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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#725393#8339. Rooted TreeKopicyTL 1461ms108016kbC++231.0kb2024-11-08 17:26:572024-11-08 17:26:57

Judging History

你现在查看的是最新测评结果

  • [2024-11-08 17:26:57]
  • 评测
  • 测评结果:TL
  • 用时:1461ms
  • 内存:108016kb
  • [2024-11-08 17:26:57]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;
#define int long long
#define rep(i, a, b) for(int i=(a);i<=(b);++i)
#define drep(i, a, b) for(int i=(a);i>=(b);--i)
#define IOS ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define sz(x) (int)x.size()
#define endl "\n"
const int N = 2e5, mod = 1e9 + 9, inf = 1e18;

int qpow(int a, int b) {
    int res = 1;
    while (b) {
        if (b & 1) res = res * a % mod;
        a = a * a % mod;
        b >>= 1;
    }
    return res;
}

int inv(int x) { return qpow(x, mod - 2); }

void solve() {
    int m, k;
    cin >> m >> k;
    vector<int> g(k + 1), f(k + 1);
    rep(i, 0, k - 1) {
        g[i + 1] = (g[i] + (f[i] * inv(1 + i * (m - 1)) % mod + 1) * m % mod) %
                   mod;
        f[i + 1] = (f[i] + (f[i] * inv(1 + i * (m - 1)) % mod + 1) * m % mod -
                    f[i] * inv(1 + i * (m - 1)) % mod + mod) % mod;
    }
    cout<<g[k]<<endl;
}

signed main() {
    IOS
    int64_t tt = 1;
    //cin >> tt;
    rep(kase, 1, tt) solve();
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3500kb

input:

6 2

output:

18

result:

ok 1 number(s): "18"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3552kb

input:

2 6

output:

600000038

result:

ok 1 number(s): "600000038"

Test #3:

score: 0
Accepted
time: 134ms
memory: 12688kb

input:

83 613210

output:

424200026

result:

ok 1 number(s): "424200026"

Test #4:

score: 0
Accepted
time: 1461ms
memory: 108016kb

input:

48 6713156

output:

198541581

result:

ok 1 number(s): "198541581"

Test #5:

score: 0
Accepted
time: 0ms
memory: 3624kb

input:

1 111

output:

6216

result:

ok 1 number(s): "6216"

Test #6:

score: -100
Time Limit Exceeded

input:

28 7304152

output:

457266679

result: