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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#706471#8339. Rooted TreeAnneliese#TL 141ms16740kbC++141009b2024-11-03 11:34:142024-11-03 11:34:14

Judging History

This is the latest submission verdict.

  • [2024-11-03 11:34:14]
  • Judged
  • Verdict: TL
  • Time: 141ms
  • Memory: 16740kb
  • [2024-11-03 11:34:14]
  • Submitted

answer

#include<bits/stdc++.h>

using namespace std;
using LL = long long;
using ll = long long;
const int N = 10000005;
#define rep(i,a ,b )  for(int i = a ;i<=b;i++)
#define pre(i,a ,b )  for(int i = a ;i>=b;i--)
#define pb push_back
#define sc(x) scanf("%d",&x)
ll dp[N];
ll f[N];
ll dp2[N];
const int mod=1e9+9;
ll ksm(ll a,ll b){ll res=1;
while(b){
	if(b%2==1)res=res*a%mod;a=a*a%mod;b/=2;
}
return res;
}
void solve() {
	int m,k;
	sc(m);sc(k);
	f[0]=1;
	rep(i,1,k)f[i]=(f[i-1]+m-1)%mod;
	ll res=0;
	rep(i,1,k){
		dp[i]=dp[i-1]+(dp[i-1]*(m-1)%mod+f[i-1]*m%mod)*ksm(f[i-1],mod-2)%mod;//dp[i]为叶子节点深度之和 
		dp[i]%=mod;
		res=(res+(dp[i-1]*m%mod+f[i-1]*m%mod)*ksm(f[i-1],mod-2)%mod)%mod;
	//	cout<<dp[i-1]*m%mod+f[i-1]*m%mod*ksm(f[i-1],mod-2)%mod<<" "<<endl;
	}
	cout<<res<<endl; 
}


int main() {

    ios::sync_with_stdio(false);
    cin.tie(nullptr);

    int t = 1;
    //cin >> t ;

    while (t--) {
        solve();
    }

    return 0;


}

Details

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Test #1:

score: 100
Accepted
time: 0ms
memory: 5868kb

input:

6 2

output:

18

result:

ok 1 number(s): "18"

Test #2:

score: 0
Accepted
time: 1ms
memory: 5860kb

input:

2 6

output:

600000038

result:

ok 1 number(s): "600000038"

Test #3:

score: 0
Accepted
time: 141ms
memory: 16740kb

input:

83 613210

output:

424200026

result:

ok 1 number(s): "424200026"

Test #4:

score: -100
Time Limit Exceeded

input:

48 6713156

output:

198541581

result: