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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#719180#6435. Paimon Segment TreeFUCKUCUPWA 2ms21660kbC++204.6kb2024-11-06 23:07:132024-11-06 23:07:15

Judging History

你现在查看的是最新测评结果

  • [2024-11-06 23:07:15]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:21660kb
  • [2024-11-06 23:07:13]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int maxn = 50010, mod = 1e9 + 7;
int n, m, q, a[maxn], ans[maxn];
struct operation { int l, r, x; }op[maxn];
struct query { int l, r, t, sgn, id; }qry[maxn << 1];
struct matrix {
    matrix() { memset(x, 0, sizeof x); }
    int x[4][4];
}I;
inline bool operator != (matrix &a, matrix &b) {
  for(int i = 0; i < 4; ++i) for(int j = 0; j < 4; ++j) if(a.x[i][j] != b.x[i][j]) return true;
  return false;
}
inline matrix operator * (matrix &a, matrix &b) {
  matrix c;
  for(int i = 0; i < 4; ++i) for(int j = 0; j < 4; ++j) for(int k = 0; k < 4; ++k) {
    c.x[i][j] = (c.x[i][j] + 1ll * a.x[i][k] * b.x[k][j]) % mod;
  }
  return c;
}
struct node {
    int sum3, sum2, sum, len;
    matrix tag;
}t[maxn << 2];
inline void update(int d) {
  t[d].sum3 = (t[d << 1].sum3 + t[d << 1 | 1].sum3) % mod;
  t[d].sum2 = (t[d << 1].sum2 + t[d << 1 | 1].sum2) % mod;
  t[d].sum = (t[d << 1].sum + t[d << 1 | 1].sum) % mod;
}
inline void calc(int &a, int &b, int &c, int &d, matrix &mt) {
  int vec[4] = {a, b, c, d}, res[4] = {0, 0, 0, 0};
  for(int i = 0; i < 4; ++i) for(int j = 0; j < 4; ++j) res[i] = (res[i] + 1ll * vec[j] * mt.x[i][j]) % mod;
  a = res[0], b = res[1], c = res[2], d = res[3];
}
inline void pushdown(int d) {
  calc(t[d << 1].sum3, t[d << 1].sum2, t[d << 1].sum, t[d << 1].len, t[d].tag);
  calc(t[d << 1 | 1].sum3, t[d << 1 | 1].sum2, t[d << 1 | 1].sum, t[d << 1 | 1].len, t[d].tag);
  t[d << 1].tag = t[d << 1].tag * t[d].tag;
  t[d << 1 | 1].tag = t[d << 1 | 1].tag * t[d].tag;
  t[d].tag = I;
}
void build(int d, int l, int r) {
  t[d].tag = I, t[d].len = r - l + 1;
//  cout << l << ' ' << r << ' ' << t[d].len << '\n';
  if(l == r) {
    t[d].sum3 = 0;
    t[d].sum2 = 1ll * a[l] * a[l] % mod;
    t[d].sum = a[l];
    return;
  }
  int md = l + r >> 1;
  build(d << 1, l, md), build(d << 1 | 1, md + 1, r);
  update(d);
}
void modify(int d, int l, int r, int dl, int dr, int x) {
  if(dl > dr) return;
  if(dl <= l && r <= dr) {
    matrix tmp;
    tmp.x[0][0] = tmp.x[0][1] = 1, tmp.x[0][2] = 2ll * x % mod, tmp.x[0][3] = 1ll * x * x % mod;
    tmp.x[1][1] = 1, tmp.x[1][2] = 2ll * x % mod, tmp.x[1][3] = 1ll * x * x % mod;
    tmp.x[2][2] = 1, tmp.x[2][3] = x;
    tmp.x[3][3] = 1;
    t[d].tag = tmp * t[d].tag;
    calc(t[d].sum3, t[d].sum2, t[d].sum, t[d].len, tmp);
//    cout << l << ' ' << r << ' ' << t[d].sum3 << ' ' << t[d].sum2 << ' ' << t[d].sum << '\n';
    return;
  }
  if(t[d].tag != I) pushdown(d);
  int md = l + r >> 1;
  if(dl <= md) modify(d << 1, l, md, dl, dr, x);
  if(dr > md) modify(d << 1 | 1, md + 1, r, dl, dr, x);
  update(d);
}
int ask(int d, int l, int r, int dl, int dr) {
//  cout << d << ' ' << l << ' ' << r << ' ' << t[12].sum3 << '\n';
	if(l != r && t[d].tag != I) pushdown(d);
  if(dl <= l && r <= dr) return pushdown(d), t[d].sum3;
//  if(t[d].tag != I) pushdown(d);
  int md = l + r >> 1, ans = 0;
  if(dl <= md) ans = ask(d << 1, l, md, dl, dr);
  if(dr > md) ans = (ans + ask(d << 1 | 1, md + 1, r, dl, dr)) % mod;
  return ans;
}
inline void solve() {
  cin >> n >> m >> q;
  for(int i = 1; i <= n; ++i) cin >> a[i], a[i] = (a[i] + mod) % mod;
  op[0] = {1, n, 0};
  for(int i = 1; i <= m; ++i) cin >> op[i].l >> op[i].r >> op[i].x, op[i].x = (op[i].x + mod) % mod;
  for(int i = 1; i <= q; ++i) {
    int l, r, x, y;
    cin >> l >> r >> x >> y;
    qry[i] = {l, r, x - 1, -1, i}, qry[i + q] = {l, r, y, 1, i};
  }
  q <<= 1, sort(qry + 1, qry + 1 + q, [&](auto x, auto y) { return x.t < y.t; });
  build(1, 1, n);
//  for(int j = 1; j <= n; ++j) cout << ask(1, 1, n, j, j) << ' '; cout << '\n';
  int now = 0;
  while(now < q && qry[now + 1].t == -1) ++now;
  for(int i = 0; i <= m; ++i) {
    modify(1, 1, n, 1, op[i].l - 1, 0);
//    cout << t[12].sum3 << '\n';
    modify(1, 1, n, op[i].l, op[i].r, op[i].x);
//    cout << t[12].sum3 << '\n';
    modify(1, 1, n, op[i].r + 1, n, 0);
//    cout << i << ' ' << op[i].r << ' ' << t[12].sum3 << '\n';
//    for(int j = 1; j <= n; ++j) cout << ask(1, 1, n, j, j) << ' '; cout << '\n';
    while(now < q && qry[now + 1].t <= i) {
      ++now;
      if(qry[now].sgn == 1) ans[qry[now].id] = (ans[qry[now].id] + ask(1, 1, n, qry[now].l, qry[now].r)) % mod;
      else ans[qry[now].id] = (ans[qry[now].id] - ask(1, 1, n, qry[now].l, qry[now].r) + mod) % mod;
    }
  }
  for(int i = 1; i <= q / 2; ++i) cout << ans[i] << '\n';
}
signed main() {
//	freopen("e.in", "r", stdin);
//	freopen("e1.out", "w", stdout);
  ios::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
  for(int i = 0; i < 4; ++i) I.x[i][i] = 1;
  solve();
  return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 2ms
memory: 21660kb

input:

3 1 1
8 1 6
2 3 2
2 2 0 0

output:

1

result:

ok 1 number(s): "1"

Test #2:

score: 0
Accepted
time: 0ms
memory: 20888kb

input:

4 3 3
2 3 2 2
1 1 6
1 3 3
1 3 6
2 2 2 3
1 4 1 3
4 4 2 3

output:

180
825
8

result:

ok 3 number(s): "180 825 8"

Test #3:

score: -100
Wrong Answer
time: 2ms
memory: 20492kb

input:

100 107 180
-280960553 266308104 -997644864 856103777 592874377 674379235 -946339772 641750362 642418716 -360811715 -555543246 206614021 358239245 349842656 983198973 807518446 -66612455 -980932737 109826132 -109676067 51226145 452115561 -42729559 -950621304 -87009773 714026474 375317493 693260053 -...

output:

53866943
279478
881641276
841999497
56195989
90706154
270683312
450935095
835603222
800743867
864720046
480690173
811171254
562745155
152266362
473901758
263118069
124037336
615492791
40336593
983965002
848340298
539877921
440406648
553728064
642626534
467720280
498489170
369560740
727001497
7806747...

result:

wrong answer 1st numbers differ - expected: '400489222', found: '53866943'