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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#724666#5415. RopewayMitsubachiWA 2ms3664kbC++145.5kb2024-11-08 14:21:232024-11-08 14:21:24

Judging History

你现在查看的是最新测评结果

  • [2024-11-08 14:21:24]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3664kb
  • [2024-11-08 14:21:23]
  • 提交

answer

//g++-13 1.cpp -std=c++17 -O2 -I .
#include <bits/stdc++.h>
using namespace std;

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
#include<ext/pb_ds/tag_and_trait.hpp>
using namespace __gnu_pbds;


#include <algorithm>
#include <cassert>
#include <vector>


#ifdef _MSC_VER
#include <intrin.h>
#endif

namespace atcoder {

namespace internal {

int ceil_pow2(int n) {
    int x = 0;
    while ((1U << x) < (unsigned int)(n)) x++;
    return x;
}

int bsf(unsigned int n) {
#ifdef _MSC_VER
    unsigned long index;
    _BitScanForward(&index, n);
    return index;
#else
    return __builtin_ctz(n);
#endif
}

}  // namespace internal

}  // namespace atcoder


namespace atcoder {

template <class S, S (*op)(S, S), S (*e)()> struct segtree {
  public:
    segtree() : segtree(0) {}
    explicit segtree(int n) : segtree(std::vector<S>(n, e())) {}
    explicit segtree(const std::vector<S>& v) : _n(int(v.size())) {
        log = internal::ceil_pow2(_n);
        size = 1 << log;
        d = std::vector<S>(2 * size, e());
        for (int i = 0; i < _n; i++) d[size + i] = v[i];
        for (int i = size - 1; i >= 1; i--) {
            update(i);
        }
    }

    void set(int p, S x) {
        assert(0 <= p && p < _n);
        p += size;
        d[p] = x;
        for (int i = 1; i <= log; i++) update(p >> i);
    }

    S get(int p) const {
        assert(0 <= p && p < _n);
        return d[p + size];
    }

    S prod(int l, int r) const {
        assert(0 <= l && l <= r && r <= _n);
        S sml = e(), smr = e();
        l += size;
        r += size;

        while (l < r) {
            if (l & 1) sml = op(sml, d[l++]);
            if (r & 1) smr = op(d[--r], smr);
            l >>= 1;
            r >>= 1;
        }
        return op(sml, smr);
    }

    S all_prod() const { return d[1]; }

    template <bool (*f)(S)> int max_right(int l) const {
        return max_right(l, [](S x) { return f(x); });
    }
    template <class F> int max_right(int l, F f) const {
        assert(0 <= l && l <= _n);
        assert(f(e()));
        if (l == _n) return _n;
        l += size;
        S sm = e();
        do {
            while (l % 2 == 0) l >>= 1;
            if (!f(op(sm, d[l]))) {
                while (l < size) {
                    l = (2 * l);
                    if (f(op(sm, d[l]))) {
                        sm = op(sm, d[l]);
                        l++;
                    }
                }
                return l - size;
            }
            sm = op(sm, d[l]);
            l++;
        } while ((l & -l) != l);
        return _n;
    }

    template <bool (*f)(S)> int min_left(int r) const {
        return min_left(r, [](S x) { return f(x); });
    }
    template <class F> int min_left(int r, F f) const {
        assert(0 <= r && r <= _n);
        assert(f(e()));
        if (r == 0) return 0;
        r += size;
        S sm = e();
        do {
            r--;
            while (r > 1 && (r % 2)) r >>= 1;
            if (!f(op(d[r], sm))) {
                while (r < size) {
                    r = (2 * r + 1);
                    if (f(op(d[r], sm))) {
                        sm = op(d[r], sm);
                        r--;
                    }
                }
                return r + 1 - size;
            }
            sm = op(d[r], sm);
        } while ((r & -r) != r);
        return 0;
    }

  private:
    int _n, size, log;
    std::vector<S> d;

    void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};

}  // namespace atcoder

using namespace atcoder;

using ll = long long;
using ld = long double;
 
using vi = vector<int>;
using vvi = vector<vi>;
using vll = vector<ll>;
using vvll = vector<vll>;
using vld = vector<ld>;
using vvld = vector<vld>;
using vst = vector<string>;
using vvst = vector<vst>;
 
#define fi first
#define se second
#define pb push_back
#define eb emplace_back
#define pq_big(T) priority_queue<T,vector<T>,less<T>>
#define pq_small(T) priority_queue<T,vector<T>,greater<T>>
#define all(a) a.begin(),a.end()
#define rep(i,start,end) for(ll i=start;i<(ll)(end);i++)
#define per(i,start,end) for(ll i=start;i>=(ll)(end);i--)
#define uniq(a) sort(all(a));a.erase(unique(all(a)),a.end())

random_device seed;
mt19937_64 randint(seed());

ll grr(ll mi, ll ma) { // [mi, ma)
    return mi + randint() % (ma - mi);
}

ll op(ll a,ll b){
  return min(a,b);
}

ll e(){
  return 1e18;
}

vll make_dp(int k,vll &a,string &s){
  int n=a.size();
  segtree<ll,op,e> seg(n);
  seg.set(0,0);

  int ls=0;  
  rep(i,1,n){
    int left=max(ls,(int)i-k);
    ll pd=seg.prod(left,i);
    seg.set(i,pd+a[i]);
    if(s[i]=='1')ls=i;
  }

  vll res(n);
  rep(i,0,n)res[i]=seg.get(i);
  return res;
}

void solve(){
  int n,k;cin>>n>>k;
  vll a(n+2,0);
  rep(i,1,n+1)cin>>a[i];
  string s;cin>>s;
  s='1'+s+'1';

  vll prefix=make_dp(k,a,s);
  reverse(all(a));
  reverse(all(s));
  vll suffix=make_dp(k,a,s);
  reverse(all(a));
  reverse(all(suffix));

  segtree<ll,op,e> pre(prefix),suf(suffix);

  int q;cin>>q;
  while(q--){
    int p;
    ll v;
    cin>>p>>v;

    // 使う場合
    ll ans=prefix[p]+suffix[p]-2*a[p]+v;

    if(s[p]=='1'){
      cout<<ans<<"\n";
      continue; 
    }

    // 使わない場合
    rep(l,p-k,p){
      if(l<0)continue;
      int rl=p+1,rr=min(n+1,(int)l+k);
      if(rl>rr)continue;
      ans=min(ans,prefix[l]+suf.prod(rl,rr+1));
    }

    cout<<ans<<"\n";
  }
}

int main(){
  ios::sync_with_stdio(false);
  cin.tie(nullptr);

  int t;cin>>t;
  while(t--){
    solve();
  }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3664kb

input:

3
10 3
5 10 7 100 4 3 12 5 100 1
0001000010
2
2 3
6 15
5 6
1 1 1 1 1
00000
1
3 100
5 6
1 1 1 1 1
00100
1
3 100

output:

206
214
0
100

result:

ok 4 number(s): "206 214 0 100"

Test #2:

score: -100
Wrong Answer
time: 2ms
memory: 3580kb

input:

500
19 6
285203460 203149294 175739375 211384407 323087820 336418462 114884618 61054702 243946442 19599175 51974474 285317523 222489944 26675167 300331960 1412281 324105264 33722550 169011266
1111111110110100011
18
3 127056246
5 100630226
14 301161052
2 331781882
5 218792226
2 190274295
12 49227476
...

output:

1271790202
1271790202
2796055445
2650202148
1271790202
2508694561
2285479513
1765265336
2712540666
2240907690
2577284958
2826535456
2766700195
2511807344
2814193324
2438434986
2669077215
2682112324
341886459
729032050
146144035
146144035
238162409
470735446
146144035
18
19
19
19
20
15
54
15465560
15...

result:

wrong answer 1st numbers differ - expected: '2472886431', found: '1271790202'