#include<iostream>
#include<vector>
#include<algorithm>
#include<set>
#include<iomanip>
#include<queue>
#include<math.h>
#include<map>
#include<bitset>
#include<numeric>
#include <cstring>
#include<array>
#include <string>  
#include<unordered_set>
#include<unordered_map>
using namespace std;
#define int long long
//#define endl "\n"
#define mod 1000000007ll
#define IOS  ios::sync_with_stdio(false),cin.tie(nullptr)
#define syy return
const double pi = acos(-1.0);
using ll = long long;
using pii = pair<int, int>;
using vint = vector<int>;
using vll = vector<ll>;
using vvint = vector<vint>;
using vpo = vector<pii>;
using tup = tuple<int, int, int>;
using vbl = vector<bool>;
constexpr int N = 100000, M = 2000006;//开足够的空间 注意无向图的双向边边数*2
constexpr ll inf = 1e16;
long double eps = 1e-7;


set<int> all;
void solve()
{
    double p1, v1, p2, v2, ans, n;
    cin >> n >> p1 >> v1 >> p2 >> v2;
    if (p1 > p2) {
        swap(p1, p2);
        swap(v1, v2);
    }
    //一个人走完全程
    ans = (min(p1, n - p1) + n) / v1;
    ans = min(ans, (min(p2, n - p2) + n) / v2);
    //相反方向走
    ans = min(ans, (n + p1 + (n - p2)) / (v1 + v2));
    double tt = min(max((p2 + p1) / v1, (n - p2) / v2), max((n - p1 + n - p2) / v2, p1 / v1)), x, x2;
    ans = min(ans, tt);
    //相对方向走
    ans = min(ans, (n + p2 - p1) / (v1 + v2));

    //相同方向走
    x = (2 * n * v1 + p1 * v2 - p2 * v1) / (v1 + 2 * v2);
    if (x >= p1 && x <= p2)
        ans = min(ans, (2 * x - p1) / v1);
   // else ans = min(ans, max((p2 + p2 - p1) / v1, (n - p2) / v2));
    x2 = (n * v1 + p2 * v1 - p1 * v2) / (2 * v1 + v2);
    if (x2 >= p1 && x2 <= p2)
        ans = min(ans, (n + p2 - 2 * x2) / v2);
    //else ans = min(ans, max((p2 - p1 + n - p1) / v2, p1 / v1));
    cout << setiosflags(ios::fixed) << setprecision(10) << ans << endl;
}

signed main() {
    ios::sync_with_stdio(false), cin.tie(nullptr);
    int T = 1;
    cin >> T;
    while (T--) {
        solve();
    }
    return 0;
}