QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#719157 | #9528. New Energy Vehicle | 20225954# | WA | 153ms | 20036kb | C++20 | 3.4kb | 2024-11-06 22:55:10 | 2024-11-06 22:55:10 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define db(x) cerr<<#x<<(x)<<"\n"
#define db1(x) cerr<<#x<<(x)<<" "
#define rep(i,a,b) for(auto i=(a);i<=(b);i++)
#define ll long long
const int N = 1e5+10;
int n,m;
ll x[N],id[N],a[N],na[N],pos[N],net[N],pre[N];
ll ans;
int num[N];
vector<int> kpos[N];
const ll inf = 1e18;
int tot;
struct st{
ll idx,pos;
bool operator<(const st& T)const {
return pos>T.pos;
}
};
void solve(){
cin>>n>>m;
for(int i=1;i<=n;i++){
cin>>a[i];na[i] = a[i];
}
x[0]=0;
for(int i=1;i<=m;i++){
cin>>x[i]>>id[i];
if(pos[id[i]]==0)pos[id[i]] = x[i];
int k = id[i];
net[pre[k]] = i;
pre[k] = i;
kpos[k].push_back(i);
}
x[m+1] = x[m]+1;
for(int i=1;i<=m;i++){
if(net[i]== 0)net[i] =m+1; //走向最后一个
}
priority_queue<st>q;
map<int,int> mp;
for(int i=1;i<=n;i++){
if(pos[i]){
//第一个的位置
q.push({i,pos[i]});
++num[i];
}else {
++tot;
q.push({i,x[m+1]});
}
mp[i] =1;
}
auto q1 =q;
auto pr = [&](){
for(int i=1;i<=n;i++)cout<<na[i]<< " ";cout<<"\n";
};
// while(q1.size()){
// //cout<<q1.top().w<<" "<<q1.top().idx<<" \n";q1.pop();
// }
for(int i=1;i<=m;i++){
ll dis = x[i]-x[i-1];
ll tmp =0,f =0;
while(q.size()){
auto [idx,pos] = q.top();q.pop();
// cout<<"i --"<<i<<"使用idx = "<<idx<<"\n";
mp[idx] =0;//该电池已经用完了
if(tmp+na[idx]<=dis){
//tmp代表当前走的距离+优先使用的电池<=dis,那么都将电池用完,丢弃,
//只有再次充电时才能用,直接丢弃,以后再加进来
tmp+=na[idx];
}else if(tmp+na[idx]>dis){
//电池暂时不能丢弃,那么该电池为临时电池,na[]值依旧要改变
//若为后续充电电池后,na[i]会增加就好
ll res = dis-tmp;
tmp=dis;//走到地方了
na[idx]-=res;
if(num[idx]<kpos[idx].size())q.push({idx,x[kpos[idx][num[idx]]]}),num[idx]++;
else q.push({idx,x[m+1]});
// num++;
mp[idx] =1;
}
// pr();
if(tmp==dis){
f =1; //跳出
break;
}
}
if(f==0){
//走不到当前点
ans = x[i-1]+tmp;
cout<<ans<<"\n"; return;
}
// pr();
int k = id[i];
na[k] = max(na[k],a[k]);
// na[id[i]] = max(a[id[i]],na[id[i]]);
// cout<<"更新后q.size()"<<q.size()<<"\n"; pr();
// cout<<"i = "<<" "<<id[i]<<"\n";
if(!mp[id[i]]){
ll netpos = x[net[k]];
q.push({k,netpos});
//cout<<"加入 "<<k<<"\n";
}
}
ans = x[m];
while(q.size()){
auto [idx,pos] = q.top();q.pop();
// cout<<"idx<<"<<idx<<"\n";
ans+= na[idx];
// db(ans);
}
cout<<ans<<"\n";
for(int i=1;i<=n;i++)pos[i] =net[i] =0,kpos[i].clear();
ans =0;
return ;
}
int main()
{
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int _ ;cin>>_;while(_--)solve();
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 1ms
memory: 7924kb
input:
2 3 1 3 3 3 8 1 2 2 5 2 1 2 2 1
output:
12 9
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 7972kb
input:
6 3 2 2 2 2 6 1 7 1 2 2 3 3 2 1 6 2 2 3 2 2 5 1 7 2 9 1 2 2 3 3 2 1 6 2 1 1 999999999 1000000000 1 1 1 1000000000 1000000000 1
output:
9 11 4 11 999999999 2000000000
result:
ok 6 lines
Test #3:
score: -100
Wrong Answer
time: 153ms
memory: 20036kb
input:
10 230 8042 599 1039 69 1011 1366 824 14117 1523 806 5002 332 55 3769 996 359 1040 255 1135 3454 3609 6358 2509 3695 8785 3890 1304 3394 14611 33 89 2245 508 22 1043 10411 628 1279 714 903 585 7413 5099 845 148 4689 2110 8683 1613 143 3263 2599 110 244 3297 4742 1571 425 1822 15692 572 9397 328 1691...
output:
1527543 1568299 1322255 1520690 1516731 1557796 863518 1540142 1003604 910857
result:
wrong answer 1st lines differ - expected: '1543020', found: '1527543'