QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#699496 | #6766. Direction Setting | jkliao# | AC ✓ | 2ms | 3920kb | C++17 | 2.7kb | 2024-11-02 09:23:12 | 2024-11-02 09:23:13 |
Judging History
answer
#include <climits>
#include <iostream>
#include <vector>
using namespace std;
#define rep(i, a, b) for (int i = a; i < (b); ++i)
#define all(x) begin(x), end(x)
#define sz(x) (int)(x).size()
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
struct Dinic {
struct Edge {
int to, rev;
ll c, oc;
ll flow() { return max(oc - c, 0LL); } // if you need flows
};
vi lvl, ptr, q;
vector<vector<Edge>> adj;
Dinic(int n) : lvl(n), ptr(n), q(n), adj(n) {}
void addEdge(int a, int b, ll c, ll rcap = 0) {
adj[a].push_back({b, sz(adj[b]), c, c});
adj[b].push_back({a, sz(adj[a]) - 1, rcap, rcap});
}
ll dfs(int v, int t, ll f) {
if (v == t || !f)
return f;
for (int &i = ptr[v]; i < sz(adj[v]); i++) {
Edge &e = adj[v][i];
if (lvl[e.to] == lvl[v] + 1)
if (ll p = dfs(e.to, t, min(f, e.c))) {
e.c -= p, adj[e.to][e.rev].c += p;
return p;
}
}
return 0;
}
ll calc(int s, int t) {
ll flow = 0;
q[0] = s;
rep(L, 0, 31) do { // 'int L=30' maybe faster for random data
lvl = ptr = vi(sz(q));
int qi = 0, qe = lvl[s] = 1;
while (qi < qe && !lvl[t]) {
int v = q[qi++];
for (Edge e : adj[v])
if (!lvl[e.to] && e.c >> (30 - L))
q[qe++] = e.to, lvl[e.to] = lvl[v] + 1;
}
while (ll p = dfs(s, t, LLONG_MAX))
flow += p;
}
while (lvl[t])
;
return flow;
}
bool leftOfMinCut(int a) { return lvl[a] != 0; }
};
void solve() {
int n, m;
cin >> n >> m;
vector<ll> limits(n + 1);
ll su = 0;
for (int i = 1; i <= n; i++) {
cin >> limits[i];
su += limits[i];
}
Dinic d(n + m + 2);
for (int i = 1; i <= n; i++) {
d.addEdge(i, n + m + 1, limits[i]);
}
vector<pair<int, int>> edgelookup(m + 1);
for (int i = 1; i <= m; i++) {
d.addEdge(0, n + i, 1);
int u, v;
cin >> u >> v;
edgelookup[i].first = d.adj[n + i].size();
d.addEdge(n + i, u, 1);
edgelookup[i].second = d.adj[n + i].size();
d.addEdge(n + i, v, 1);
}
d.calc(0, n + m + 1);
ll ans = 0;
vector<int> sans(m);
for (int i = 1; i <= m; i++) {
Dinic::Edge utv = d.adj[n + i][edgelookup[i].second];
Dinic::Edge vtu = d.adj[n + i][edgelookup[i].first];
if (utv.flow() == 1) {
sans[i - 1] = 0;
} else if (vtu.flow() == 1) {
sans[i - 1] = 1;
} else {
sans[i - 1] = 1;
ans++;
}
}
cout << ans << endl;
for (int x : sans) {
cout << x;
}
cout << endl;
}
int main() {
cin.tie(0)->sync_with_stdio(0);
cin.exceptions(cin.failbit);
int t;
cin >> t;
while (t--)
solve();
}
这程序好像有点Bug,我给组数据试试?
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3876kb
input:
2 4 5 0 1 1 5 1 2 1 3 2 3 3 2 4 4 3 2 0 0 2 1 3 3 2
output:
2 00111 0 01
result:
ok 2 cases
Test #2:
score: 0
Accepted
time: 1ms
memory: 3920kb
input:
120 21 14 0 1 2 2 3 2 0 1 0 3 3 2 1 1 2 0 1 3 1 0 0 6 12 14 11 10 18 15 12 6 11 15 8 3 4 10 11 3 18 5 13 5 19 5 10 17 18 4 2 20 21 9 3 0 4 7 9 5 2 0 4 0 1 6 1 5 8 3 2 7 0 16 6 12 6 11 4 6 6 19 10 17 19 20 20 1 17 15 10 3 2 5 16 7 8 6 1 6 4 18 16 1 8 4 1 20 6 6 9 4 15 7 5 6 16 12 8 0 9 5 8 4 5 6 3 2 ...
output:
0 11111111111111 1 110111111011111110111 0 1111101111111011 2 111100111010111111111101 2 11111011111 2 000111111011111111010111 3 1101111111110111111011 0 11 0 1111111111111111111 0 0111011111111111 2 0111111001001 3 101101001 0 1111111 0 111111111111111 0 1111111111111111111 2 11110111110001111101 ...
result:
ok 120 cases
Test #3:
score: 0
Accepted
time: 2ms
memory: 3692kb
input:
120 5 9 1 2 2 3 1 2 2 2 4 1 5 4 3 3 4 3 3 1 5 5 4 4 3 5 4 1 0 1 1 1 2 3 5 3 1 4 4 3 15 17 0 1 1 3 1 2 1 1 1 1 1 2 0 1 1 14 6 13 12 11 4 9 8 9 4 10 5 10 2 4 4 7 4 11 10 15 6 7 1 5 3 13 14 15 12 2 14 11 6 13 17 2 2 1 1 2 1 0 0 1 4 1 1 1 5 11 6 2 2 1 5 2 1 12 7 10 10 2 1 3 3 11 7 1 9 7 11 10 11 2 4 3 7...
output:
0 111111001 0 0111 0 00001011011100010 0 11110011101101001 0 1111111 5 1000111100111 4 1111011 2 101111111111011111111 0 11110 0 1111 0 11100 0 0101 5 11110100110101011 4 111111111 4 01111111 4 10101010111110110 0 110000001010100 0 000000111100001 0 0001001111010100000 4 10111000101 2 11101101101111...
result:
ok 120 cases
Test #4:
score: 0
Accepted
time: 1ms
memory: 3648kb
input:
120 12 11 7 0 0 1 0 0 1 1 0 0 1 0 12 1 1 9 1 2 1 8 3 1 6 1 10 1 1 7 5 1 11 1 4 1 11 10 1 0 0 0 1 0 7 0 0 0 1 7 11 6 7 7 5 8 7 10 7 9 7 7 4 7 1 7 2 3 7 24 23 1 1 1 1 0 5 1 1 1 1 0 1 1 1 1 0 1 0 1 1 1 1 0 1 20 6 12 6 6 9 1 6 6 15 14 6 6 2 6 18 23 6 10 6 3 6 6 16 6 7 17 6 6 13 19 6 6 22 5 6 4 6 6 11 6 ...
output:
0 01100000011 0 0000001010 0 11010101011101010011001 0 1010 0 0001101111101 0 1000110001101101011 0 10100101 0 00011011110 0 101001111011011001110110 0 1001111110010001 0 00100 0 0010101001 0 00101101011111101 0 100001110100100000 0 10011100001110011000 0 010010000101000111001 0 010 0 001100110 0 10...
result:
ok 120 cases
Test #5:
score: 0
Accepted
time: 2ms
memory: 3752kb
input:
10 300 300 0 0 0 1 6 3 0 36 0 0 0 0 8 53 23 2 8 7 8 4 1 0 3 5 0 4 0 0 2 5 5 5 7 0 0 4 3 0 0 21 2 7 6 2 0 0 0 4 0 67 3 4 9 3 1 1 0 6 2 2 0 0 0 0 0 41 5 0 0 15 2 5 0 6 5 4 0 7 4 4 6 8 0 7 2 6 0 4 4 0 8 22 1 2 6 3 0 3 6 0 0 3 0 0 6 3 0 63 3 7 7 4 0 0 0 26 0 0 1 3 6 1 1 0 0 22 0 2 0 0 1 7 4 1 0 1 0 4 0 ...
output:
31 011110111101011111110111111110110110111111011111111011011111111111101111101010111100110111111101100100101101111110101011011010111110001110110111111111101110111101111111111011100001101110011110111110110110001111111111101111110111101101111100111101011111101010110001011110100111110011111101001111111...
result:
ok 10 cases
Test #6:
score: 0
Accepted
time: 1ms
memory: 3652kb
input:
10 30 300 17 12 25 27 17 21 21 24 10 18 23 19 25 26 14 23 9 27 22 19 25 15 13 22 25 12 20 10 27 22 29 11 25 9 23 10 9 25 25 12 20 1 18 9 2 1 30 14 2 10 6 18 3 27 10 17 14 4 21 2 2 15 28 4 7 8 19 13 14 13 8 7 10 18 4 18 4 19 5 16 23 14 21 24 24 12 15 24 23 29 11 25 10 4 23 9 27 13 18 26 12 24 23 3 27...
output:
0 1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111110111111...
result:
ok 10 cases
Test #7:
score: 0
Accepted
time: 2ms
memory: 3776kb
input:
10 290 299 0 3 2 1 2 0 0 0 0 1 0 3 2 1 3 0 0 3 1 0 3 1 0 1 0 0 0 1 0 3 0 1 0 2 1 7 0 1 0 3 0 2 1 2 1 2 0 1 0 0 2 2 1 0 0 0 0 1 2 0 2 1 0 1 2 1 1 0 1 0 0 0 1 1 1 1 1 2 2 1 3 0 0 1 2 0 1 0 1 2 1 1 0 0 2 1 2 1 1 0 1 0 2 0 0 1 1 0 0 1 0 4 1 2 2 1 1 1 1 2 2 3 1 1 1 0 1 2 1 1 2 0 1 1 1 1 0 0 2 1 1 0 0 1 1...
output:
0 1111100000010110001101010001000010011010011010010100011001001000000010011100100011101100001001101110000111111110010001110000011000000111011001011110101010101110110100001110001000111100000010111010011001100101011100000110001100011001001101000001111100011000001010001001100100011101001000000111010101...
result:
ok 10 cases
Test #8:
score: 0
Accepted
time: 2ms
memory: 3716kb
input:
10 300 299 1 1 1 1 1 1 0 1 0 0 1 1 1 1 0 0 0 1 1 1 1 0 0 1 1 1 1 0 0 1 1 1 1 0 0 1 1 0 1 0 1 1 0 0 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 0 0 1 0 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 0 1 1 1 0 0 1 142 1 0 0 1 1 1 0 0 0 1 0 1 1 0 0 0 1 0 0 0 0 0 1 0 1 0 0 0 1 0 1 1 0 0 1 0 1 0 1 1 1 0 0 0 1 0 0 1 0 1 1 0 1 1 1 1 0...
output:
0 0111101010001110110101100110100101010010001000100000011000100101111101111101010111000110110010110011010000011011011101000000111011111001010111001011010110010000110010110000010111011100111100100011110110010010101111110011110011001001101011010100101001110111101100000101101111110010001110011010111011...
result:
ok 10 cases