QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#714039 | #8056. Travel 2 | frankly6 | TL | 1ms | 3720kb | C++17 | 1.1kb | 2024-11-05 21:21:40 | 2024-11-05 21:21:41 |
Judging History
answer
#include<iostream>
#include<vector>
#include<cstring>
#include<unordered_map>
using namespace std;
const int MX=2550;
int T;
int start, num, now;
void ask(int e)
{
cout << "> " << e << '\n';
cout.flush();
cin >> now >> num;
}
int main()
{
ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);
cin >> T;
while(T--)
{
vector<unordered_map<int,int>> G(MX);
vector<int> fa(MX), id(MX);
cin >> start >> num; now=start;
while(now!=start||id[now]!=num)
{
if(id[now]==num) {ask(G[now][fa[now]]); continue;} //finish subtree & return to father
int pre=now;
ask(++id[now]); //try to expand
G[pre][now]=id[pre]; //pre's try num
if(now==fa[pre]) ask(G[now][pre]); //KEY edge, return to son
else if(!fa[now]) fa[now]=pre; //upd KEY edge
}
cout << "! ";
for(int u=1;u<MX;u++)
for(auto [v,id]:G[u])
if(u<v) cout << u << " " << v << " ";
cout << '\n'; cout.flush();
string s; cin >> s;
}
return (0-0);
}
Details
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Test #1:
score: 100
Accepted
time: 1ms
memory: 3720kb
input:
2 1 1 2 1 1 1 2 1 1 1 Correct 1 3 2 2 1 3 2 2 4 2 1 3 3 1 1 3 3 1 1 3 4 2 1 3 Correct
output:
> 1 > 1 > 1 > 1 ! 1 2 > 1 > 1 > 1 > 2 > 1 > 2 > 1 > 2 > 1 > 3 > 1 ! 1 4 1 3 1 2 2 4
result:
ok correct! (2 test cases)
Test #2:
score: -100
Time Limit Exceeded
input:
1000 1 9 2 7 1 9 2 7 3 9 1 9 3 9 1 9 4 9 1 9 4 9 3 9 4 9 7 7 1 9 5 8 1 9 5 8 8 8 1 9 6 9 1 9 6 9 2 7 10 6 1 9 7 7 4 9 7 7 8 8 5 8 8 8 10 6 2 7 10 6 8 8 9 8 1 9 8 8 7 7 5 8 9 8 3 9 9 8 5 8 2 7 6 9 10 6 4 9 10 6 6 9 5 8 3 9 2 7 3 9 5 8 6 9 8 8 3 9 10 6 3 9 8 8 6 9 3 9 7 7 3 9 6 9 9 8 2 7 5 8 7 7 9 8 8...
output:
> 1 > 1 > 1 > 2 > 1 > 2 > 1 > 3 > 1 > 3 > 2 > 2 > 3 > 1 > 4 > 1 > 4 > 2 > 1 > 5 > 1 > 5 > 2 > 3 > 1 > 6 > 2 > 3 > 3 > 2 > 2 > 3 > 2 > 3 > 3 > 4 > 1 > 7 > 5 > 4 > 3 > 2 > 3 > 3 > 4 > 4 > 3 > 4 > 4 > 5 > 4 > 5 > 4 > 2 > 5 > 6 > 5 > 6 > 6 > 6 > 7 > 7 > 6 > 8 > 5 > 9 > 7 > 4 > 5 > 7 > 6 > 5 > 4 > 6 > 7 ...