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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#693256 | #8551. DFS Order 5 | szy10010 | WA | 27ms | 36036kb | C++23 | 3.0kb | 2024-10-31 15:49:43 | 2024-10-31 15:49:44 |
Judging History
answer
#include <map>
#include <set>
#include <queue>
#include <deque>
#include <cmath>
#include <vector>
#include <cstring>
#include <iostream>
#include <algorithm>
#include <unordered_map>
using namespace std;
#define fi first
#define se second
#define u1 (u<<1)
#define u2 (u<<1|1)
#define pb push_back
#define pp pop_back()
#define int long long
#define laile cout<<"laile"<<endl
#define lowbit(x) ((x)&(-x))
#define double long double
#define sf(x) scanf("%lld",&x)
#define sff(x,y) scanf("%lld %lld",&x,&y)
#define sd(x) scanf("%Lf",&x)
#define sdd(x,y) scanf("%Lf %Lf",&x,&y)
#define _for(i,n) for(int i=0;i<(n);++i)
#define _rep(i,a,b) for(int i=(a);i<=(b);++i)
#define _pre(i,a,b) for(int i=(a);i>=(b);--i)
#define all(x) (x).begin(), (x).end()
#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0)
typedef unsigned long long ULL;
typedef pair<int,int>PII;
const int N=1e6+10,INF=4e18;
int n,m;
int h[N],e[N],ne[N],idx;
int depth[N],fa[N][20],sz[N],cnt[N],son[N];
int tr[N+10];//c[N];
int query(int x)
{
int res=0;
for(int i=x;i;i-=lowbit(i))res+=tr[i];
return res;
}
void addtree(int x,int c)
{
for(int i=x;i<=N;i+=lowbit(i))tr[i]+=c;
}
void add(int a,int b)
{
e[idx]=b;
ne[idx]=h[a];
h[a]=idx++;
}
void bfs(int root)
{
memset(depth,0x3f,sizeof(depth));
depth[0]=0;
depth[root]=1;
queue<int>q;
q.push(root);
while(q.size())
{
auto t=q.front();
q.pop();
for(int i=h[t];~i;i=ne[i])
{
int j=e[i];
if(depth[j]>depth[t]+1)
{
depth[j]=depth[t]+1;
q.push(j);
fa[j][0]=t;
for(int i=1;i<=19;i++)
fa[j][i]=fa[fa[j][i-1]][i-1];
}
}
}
return;
}
int la(int v, int d) {
d=depth[v]-d;
for (int k = 20; k >= 0; --k) {
if (d >= (1 << k)) {
v = fa[v][k];
d -= (1 << k);
}
}
return v;
}
int lca(int a,int b)
{
if(depth[a]<depth[b])swap(a,b);
for(int i=19;i>=0;i--)
if(depth[fa[a][i]]>=depth[b])a=fa[a][i];
if(a==b)return a;
for(int i=19;i>=0;i--)
if(fa[a][i]!=fa[b][i])
a=fa[a][i],b=fa[b][i];
return fa[a][0];
}
int id[N],nowid;
void dfs(int u,int fa)
{
sz[u]=1;
id[u]=++nowid;
for(int i=h[u];~i;i=ne[i])
{
int j=e[i];
if(j==fa)continue;
dfs(j,u);
sz[u]+=sz[j];
}
return ;
}
void solve()
{
memset(h,-1,sizeof(h));
cin>>n>>m;
_rep(i,2,n)
{
int a,b;
cin>>a>>b;
add(a,b);
add(b,a);
}
bfs(1);
dfs(1,0);
while(m--)
{
cin>>n;
bool bl=true;
int pre=0;
_rep(i,1,n)
{
cin>>son[i];
if(pre)
{
if(pre!=fa[son[i]][0])
{
bool pan=true;
int lc=lca(pre,son[i]);
if(!pan||!fa[son[i]]||fa[son[i]][0]!=lc||query(son[i]+sz[son[i]]-1)-query(son[i]-1)==sz[son[i]])
{
// cout<<son[i]<<" "<<cnt[lc_1]<<" "<<sz[lc_1]<<endl;
bl=false;
break;
}
}
}
addtree(son[i],1);
pre=son[i];
}
if(bl)cout<<"Yes\n";
else cout<<"No\n";
}
return ;
}
signed main()
{
IOS;
int T=1;
// cin>>T;
while(T--)
solve();
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 36036kb
input:
6 7 1 2 1 3 2 4 3 5 2 6 2 4 1 2 4 2 2 4 3 2 4 4 2 4 5 2 4 6 6 1 2 6 4 3 5
output:
No No Yes No No Yes Yes
result:
ok 7 tokens
Test #2:
score: -100
Wrong Answer
time: 27ms
memory: 34980kb
input:
10 100000 7 2 1 7 7 10 8 6 8 7 1 3 4 5 9 5 5 8 8 8 9 7 2 8 1 6 1 4 8 3 5 2 6 7 10 3 9 9 1 1 1 8 10 3 2 9 3 8 7 3 7 5 6 2 8 5 9 1 6 3 4 6 2 1 3 5 8 9 2 4 9 1 3 2 1 5 5 8 5 1 7 9 10 5 2 9 2 6 4 10 6 3 8 3 4 5 8 2 8 4 9 4 10 1 2 4 3 3 6 3 1 3 6 1 1 6 8 3 1 3 7 3 2 3 9 1 5 4 3 7 8 10 9 4 2 3 10 2 5 4 3 ...
output:
No No No No No No No Yes No No No No No No No No No Yes No No Yes No No No No No Yes No No No Yes No No No No No Yes No No No No No No No No No No No No No Yes No No Yes No No No No No No No Yes No No No Yes No No No No No Yes No No No No No No No No No No No No No Yes Yes No Yes No No No No No No Y...
result:
wrong answer 4th words differ - expected: 'Yes', found: 'No'