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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#693857#7944. Max Minus Minkzxx00011WA 16ms3684kbC++14876b2024-10-31 16:51:252024-10-31 16:51:26

Judging History

你现在查看的是最新测评结果

  • [2024-10-31 16:51:26]
  • 评测
  • 测评结果:WA
  • 用时:16ms
  • 内存:3684kb
  • [2024-10-31 16:51:25]
  • 提交

answer

#include<iostream>
using namespace std;
const int N=2e5+10;
int t,n;
int a[N];
int maxx,minn;
int ans=0;
bool check(int x)   //能否把最大值下降x点距离 
{
	//if(x==0) return 1;
	//cout<<x<<endl; 
	int lj=2e5+10,rj=0;
	//int lb=2e5+10,rb=0;
	for(int i=1;i<=n;i++)
	{
		if(a[i]>maxx-x)     //需要下降 
		{
			rj=max(rj,i);
			lj=min(lj,i);
		}
	}
	for(int i=1;i<=n;i++)
	{
	    if(a[i]<minn+x)     //不能下降 
		{
			if(i>=lj&&i<=rj) return 0;
		}
	}
	return 1;
}
int main()
{
	cin>>t;
	while(t--)
	{
	cin>>n;
	maxx=0,minn=1e9+10;
	for(int i=1;i<=n;i++) 
	{
		cin>>a[i];
		maxx=max(maxx,a[i]);
		minn=min(minn,a[i]);
	}
	int l=0,r=maxx-minn;
	ans=0;
	while(l<=r)
	{
		int mid=(l+r)/2;
		if(check(mid))
		{
			ans=mid;
			l=mid+1;
		}
		else r=mid-1;
	}
	cout<<maxx-minn-ans<<endl;
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3628kb

input:

4
3
42 42 42
4
1 2 2 1
5
1 100 1 100 1
6
1 2 3 4 5 6

output:

0
0
99
2

result:

ok 4 number(s): "0 0 99 2"

Test #2:

score: -100
Wrong Answer
time: 16ms
memory: 3684kb

input:

19530
6
2 3 3 3 4 3
6
2 4 4 2 5 5
6
2 5 2 5 1 3
6
4 4 1 2 4 1
5
5 4 5 3 3
5
2 2 1 5 1
6
3 1 2 4 2 3
5
5 5 4 4 5
6
5 3 3 1 4 2
6
3 3 2 4 2 4
6
1 2 4 5 2 5
5
3 4 5 5 3
6
4 3 3 3 4 3
6
1 5 1 2 3 1
5
5 5 2 1 4
6
1 2 5 3 5 2
6
4 5 2 4 5 2
5
2 4 2 4 1
4
2 3 3 3
6
1 2 2 1 4 5
6
3 2 1 3 3 2
6
2 1 1 2 5 3
6
...

output:

1
2
3
3
1
1
2
1
3
2
3
1
1
2
3
2
3
2
0
1
2
2
0
3
2
2
3
3
2
2
3
4
3
2
3
2
2
2
2
2
2
4
2
1
2
1
3
4
3
1
3
2
2
4
3
2
1
1
1
2
1
2
3
1
4
4
3
2
2
1
1
2
1
3
3
2
1
2
1
1
2
1
1
2
2
2
1
3
2
2
4
3
2
1
1
3
2
4
1
1
1
2
2
1
1
1
1
2
4
2
2
2
3
3
2
2
3
1
3
1
1
1
1
2
2
2
2
2
2
1
2
1
2
4
1
2
1
3
2
2
2
1
2
1
2
1
2
2
2
4
...

result:

wrong answer 8th numbers differ - expected: '0', found: '1'