#include<bits/stdc++.h>
#define ll long long
#define rep(i,l,r) for(int i(l),i##end(r);i<=i##end;++i)
#define per(i,r,l) for(int i(r),i##end(l);i>=i##end;--i)
using namespace std;
const int N=2e5+10,M=1e7;
const ll P0=1e17,mod1=1e9+7,mod2=1e9+9;
struct big{
    ll d,a,h1,h2;//v=a*10^d
    friend big operator+(big x,big y){
        //保证有 x<y<2x
        big z={y.d,((x.d==y.d)?x.a:x.a/10)+y.a,(x.h1+y.h1)%mod1,(x.h2+y.h2)%mod2};
        if(z.a>=P0) z.a/=10,z.d++;
        return z;
    }
    void ins(int x){//加一位 x
        a=a*10+x,h1=(h1*10+x)%mod1,h2=(h2*10+x)%mod2;
        if(a>=P0) a/=10,d++;
    }
}f[M],a[N];
int n; ll ans; char s[M]; unordered_map<ll,int> mp;
signed main(){
    // freopen("1.in","r",stdin);
    f[0]=f[1]={0,1,1,1};//f[0]=f[1]=1=1*10^0
    rep(i,2,M-1){
        f[i]=f[i-2]+f[i-1];
        // if(i%100000==0) cerr<<i<<'\n';
    } 
    scanf("%d",&n);
    rep(i,1,n){
        scanf("%s",s+1);
        int len=strlen(s+1);
        rep(k,1,len) a[i].ins(s[k]-'0');
    }
    sort(a+1,a+n+1,[](big i,big j){
        return i.d!=j.d?i.d<j.d:i.a<j.a;
    });
    int k=2;//f[0]=f[1]<2<=ai+aj
    auto cnt=[](big x,big y){
        return mp[(x.h1<y.h1?x.h1-y.h1+mod1:x.h1-y.h1)*mod2+(x.h2<y.h2?x.h2-y.h2+mod2:x.h2-y.h2)];
    };
    rep(i,1,n){
        while(f[k].d<a[i].d) k++;
        // cerr<<i<<' '<<k<<'\n';
        rep(j,max(0,k-10),min(M-1,k+20)){
            ans+=cnt(f[j],a[i]);
        }mp[a[i].h1*mod2+a[i].h2]++;
    }
    cout<<ans;
    return 0;
}//g++ -g my.cpp -o my -std=c++14 -O2  -Wall -Wextra -Wshadow -Wconversion