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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#691177 | #2943. Neighbors | nickbelov | TL | 48ms | 3644kb | C++20 | 2.6kb | 2024-10-31 10:16:57 | 2024-10-31 10:16:59 |
Judging History
answer
#include <vector>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define F(i, k) for(int16_t i = 0; i < (k); ++i)
#define G(x) int16_t x; cin >> x;
#define D for(int i = 1; i <= n; ++i) for(int j = 1; j <= m; ++j) cout << gr[i][j] << " \n"[j == m];
#define MT(r, c, i) (!i ? r : c)
#define N 15
#define M 2
int16_t n = -1, m = -1;
int16_t gr[N][N], mk[M][N];int8_t du[N][N], dl[N][N];
int16_t tbl[N][3];
#define ADD(r, c, x) { gr[r][c] ^= x; F(i, M) mk[i][MT(r, c, i)] ^= 1 << x; }
bool bT(int16_t r, int16_t c) {
if(r > n) return true;
int16_t rI = r + (c == m), cI = c % m + 1;
if(gr[r][c]) return bT(rI, cI);
int16_t mask = mk[0][r] & mk[1][c]
& tbl[gr[r - 1][c]][du[r][c]] & tbl[gr[r][c - 1]][dl[r][c]]
& tbl[gr[r + 1][c]][du[r + 1][c]] & tbl[gr[r][c + 1]][dl[r][c + 1]];
for(int16_t x = __builtin_ctzll(mask); mask >> x; ++x) if((mask >> x) & 1) {
ADD(r, c, x);
if(bT(rI, cI)) return true;
ADD(r, c, x);
}
return false;
}
vector<pair<int,int>> ord;
bool bT(int idx) {
if(idx >= n*m) return true;
auto [r,c] = ord[idx];
// cout << r << " " << c << endl;
// cout << "\t" << idx << endl;
if(gr[r][c]) return bT(idx+1);
int16_t mask = mk[0][r] & mk[1][c]
& tbl[gr[r - 1][c]][du[r][c]] & tbl[gr[r][c - 1]][dl[r][c]]
& tbl[gr[r + 1][c]][du[r + 1][c]] & tbl[gr[r][c + 1]][dl[r][c + 1]];
for(int16_t x = __builtin_ctzll(mask); mask >> x; ++x) if((mask >> x) & 1) {
ADD(r, c, x);
if(bT(idx+1)) return true;
ADD(r, c, x);
}
return false;
}
void init() {
cin >> n; G(k) m = n;
fill_n(tbl[0], 3, (1 << 15) - 1);
F(i, n + 1) if(i) {
tbl[i][0] = (1 << 15) - 1; //no constraint
tbl[i][2] = 5 << (i - 1); //diamond
tbl[i][1] = ~tbl[i][2]; //no diamond
}
F(q, 2 * n - 1) if(q & 1) {
int16_t r = (q + 1) / 2;
string s; cin >> s;
F(i, n) du[r + 1][i + 1] = 1 + (s[i] == '1');
} else {
int16_t r = q / 2;
string s; cin >> s;
F(i, n) if(i) dl[r + 1][i + 1] = 1 + (s[i - 1] == '1');
}
F(i, M) fill_n(mk[i], N, (1 << (n + 1)) - 2);
while(k--) {
G(r) G(c) G(v)
ADD(r, c, v);
}
for(int i = 1;i<=n;i++) for(int j = 1;j<=m;j++) ord.emplace_back(i,j);
mt19937 gen(__builtin_ia32_rdtsc());
ranges::shuffle(ord,gen);
}
int main() {
clock_t t = clock();
init(); bT(0); D
// cout << (clock() - t) / (double)(CLOCKS_PER_SEC) << '\n';
}
詳細信息
Test #1:
score: 100
Accepted
time: 48ms
memory: 3640kb
input:
7 6 100000 0111010 100000 0000000 001001 0010010 000000 0000000 000000 0000000 001000 0001010 000001 2 7 7 6 1 2 3 3 2 7 6 2 5 3 6 4 7 6
output:
4 3 5 7 1 6 2 1 2 4 6 3 5 7 7 5 2 1 6 3 4 3 7 1 5 2 4 6 5 1 6 2 4 7 3 2 6 3 4 7 1 5 6 4 7 3 5 2 1
result:
ok 7 lines
Test #2:
score: 0
Accepted
time: 5ms
memory: 3644kb
input:
7 6 100011 0010000 000001 1101010 010010 0111100 010000 0001000 011011 0001000 010101 0100000 000010 4 3 2 4 5 7 1 2 6 5 4 5 2 4 2 5 1 1
output:
5 6 4 7 1 2 3 3 1 5 2 4 6 7 4 2 1 3 6 7 5 6 3 2 4 7 5 1 1 7 6 5 2 3 4 7 4 3 6 5 1 2 2 5 7 1 3 4 6
result:
ok 7 lines
Test #3:
score: -100
Time Limit Exceeded
input:
8 9 0001000 10110100 1000000 00001110 0001001 10100011 0000101 00000100 0101001 10000000 0000000 00100101 0010001 00100000 0000010 3 5 3 4 1 7 6 8 6 4 5 1 1 4 7 1 3 5 1 5 6 3 6 6 6 2 8