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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#694885 | #8340. 3 Sum | Legend_dy | TL | 0ms | 3564kb | C++20 | 2.8kb | 2024-10-31 18:53:05 | 2024-10-31 18:53:06 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define int long long
constexpr int mod1 = 4179340454199820289;
constexpr int mod2 = 998244353;
constexpr int mod3 = 180143985094819841;
constexpr int mod4 = 4222124650659841;
constexpr int base = 10;
using i128 = __int128_t;
struct HH {
int a = 0;
int b = 0;
int c = 0;
int d = 0;
};
void inc(HH &x, HH y) {
x.a += y.a;
x.b += y.b;
x.c += y.c;
x.d += y.d;
if (x.a >= mod1) x.a -= mod1;
if (x.b >= mod2) x.b -= mod2;
if (x.c >= mod3) x.c -= mod3;
}
HH add(HH x, HH y) {
inc(x, y);
return x;
}
HH mul(HH x, HH y) {
int p = i128(x.a) * y.a % mod1;
int q = i128(x.b) * y.b % mod2;
int r = i128(x.c) * y.c % mod3;
return HH{p, q, r};
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
int n, K;
cin >> n >> K;
auto Mod = [&](string s) {
reverse(s.begin(), s.end());
int m = s.size();
vector<int> b(K);
for (int j = 0; j < s.size(); j++) {
b[j % K] += s[j] - '0';
}
while (true) {
bool ok = 1;
for (int j = 0; j < K; j++) {
if (b[j] >= 10) ok = 0;
}
if (ok) break;
vector<int> c(K);
for (int j = 0; j < K; j++) {
c[j] += b[j] % 10;
c[(j + 1) % K] += b[j] / 10;
}
b = move(c);
}
if (b == vector<int>(K, 9)) b = vector<int>(K, 0);
return b;
};
auto Hash = [&](vector<int>b) {
reverse(b.begin(), b.end());
HH hash;
for (int j = 0; j < K; j++) {
hash = add(mul(hash, HH{10, 10, 10}), HH{b[j], b[j], b[j]});
}
return hash;
};
vector<HH> a(n);
for (int i = 0; i < n; i++) {
string s;
cin >> s;
a[i] = Hash(Mod(s));
}
auto equal = [&](HH x, HH y) {
return x.a == y.a && x.b == y.b && x.c == y.c;
};
int ans = 0;
auto solve = [&](HH val) {
for (int i = 0; i < n; i++) {
for (int j = i; j < n; j++) {
for (int k = j; k < n; k++) {
if (equal(add(add(a[i], a[j]), a[k]), val)) {
ans++;
}
}
}
}
};
solve(HH{0, 0, 0});
HH h1;
for (int i = 0; i < K; i++) {
h1 = add(mul(h1, {base, base, base}), {9, 9, 9});
}
solve(h1);
HH h2 = {1, 1, 1};
for (int i = 0; i < K - 1; i++) {
h2 = add(mul(h2, {base, base, base}), {9, 9, 9});
}
h2 = add(mul(h2, {base, base, base}), {8, 8, 8});
solve(h2);
cout << ans;
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3564kb
input:
4 1 0 1 10 17
output:
3
result:
ok 1 number(s): "3"
Test #2:
score: -100
Time Limit Exceeded
input:
500 859 7118711592236878297922359501613604144948355616986970837340677671376753603836852811886591300370143151943368529129749813118476151865844255212534355441611481420938483178075143062691345257288242460282715389758789648541099090735875617822348551942134616963557723055980260082230902505269975518146286...