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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#70716#5069. Vacationnocriz#WA 985ms75008kbC++175.1kb2023-01-07 16:56:582023-01-07 16:57:00

Judging History

你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2023-01-07 16:57:00]
  • 评测
  • 测评结果:WA
  • 用时:985ms
  • 内存:75008kb
  • [2023-01-07 16:56:58]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
using namespace std;
typedef long long ll;
ll mx[800005],tg[800005],lp[800005],lsum[800005],rp[800005],rsum[800005],mx2[800005];
ll mxs[800005],tg2[800005],mxx[800005],num[800005];
ll ans=0;
int n,m,c,gl,gr;
ll a[200005],sum[200005];
ll ty,x,y,v;
ll tr[200005];
const ll inf=1e18;
vector<int>q;
int lowbit(int p){return p&-p;}
void update(int p,int val)//单点更新
{
    while(p<=n){
        tr[p]+=val;
        p+=lowbit(p);//由叶子节点向上更新树状数组C,从左往右更新
    }
}
ll asksum(int p)//求区间[1,i]内所有元素的和
{
    ll ret=0;
    while(p>0){
        ret+=tr[p];//从右往左累加求和
        p-=lowbit(p);
    }
    return ret;
}
void build(int p,int l,int r)
{
	num[p]=r-l+1;
	if(l==r)
	{
		mx[p]=sum[min(n,l+c-1)]-sum[l-1];
		mxs[p]=sum[l];tg2[p]=0;
		mxx[p]=sum[l];
		tg[p]=0;
		if(a[l]>=0)lp[p]=rp[p]=1,lsum[p]=rsum[p]=a[l];
		else lp[p]=rp[p]=lsum[p]=rsum[p]=0;
		mx2[p]=lsum[p];
		return;
	}
	int mid=(l+r)/2;
	build(2*p,l,mid);
	build(2*p+1,mid+1,r);
	mx[p]=max(mx[2*p],mx[2*p+1]);
	tg[p]=0;
	mxs[p]=min(mxs[2*p],mxs[2*p+1]);
	mxx[p]=max(mxx[2*p],mxx[2*p+1]);
	tg2[p]=0;
	if(lp[2*p]==mid-l+1)
	{
		lp[p]=lp[2*p]+lp[2*p+1];
		lsum[p]=lsum[2*p]+lsum[2*p+1];
	}
	else
	{
		lp[p]=lp[2*p];
		lsum[p]=lsum[2*p];
	}
	if(rp[2*p+1]==r-mid)
	{
		rp[p]=rp[2*p+1]+rp[2*p];
		rsum[p]=rsum[2*p+1]+rsum[2*p];
	}
	else
	{
		rp[p]=rp[2*p+1];
		rsum[p]=rsum[2*p+1];
	}
	mx2[p]=max(mx2[2*p],mx2[2*p+1]);
	if(rp[2*p]+lp[2*p+1]<=c)mx2[p]=max(mx2[p],rsum[2*p]+lsum[2*p+1]);
}
void activate(int p,int v)
{
	mx[p]+=v;
	tg[p]+=v;
}
void push(int p)
{
	if(tg[p]==0)return;
	activate(2*p,tg[p]);
	activate(2*p+1,tg[p]);
	tg[p]=0;
}
void activate2(int p,int v)
{
	mxs[p]+=v;
	mxx[p]+=v;
	tg2[p]+=v;
}
void push2(int p)
{
	if(tg2[p]==0)return;
	activate2(2*p,tg2[p]);
	activate2(2*p+1,tg2[p]);
	tg2[p]=0;
}
void modify1(int p,int l,int r)
{
	if(gl>r||gr<l)return;
	if(gl<=l&&gr>=r)
	{
		activate(p,v);
		return;
	}
	push(p);
	int mid=(l+r)/2;
	modify1(2*p,l,mid);
	modify1(2*p+1,mid+1,r);
	mx[p]=max(mx[2*p],mx[2*p+1]);
	
}
void modify3(int p,int l,int r)
{
	if(gl>r||gr<l)return;
		if(gl<=l&&gr>=r)
		{
			activate2(p,v);
			return;
		}
		push2(p);
		int mid=(l+r)/2;
		modify3(2*p,l,mid);
		modify3(2*p+1,mid+1,r);
		mxs[p]=min(mxs[2*p],mxs[2*p+1]);
		mxx[p]=max(mxx[2*p],mxx[2*p+1]);
}
void modify2(int p,int l,int r)
{
	if(l==r)
	{
		if(a[l]>=0)lp[p]=rp[p]=1,lsum[p]=rsum[p]=a[l];
		else lp[p]=rp[p]=lsum[p]=rsum[p]=0;
		mx2[p]=lsum[p];
		return;
	}
	int mid=(l+r)/2;
	if(x<=mid)modify2(2*p,l,mid);
	else modify2(2*p+1,mid+1,r);
		if(lp[2*p]==mid-l+1)
		{
			lp[p]=lp[2*p]+lp[2*p+1];
			lsum[p]=lsum[2*p]+lsum[2*p+1];
		}
		else
		{
			lp[p]=lp[2*p];
			lsum[p]=lsum[2*p];
		}
		if(rp[2*p+1]==r-mid)
		{
			rp[p]=rp[2*p+1]+rp[2*p];
			rsum[p]=rsum[2*p+1]+rsum[2*p];
		}
		else
		{
			rp[p]=rp[2*p+1];
			rsum[p]=rsum[2*p+1];
		}
		mx2[p]=max(mx2[2*p],mx2[2*p+1]);
		if(rp[2*p]+lp[2*p+1]<=c)mx2[p]=max(mx2[p],rsum[2*p]+lsum[2*p+1]);
}
ll ask1(int p,int l,int r)
{
	if(gl>r||gr<l)return -inf;
	if(gl<=l&&gr>=r)return mx[p];
	int mid=(l+r)/2;
	push(p);
	return max(ask1(2*p,l,mid),ask1(2*p+1,mid+1,r));
}
ll ask2(int p,int l,int r)
{
	if(gl>r||gr<l)return inf;
	if(gl<=l&&gr>=r)return mxs[p];
	int mid=(l+r)/2;
	push2(p);
	return min(ask2(2*p,l,mid),ask2(2*p+1,mid+1,r));
}
ll ask3(int p,int l,int r)
{
	if(gl>r||gr<l)return -inf;
	if(gl<=l&&gr>=r)return mxx[p];
	int mid=(l+r)/2;
	push2(p);
	return max(ask3(2*p,l,mid),ask3(2*p+1,mid+1,r));
}
void ask4(int p,int l,int r)
{
	if(gl>r||gr<l)return;
	if(gl<=l&&gr>=r)
	{
		ans=max(ans,mx2[p]);
		q.push_back(p);
		return;
	}
	int mid=(l+r)/2;
	ask4(2*p,l,mid);
	ask4(2*p+1,mid+1,r);
}
signed main()
{
	//freopen("233.txt","r",stdin);
	//freopen("outm.txt","w",stdout);
	scanf("%d%d%d",&n,&m,&c);
	for(int i=1;i<=n;i++)scanf("%lld",&a[i]),update(i,a[i]);
	for(int i=1;i<=n;i++)sum[i]=sum[i-1]+a[i];
	build(1,1,n);
	for(int i=1;i<=m;i++)
	{
		scanf("%lld%lld%lld",&ty,&x,&y);
		//printf("%lld %lld %lld\n",ty,x,y);
		if(ty==1)
		{
			gl=max(1ll,x-c+1);
			gr=x;
			v=y-a[x];
			ll tmp=v;
			update(x,v);
			a[x]=y;
			modify1(1,1,n);
			gl=x;gr=n;
			v=tmp;
			modify3(1,1,n);
			modify2(1,1,n);
		}
		else
		{
			ans=0;
			gl=x;gr=y-c+1;
			if(gl<=gr)ans=max(ans,ask1(1,1,n));
			ll sumr=asksum(y);
			ll suml=asksum(x-1);
			gl=max(y-c+1,x-1);gr=y-1;
			if(gl<=gr)
			{
				if(gl>0)ans=max(ans,sumr-ask2(1,1,n));
				else ans=max(ans,sumr-min(0ll,ask2(1,1,n)));
			}
			gl=x;gr=min(x+c-1,y);
			if(gl<=gr)ans=max(ans,ask3(1,1,n)-suml);
			q.clear();
			gl=x;gr=y;
			ask4(1,1,n);
			ll rpp,rs;
			rpp=rp[q[0]];
			rs=rsum[q[0]];
			for(int j=1;j<q.size();j++)
			{
				int id=q[j];
				if(lp[id]+rpp<=c)ans=max(ans,rs+lsum[id]);
				if(rp[id]==num[id])
				{
					rpp=rp[id]+rpp;
					rs=rs+rsum[id];
				}
				else
				{
					rpp=rp[id];
					rs=rsum[id];
				}
			}
			printf("%lld\n",ans);
		}
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 28400kb

input:

5 6 3
0 -5 -3 8 -3
2 3 5
1 2 5
2 1 5
1 4 -3
2 3 5
2 1 5

output:

8
10
0
5

result:

ok 4 number(s): "8 10 0 5"

Test #2:

score: 0
Accepted
time: 883ms
memory: 74720kb

input:

200000 500000 1
387060158 961744470 37167782 737122872 -532977662 1604246 -30977399 871848791 444997246 454204578 -813187501 -660394286 448014171 -835115276 -631880452 887715308 258530352 805589560 -414653327 -156732249 -335096199 -80266237 367896009 738406627 -903652056 446120866 415658444 -1347916...

output:

999902477
999981999
999343404
999847372
999957587
998160312
999981999
999981999
999981999
999980061
999981999
999981999
999981999
999876122
999981999
999996602
999981999
999981999
999981999
999723649
999981999
999957587
999896087
999981999
999981999
999981999
999981999
999981999
999957587
999981999
...

result:

ok 250051 numbers

Test #3:

score: -100
Wrong Answer
time: 985ms
memory: 75008kb

input:

200000 500000 5
802774074 383481934 -295470374 285359286 751657057 197444479 626916547 -828168464 288373833 -493446966 -208422769 956745384 919286225 959643271 -176531848 -380256966 357111771 -50890039 -637284768 -337010918 259019684 752475630 -259898780 98620995 -704832505 -532710796 -971600790 -84...

output:

4544135313
4544135313
4443416295
3390067591
4544135313
4544135313
4322308420
4386413596
4386413596
4165697630
4322308420
4287938127
4443416295
4544135313
4386413596
4165697630
4386413596
4386413596
4386413596
4323325838
4443416295
4386413596
4385851999
4544135313
4443416295
4443416295
4323325838
432...

result:

wrong answer 22716th numbers differ - expected: '2256871648', found: '1678581860'