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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#699460#9221. Missing BoundariesMaybe_TomorrowWA 26ms6076kbC++202.2kb2024-11-02 09:10:532024-11-02 09:11:00

Judging History

你现在查看的是最新测评结果

  • [2024-11-02 09:11:00]
  • 评测
  • 测评结果:WA
  • 用时:26ms
  • 内存:6076kb
  • [2024-11-02 09:10:53]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

const int MAXN = 2e5 + 2;
struct segment {
    int l, r;
    int idx;
    segment(int a, int b, int c) : l(a), r(b), idx(c) {}
    segment() : l(0), r(0), idx(0) {}  // Default constructor added
};

segment pointers[MAXN];  // Array of segment objects

bool cmp(segment x, segment y) {
    return x.l < y.l;
}

void returnable() {
    int n, finall; 
    cin >> n >> finall;
    
    int free = 0, badseg = 0;
    for (int i = 1; i <= n; i++) {
        int a, b; 
        cin >> a >> b;
        
        if (a == -1 || b == -1) {
            free++;
            continue;  // Skip this segment without decrementing `badseg`
        } 
        badseg++;
        if (a == -1) {
            pointers[badseg] = segment(b, b, 1);
        } else if (b == -1) {
            pointers[badseg] = segment(a, a, 2);
        } else {
            pointers[badseg] = segment(a, b, 3);
        }
    }

    if (badseg == 0) {
        if (finall < badseg) cout << "TAK\n";
        else cout << "NIE\n";
        return; 
    }

    sort(pointers + 1, pointers + badseg + 1, cmp);

    int curr = 0, cnt = 0, lft = finall;
    
    if (pointers[1].l != 1 && pointers[1].idx != 1) cnt++;

    for (int i = 1; i <= badseg; i++) {  // Start loop from i=2
        if (pointers[i].l == pointers[i-1].l || pointers[i].r == pointers[i-1].r) {
            cout << "NIE\n"; 
            return;
        }
        if (pointers[i].l <= curr) {
            cout << "NIE\n"; 
            return;
        }
        if (pointers[i].idx != 1) {
            if (pointers[i-1].idx == 3 || pointers[i-1].idx == 1) {
                if (pointers[i-1].r != pointers[i].l - 1) cnt++;
            }
        }
        lft -= pointers[i].r - pointers[i].l + 1;
        curr = pointers[i].r;
    }
    
    if (pointers[badseg].r != finall && pointers[badseg].idx != 2) cnt++;

    if (cnt > free || lft < free) {
        cout << "NIE\n";
    } else {
        cout << "TAK\n";
    }
}

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0); 

    int t; 
    cin >> t;
    while (t--) {
        returnable();
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 6032kb

input:

3
4 51
1 -1
11 50
-1 -1
-1 10
3 2
-1 -1
-1 -1
-1 -1
2 3
1 2
2 3

output:

TAK
NIE
NIE

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 26ms
memory: 5956kb

input:

1
200000 1000000000
490669427 -1
224278942 224287156
821104480 -1
861696576 861702036
807438935 807440055
574078002 574083717
465630141 -1
195378188 -1
-1 13500961
-1 977536179
92893115 -1
-1 661145418
-1 215804863
-1 685338515
544348999 -1
465532902 -1
130346949 -1
-1 526666304
635604584 635605404
...

output:

TAK

result:

ok single line: 'TAK'

Test #3:

score: 0
Accepted
time: 1ms
memory: 6076kb

input:

3
4 51
1 -1
11 50
-1 -1
-1 10
3 2
-1 -1
-1 -1
-1 -1
2 3
1 2
2 3

output:

TAK
NIE
NIE

result:

ok 3 lines

Test #4:

score: 0
Accepted
time: 24ms
memory: 5964kb

input:

1
197838 400000
34167 34169
352180 -1
235963 -1
-1 -1
160401 160405
347288 -1
270353 270354
214502 214504
183243 183245
-1 -1
-1 36193
-1 -1
-1 17557
273498 273500
269137 -1
395099 395100
285515 285518
-1 -1
71041 71042
324060 -1
-1 385151
-1 379645
-1 -1
-1 185142
-1 191584
89259 89261
328347 32834...

output:

TAK

result:

ok single line: 'TAK'

Test #5:

score: -100
Wrong Answer
time: 22ms
memory: 6040kb

input:

2
97340 150000
-1 101927
105937 -1
-1 107253
-1 47307
110550 -1
84061 84062
125176 125177
-1 15915
29617 -1
-1 -1
-1 43147
115958 -1
101807 101808
24866 -1
66826 66828
-1 31640
-1 5610
1281 1284
-1 -1
-1 -1
-1 73973
-1 2945
29064 -1
30653 -1
-1 63714
-1 -1
141389 141390
-1 27465
57358 -1
47388 47389...

output:

TAK
TAK

result:

wrong answer 1st lines differ - expected: 'NIE', found: 'TAK'