QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#690262 | #6128. Flippy Sequence | DanRan02 | AC ✓ | 40ms | 7128kb | C++20 | 979b | 2024-10-30 21:18:49 | 2024-10-30 21:18:50 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
void solve() {
LL n;
cin >> n;
string s, t;
cin >> s >> t;
LL cnt1 = 0, cnt2 = 0, pre = 0, aft = 0;
for (int i = 0; i < n; i++) {
if (s[i] != t[i]) {
int pos = i;
while (i < n && s[i] != t[i]) i++;
if (!cnt1) {
cnt1 = i - pos;
pre = pos;
aft = n - i;
} else if (!cnt2) {
cnt2 = i - pos;
aft = n - i;
} else {
cout << 0 << '\n';
return;
}
}
// cout << pre << ' ' << af/t << '\n';
}
LL res = 0;
if (cnt1 < cnt2) swap(cnt1, cnt2);
if (!cnt1 && !cnt2) {
res = (n - 1) * n / 2 + n;
cout << res << '\n';
} else if (!cnt2) {
if (pre) res += 2 * pre;
if (aft) res += 2 * aft;
if (cnt1 > 1) res += (cnt1 - 1) * 2;
cout << res << '\n';
} else {
cout << 6 << '\n';
}
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int T = 1;
cin >> T;
while (T--) {
solve();
}
return 0;
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3528kb
input:
3 1 1 0 2 00 11 5 01010 00111
output:
0 2 6
result:
ok 3 number(s): "0 2 6"
Test #2:
score: 0
Accepted
time: 40ms
memory: 7128kb
input:
126648 1 0 0 1 1 0 2 01 01 2 01 11 2 10 11 2 11 00 3 011 011 3 010 110 3 011 001 3 111 001 3 001 000 3 101 000 3 011 000 3 111 000 4 1111 1111 4 1110 0110 4 0010 0110 4 1011 0111 4 1001 1011 4 0100 1110 4 0000 0110 4 0111 1001 4 1001 1000 4 1011 0010 4 0001 0100 4 1000 0101 4 0100 0111 4 1101 0110 4...
output:
1 0 3 2 2 2 6 4 4 4 4 6 4 4 10 6 6 6 6 6 6 6 6 6 6 6 6 6 6 6 15 8 8 8 8 6 8 8 8 6 6 6 8 6 8 8 8 6 6 6 6 0 6 6 8 6 6 6 8 6 8 8 21 10 10 10 10 6 10 10 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 10 6 6 6 6 0 6 6 6 0 0 0 6 0 6 6 10 6 6 6 6 0 6 6 10 6 6 6 10 6 10 10 28 12 12 12 12 6 12 12 1...
result:
ok 126648 numbers