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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#697106#3846. Link-Cut Treeyzj123#AC ✓144ms14932kbC++202.5kb2024-11-01 10:35:462024-11-01 10:35:47

Judging History

你现在查看的是最新测评结果

  • [2024-11-01 10:35:47]
  • 评测
  • 测评结果:AC
  • 用时:144ms
  • 内存:14932kb
  • [2024-11-01 10:35:46]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e5 + 5;
int n, m;
struct Edge {
    int x, y;
}e[MAXN];
int prt[MAXN];
int get_prt(int x) {
    if (x == prt[x]) return x;
    return prt[x] = get_prt(prt[x]);
}
vector<pair<int, int> > g[MAXN];
int du[MAXN], vis1[MAXN], vis2[MAXN];
int ans[MAXN];
int p;
void dfs(int u)
{
    // cout << "u:" << u << "\n";
    vis1[u] = 0;
    for (auto x : g[u])
    {
        int v = x.first, num = x.second;
        if (v == p) 
        {
            ans[++ans[0]] = num;
            continue;
        }
        if (!vis1[v] || !vis2[v]) continue;
        // cout << "v:" << v << "\n";
        ans[++ans[0]] = num;
        dfs(v);
    }
}
void clear() 
{
    for (int i = 1; i <= n; i++) g[i].clear();
    for (int i = 1; i <= n; i++) du[i] = vis1[i] = vis2[i] = 0;
    ans[0] = 0;
}
void solve()
{
    scanf("%d%d", &n, &m);
    for (int i = 1; i <= n; i++) prt[i] = i;
    for (int i = 1; i <= m; i++) scanf("%d%d", &e[i].x, &e[i].y);
    int lim = 0;
    for (int i = 1; i <= m; i++)
    {
        int x = e[i].x, y = e[i].y;
        vis1[x] = vis1[y] = 1;
        int prtx = get_prt(x), prty = get_prt(y);
        if (prtx != prty) prt[prtx] = prty;
        else {
            lim = i;
            break;
        }
    }
    if (lim == 0) 
    {
        cout << "-1\n";
        return;
    }
    // cout << "lim:" << lim << "\n";
    for (int i = 1; i <= lim; i++)
    {
        int x = e[i].x, y = e[i].y;
        du[x]++, du[y]++;
        g[x].push_back(make_pair(y, i));
        g[y].push_back(make_pair(x, i));
    }
    for (int i = 1; i <= n; i++) vis2[i] = 1;
    queue<int> q;
    for (int i = 1; i <= n; i++) 
        if (du[i] == 1) q.push(i);
    while (q.size())
    {
        int u = q.front();
        q.pop();
        vis2[u] = 0;
        for (auto x : g[u])
        {
            int v = x.first;
            du[v]--;
            if (du[v] == 1) q.push(v);
        }
    } 
    // cout << "pos:";
    // for (int i = 1; i <= n; i++)
        // if (vis1[i] && vis2[i]) cout << i << " ";
    // cout << "\n";
    for (int i = 1; i <= n; i++)
        if (vis1[i] && vis2[i]) {
            p = i;
            dfs(i);
            break;
        }
    sort(ans + 1, ans + ans[0] + 1);
    int X = unique(ans + 1, ans + ans[0] + 1) - ans - 1;
    for (int i = 1; i <= X - 1; i++) cout << ans[i] << " ";
    cout << ans[X];
    cout << "\n";
}
int main() 
{
    int T;
    scanf("%d", &T);
    while (T--) solve(), clear();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 6004kb

input:

2
6 8
1 2
2 3
5 6
3 4
2 5
5 4
5 1
4 2
4 2
1 2
4 3

output:

2 4 5 6
-1

result:

ok 2 lines

Test #2:

score: 0
Accepted
time: 112ms
memory: 12192kb

input:

1658
9 20
6 4
5 8
1 7
2 3
3 8
3 1
4 8
5 3
7 6
1 6
4 9
4 1
9 3
2 5
4 5
8 9
1 8
4 2
5 7
3 6
14 78
13 12
10 8
2 10
6 13
2 14
13 1
14 10
9 6
2 13
8 3
9 8
5 6
14 12
8 1
9 14
9 5
12 6
5 10
3 12
10 4
8 5
9 10
6 8
1 6
12 4
3 13
1 5
10 3
13 9
10 13
2 5
4 7
7 1
7 6
9 3
2 12
1 10
9 1
1 14
3 1
3 4
11 1
11 6
7 1...

output:

2 5 8
3 5 7
1 3 4
2 3 4
2 3 4 7 13
1 3 4 5 9
3 4 7 12
1 2 3
8 10 11
2 3 5 7 12 13 14 15 16
1 2 3 5
1 2 4
1 3 4
1 2 3
1 2 3
10 11 15
1 5 6
1 5 7
1 2 3 4
-1
1 3 6
-1
1 2 3 5
-1
-1
6 8 9 10 11 16
1 2 6
2 3 4
-1
-1
7 8 12 13 18
-1
1 4 8 12
3 5 10
4 6 8
1 2 3 4
3 5 6
5 8 10 15
4 6 8
-1
1 2 3 5 6
1 3 4
1 ...

result:

ok 1658 lines

Test #3:

score: 0
Accepted
time: 144ms
memory: 14932kb

input:

10
100000 100000
1 2
2 3
3 4
4 5
5 6
6 7
7 8
8 9
9 10
10 11
11 12
12 13
13 14
14 15
15 16
16 17
17 18
18 19
19 20
20 21
21 22
22 23
23 24
24 25
25 26
26 27
27 28
28 29
29 30
30 31
31 32
32 33
33 34
34 35
35 36
36 37
37 38
38 39
39 40
40 41
41 42
42 43
43 44
44 45
45 46
46 47
47 48
48 49
49 50
50 51
...

output:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 ...

result:

ok 10 lines