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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#724354#9246. Dominating PointyldTL 0ms3780kbC++20970b2024-11-08 12:25:082024-11-08 12:25:08

Judging History

你现在查看的是最新测评结果

  • [2024-11-22 18:38:25]
  • hack成功,自动添加数据
  • (/hack/1238)
  • [2024-11-08 12:25:08]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:3780kb
  • [2024-11-08 12:25:08]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
#define endl '\n'
using namespace std;
void solve()
{
    int n;cin>>n;
    vector<int> e[n+1];
    for(int i=1;i<=n;i++)
    {
        string s;cin>>s;
        s=' '+s;
        for(int j=1;j<=n;j++)
            if(s[j]=='1')e[i].push_back(j);
    }
    vector<int> vis(n+1);
    function<void(int,int)> dfs=[&](int u,int dep)
    {
        vis[u]=1;
        if(dep==2) return;
        for(auto v:e[u])
            dfs(v,dep+1);
    };
    vector<int> ans;
    for(int i=1;i<=n;i++)
    {
        fill(vis.begin(),vis.end(),0);
        dfs(i,0);
        int tmp=0;
        for(int i=1;i<=n;i++)
            if(vis[i]==0) tmp=1;
        if(!tmp) ans.push_back(i); 
    }
    if(ans.size()<3) cout<<"NOT FOUND";
    else for(int i=0;i<3;i++) cout<<ans[i]<<' ';
    cout<<endl;
}
signed main()
{
    cin.tie(0)->sync_with_stdio(0);
    int t=1;
    while(t--) solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3608kb

input:

6
011010
000101
010111
100001
010100
100010

output:

1 3 4 

result:

ok OK, Answer correct.

Test #2:

score: 0
Accepted
time: 0ms
memory: 3484kb

input:

3
011
001
000

output:

NOT FOUND

result:

ok OK, Answer correct.

Test #3:

score: 0
Accepted
time: 0ms
memory: 3780kb

input:

3
010
001
100

output:

1 2 3 

result:

ok OK, Answer correct.

Test #4:

score: -100
Time Limit Exceeded

input:

4994
0100001010011001010101110010101000111101111100100001110010000111100000000100110100101000001010100000010010010110110110111010010010100110100000110110111001010111010111010111011001000101001000010001010111110000000100001100000111100011001010010111011100111010101110011000010111101011111110001111110...

output:


result: