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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#720290#9528. New Energy VehiclebulingRE 0ms3604kbC++144.2kb2024-11-07 11:38:332024-11-07 11:38:34

Judging History

This is the latest submission verdict.

  • [2024-11-07 11:38:34]
  • Judged
  • Verdict: RE
  • Time: 0ms
  • Memory: 3604kb
  • [2024-11-07 11:38:33]
  • Submitted

answer

#include <bits/stdc++.h>
using namespace std;
#define lll i << 1
#define rrr i << 1 | 1


//
 #define ll long long
 #define int long long
	#define ld long double
	#define rint register int
	#define inv inline void
	#define ini inline int
//    inline int read()
//    {
//        int sum=0;
//        char ch=getchar();
//        while(ch>'9'||ch<'0') ch=getchar();
//        while(ch>='0'&&ch<='9') sum=sum*10+ch-48,ch=getchar();
//        return sum;
//    }//读入优化
//	
//    
//    inline void print(int x){
//        if(!x){
//            putchar('0');
//            return;
//        }
//        int num[22],siz=0,px=x;
//        while(px){
//            siz++;
//            num[siz]=px%10;
//            px/=10;
//        }
//        while(siz){
//            putchar(num[siz]+'0');
//            siz--;
//        }
//    }   //快速输出
      __int128 read() {
	char arr[30];
	__int128 res = 0;
	scanf("%s", arr);
	for (int i = 1; i <= strlen(arr); i++) {
		res *= 10;
		res += arr[i]-'0';
	}
	return res;
}
void print (__int128 num) {
	if (num > 9) { print(num / 10); }
	putchar(num % 10 + '0');
}
      
      
      
    long long max(long long a,long long b)
    {
       return a>b?a:b;
    }
      
    long long min(long long a,long long b)
    {
       return a<b?a:b;
    }
     
      
    const int N=1e5+6;
    const int N2=1004; 
    int mod=1000000007;
    //int Mod=1e15+7;
    const int INF=2e17;
  	const double eps=1e-10;
 	const double PI=3.1415926535;
//priority_queue<int , vector<int >, greater<int >> q;
//priority_queue<int > q;
//map<string ,int>mp,mmp;
 //typedef pair<int ,int > PII;
//stack < PII > p;
 
//queue<int > q;
//char s1[2020],s2[2020];
//vector<vector<int>> c(n+13,vector<int>(m+3));
//map<int,int>mp;
 
//priority_queue<pair<int, int>, vector<pair<int, int> >, greater<pair<int, int> > >q[1001][1001],p;
 //a.erase(unique(a.begin(), a.end()), a.end());
//char p,q;
//char s[N];
//deque<int > q;
//queue<int> q;
//using ull = unsigned long long;
//ull mod=212370440130137957ll;

int ma,mi;
int  n,m;

//int f[N][N],a[N][N],b[N][N],c[N][N],dp[N][N],q[N],v[N][N];

//
//struct node
//{
//	
//	double x,y,z;
//	
//}p[N];
//
//inline bool cmp(node w,node v)
//{
//	if(w.x==v.x)
//		return w.y<v.y;
//		
//	return w.x<v.x;	
//}

//
//int fx[5]={-1,0,0,1};
//int fy[5]={0,-1,1,0};


//int q[N],q2[N];


//知道3边,判断是否可以组成三角形 
bool check(int x,int y,int z) 
{
	if(x+y>z&&x+z>y&&y+z>x) return 1;
	return 0;
}
//知道3边,求三角形面积 
double df(double x,double y,double z)
{
	double p=(x+y+z)/2;
	return sqrt(p*(p-x)*(p-y)*(p-z));
}

char ss[N];

signed main()
{
	std::ios::sync_with_stdio(false);//取消cin与stdin同步,加速读入 
	cin.tie(0);cout.tie(0);
 	int t;
 	t=1;
 	//string s;
	cin>>t;

	while(t--)
	{
		int tt=0,fa=0,ans=0;
		//int   res=0,ans=0.0;
		//ma=0,mi=2e17;
		//map<int,int> mp,mp2;
		cin>>n>>m;
		vector<int> a(n+2),la(n+2),fi(n+2),ne(n+2),x(m+2),y(m+2),now(n+2);
		set<pair<int,int > > se;
		for(int i=1;i<=n;i++)
		{
			cin>>a[i];
			now[i]=a[i];
		}
		
		for(int i=1;i<=m;i++)
		{
			cin>>x[i]>>y[i];
			if(!fi[y[i]])
			{
				fi[y[i]]=i;
			}	
			if(la[y[i]])
			{
				ne[la[y[i]]]=i;
			}			
			la[y[i]]=i;
		}	
		
		for(int i=1;i<=m;i++)
		{
			if(!ne[i])
			{
				ne[i]=m+1;
			}
		}
		
		for(int i=1;i<=n;i++)
		{
			if(fi[i])
			{
				se.insert({fi[i],i});
			}
			else
			{
				se.insert({m+1,i});
			}
		}
		int dis=0,res=0;
		for(int i=1;i<=m;i++)
		{
			res=x[i]-x[i-1];
			while(se.size()&&res>=now[se.begin()->second])
			{
				res-=now[se.begin()->second];
				
				ans+=now[se.begin()->second];
				now[se.begin()->second]=0;
				se.erase(se.begin());
			}
			if(res&&se.empty())
			{
				
				break;
			}
			
			now[se.begin()->second]-=res;
			
			if(se.find({i,y[i]})!=se.end())
				se.erase({i,y[i]});
			se.insert({ne[i],y[i]});
			
			now[y[i]]=a[y[i]];
	
			ans+=res;
			
		//	cout<<ans<<"\n";
		}
		while(se.size())
		{
			ans+=now[se.begin()->second];
			se.erase(se.begin());
		}
		cout<<ans;
		cout<<"\n";
	}
	
    return 0;
}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 3604kb

input:

2
3 1
3 3 3
8 1
2 2
5 2
1 2
2 1

output:

12
9

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 0ms
memory: 3532kb

input:

6
3 2
2 2 2
6 1
7 1
2 2
3 3
2 1
6 2
2 3
2 2
5 1
7 2
9 1
2 2
3 3
2 1
6 2
1 1
999999999
1000000000 1
1 1
1000000000
1000000000 1

output:

9
11
4
11
999999999
2000000000

result:

ok 6 lines

Test #3:

score: -100
Runtime Error

input:

10
230 8042
599 1039 69 1011 1366 824 14117 1523 806 5002 332 55 3769 996 359 1040 255 1135 3454 3609 6358 2509 3695 8785 3890 1304 3394 14611 33 89 2245 508 22 1043 10411 628 1279 714 903 585 7413 5099 845 148 4689 2110 8683 1613 143 3263 2599 110 244 3297 4742 1571 425 1822 15692 572 9397 328 1691...

output:


result: