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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#697376#9434. Italian CuisineHojstyerWA 13ms3640kbC++204.0kb2024-11-01 13:40:002024-11-01 13:40:06

Judging History

你现在查看的是最新测评结果

  • [2024-11-01 13:40:06]
  • 评测
  • 测评结果:WA
  • 用时:13ms
  • 内存:3640kb
  • [2024-11-01 13:40:00]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;

template <class T>
struct Point
{
    T x;
    T y;
    Point(T x_ = 0, T y_ = 0) : x(x_), y(y_) {}

    template <class U>
    operator Point<U>()
    {
        return Point<U>(U(x), U(y));
    }
    Point &operator+=(Point p) &
    {
        x += p.x;
        y += p.y;
        return *this;
    }
    Point &operator-=(Point p) &
    {
        x -= p.x;
        y -= p.y;
        return *this;
    }
    Point &operator*=(T v) &
    {
        x *= v;
        y *= v;
        return *this;
    }
    Point operator-() const
    {
        return Point(-x, -y);
    }
    friend Point operator+(Point a, Point b)
    {
        return a += b;
    }
    friend Point operator-(Point a, Point b)
    {
        return a -= b;
    }
    friend Point operator*(Point a, T b)
    {
        return a *= b;
    }
    friend Point operator*(T a, Point b)
    {
        return b *= a;
    }
    friend bool operator==(Point a, Point b)
    {
        return a.x == b.x && a.y == b.y;
    }
    friend istream &operator>>(istream &is, Point &p)
    {
        return is >> p.x >> p.y;
    }
    friend ostream &operator<<(ostream &os, Point p)
    {
        return os << "(" << p.x << ", " << p.y << ")";
    }
};

template <class T>
T dot(Point<T> a, Point<T> b)
{
    return a.x * b.x + a.y * b.y;
}

template <class T>
T cross(Point<T> a, Point<T> b)
{
    return a.x * b.y - a.y * b.x;
}

template <class T>
double distance(Point<T> a, Point<T> b)
{
    T xx = a.x - b.x, yy = a.y - b.y;
    return sqrtl(xx * xx + yy * yy);
}
template <class T>
T distance2(Point<T> a, Point<T> b)
{
    T xx = a.x - b.x, yy = a.y - b.y;
    return xx * xx + yy * yy;
}
template <class T>
T square(Point<T> p)
{
    return dot(p, p);
}

template <class T>
double length(Point<T> p)
{
    return sqrt(double(square(p)));
}

long double length(Point<long double> p)
{
    return sqrt(square(p));
}

template <class T>
struct Line
{
    Point<T> a;
    Point<T> b;
    Line(Point<T> a_ = Point<T>(), Point<T> b_ = Point<T>()) : a(a_), b(b_) {}
};

template <class T>
Point<T> rotate(Point<T> a)
{
    return Point(-a.y, a.x);
}

template <class T>
int sgn(Point<T> a)
{
    return a.y > 0 || (a.y == 0 && a.x > 0) ? 1 : -1;
}

template <class T>
bool pointOnLineLeft(Point<T> p, Line<T> l)
{
    return cross(l.b - l.a, p - l.a) > 0;
}

template <class T>
Point<T> lineIntersection(Line<T> l1, Line<T> l2)
{
    return l1.a + (l1.b - l1.a) * (cross(l2.b - l2.a, l1.a - l2.a) / cross(l2.b - l2.a, l1.a - l1.b));
}

template <class T>
bool pointOnSegment(Point<T> p, Line<T> l)
{
    return cross(p - l.a, l.b - l.a) == 0 && min(l.a.x, l.b.x) <= p.x && p.x <= max(l.a.x, l.b.x) && min(l.a.y, l.b.y) <= p.y && p.y <= max(l.a.y, l.b.y);
}

void solve()
{
    int n;
    cin >> n;
    int x, y, r;
    cin >> x >> y >> r;

    vector<Point<int>> p(n);
    for (int i = 0; i < n; ++i)
        cin >> p[i].x >> p[i].y;

    ll ans = 0, res = 0;
    int pos = 0;
    for (int i = 0; i < n; ++i)
    {
        ll last = 0;
        while (true)
        {
            ll A = p[i].y - p[(pos + 1) % n].y, B = p[(pos + 1) % n].x - p[i].x, C = cross(p[i], p[(pos + 1) % n]);

            __int128_t le = A * x + B * y + C;
            if ((le > 0 && last < 0) || (le < 0 && last > 0))
                break;
            last = le;
            le = le * le;
            __int128_t re = 1ll * r * r;
            re *= A * A + B * B;
            if (le < re)
                break;

            res += cross(p[i] - p[pos], p[i] - p[(pos + 1) % n]);
            pos = (pos + 1) % n;
        }
        ans = max(ans, res);
        res -= cross(p[pos] - p[i], p[pos] - p[i + 1]);
    }
    cout << ans << "\n";
}

int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0), cout.tie(0);

    int t = 1;
    cin >> t;
    while (t--)
    {
        solve();
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3584kb

input:

3
5
1 1 1
0 0
1 0
5 0
3 3
0 5
6
2 4 1
2 0
4 0
6 3
4 6
2 6
0 3
4
3 3 1
3 0
6 3
3 6
0 3

output:

5
24
0

result:

ok 3 number(s): "5 24 0"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3640kb

input:

1
6
0 0 499999993
197878055 -535013568
696616963 -535013568
696616963 40162440
696616963 499999993
-499999993 499999993
-499999993 -535013568

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: -100
Wrong Answer
time: 13ms
memory: 3596kb

input:

6666
19
-142 -128 26
-172 -74
-188 -86
-199 -157
-200 -172
-199 -186
-195 -200
-175 -197
-161 -188
-144 -177
-127 -162
-107 -144
-90 -126
-87 -116
-86 -104
-89 -97
-108 -86
-125 -80
-142 -74
-162 -72
16
-161 -161 17
-165 -190
-157 -196
-154 -197
-144 -200
-132 -200
-128 -191
-120 -172
-123 -163
-138...

output:

5093
3086
2539
668
3535
7421
4883
37588
18713
1034
2479
3920
4372
2044
4996
5070
2251
4382
4175
1489
1154
3231
16402
1631
5086
56374
1692
6066
687
1512
4849
5456
2757
22579
8557
26700
1013
5203
95092
6042
39992
4480
2303
2728
1739
2187
3385
4266
6322
909
4334
1518
948
5036
1449
2376
3180
4810
1443
6...

result:

wrong answer 8th numbers differ - expected: '5711', found: '37588'