt.id];
p[tt.id].pop();
q2.push(tt);
}
}
strc tt = q1.top();
if (tt.id == b[i].second) {
q1.pop();
tt.nxt = p[tt.id].front();
tt.c = a[tt.id];
p[tt.id].pop();
q1.push(tt);
}
else {
q1.push(q2.top());
q2.pop();
}
}
while (!q1.empty()) {
s += q1.top().c;
q1.pop();
}
cout << s << endl;
}
//&&(((sum[n]+k)%mid==0)||(sum[n]/mid!=(sum[n]+k)/mid)||(mid-(sum[n]%mid)>=k))
signed main() {
ios::sync_with_stdio(0);
cin.tie(0), cout.tie(0);
int t = 1;
cin >> t;
while (t--) {
solve();
}
//while (t--) {
// //if (k == 100000)cout << k - t + 1 << " ";
// solve();
//}
}
詳細信息
Test #1:
score: 100
Accepted
time: 12ms
memory: 84808kb
input:
2 3 1 3 3 3 8 1 2 2 5 2 1 2 2 1
output:
12 9
result:
ok 2 lines
Test #2:
score: -100
Runtime Error
input:
6 3 2 2 2 2 6 1 7 1 2 2 3 3 2 1 6 2 2 3 2 2 5 1 7 2 9 1 2 2 3 3 2 1 6 2 1 1 999999999 1000000000 1 1 1 1000000000 1000000000 1
output:
9 11 10 11 999999999