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QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#689194#6398. Puzzle: TapaMiniLongWA 1ms10092kbC++145.4kb2024-10-30 15:46:222024-10-30 15:46:24

Judging History

你现在查看的是最新测评结果

  • [2024-10-30 15:46:24]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:10092kb
  • [2024-10-30 15:46:22]
  • 提交

answer

#include <bits/stdc++.h>
#define _rep(i, x, y) for(int i = x; i <= y; ++i)
#define _req(i, x, y) for(int i = x; i >= y; --i)
#define _rev(i, u) for(int i = head[u]; i; i = e[i].nxt)
#define pb push_back
#define fi first
#define se second
#define mst(f, i) memset(f, i, sizeof f)
using namespace std;
#ifdef ONLINE_JUDGE
#define debug(...) 0
#else
#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)
#endif
typedef long long ll;
typedef pair<int, int> PII;
namespace fastio{
    #ifdef ONLINE_JUDGE
    char ibuf[1 << 20],*p1 = ibuf, *p2 = ibuf;
    #define get() p1 == p2 && (p2 = (p1 = ibuf) + fread(ibuf, 1, 1 << 20, stdin), p1 == p2) ? EOF : *p1++
    #else
    #define get() getchar()
    #endif
    template<typename T> inline void read(T &t){
        T x = 0, f = 1;
        char c = getchar();
        while(!isdigit(c)){
            if(c == '-') f = -f;
            c = getchar();
        }
        while(isdigit(c)) x = x * 10 + c - '0', c = getchar();
        t = x * f;
    }
    template<typename T, typename ... Args> inline void read(T &t, Args&... args){
        read(t);
        read(args...);
    }
    template<typename T> void write(T t){
        if(t < 0) putchar('-'), t = -t;
        if(t >= 10) write(t / 10);
        putchar(t % 10 + '0');
    }
    template<typename T, typename ... Args> void write(T t, Args... args){
        write(t), putchar(' '), write(args...);
    }
    template<typename T> void writeln(T t){
        write(t);
        puts("");
    }
    template<typename T> void writes(T t){
        write(t), putchar(' ');
    }
    #undef get
};
using namespace fastio;
#define multitest() int T; read(T); _rep(tCase, 1, T)
namespace Calculation{
    const ll mod = 998244353;
    ll ksm(ll p, ll h){ll base = p % mod, res = 1; while(h){if(h & 1ll) res = res * base % mod; base = base * base % mod, h >>= 1ll;} return res;}
    void dec(ll &x, ll y){x = ((x - y) % mod + mod) % mod;}
    void add(ll &x, ll y){x = (x + y) % mod;}
    void mul(ll &x, ll y){x = x * y % mod;}
    ll sub(ll x, ll y){return ((x - y) % mod + mod) % mod;}
    ll pls(ll x, ll y){return ((x + y) % mod + mod) % mod;}
    ll mult(ll x, ll y){return x * y % mod;}
}
using namespace Calculation;
const int N = 1005, M = 1e6 + 5, inf = 0x3f3f3f3f;
int n, m, dx[] = {-1, 0, 1, 0}, dy[] = {0, -1, 0, 1};
char ch[N][N];
int code(int x, int y){return (x - 1) * m + y;}
bool check(int x, int y){
    x = 2 * x - 1, y = 2 * y - 1;
    return ch[x][y] != '8' && ch[x][y] != '5' && ch[x][y] != '3';
}
namespace Flow{
    int s, t, ecnt = 1, head[M], cur[M];
    struct edge{
        int v, w, nxt;
    }e[M << 1];
    void add(int u, int v, int w){
        e[++ecnt] = edge{v, w, head[u]}, head[u] = ecnt;
        e[++ecnt] = edge{u, 0, head[v]}, head[v] = ecnt;
    }
    int num[M];
    bool bfs(int s, int t){
        fill(num + s, num + t + 1, 0);
        queue<int> q;
        q.push(s), cur[s] = head[s], num[s] = 1;
        while(q.size()){
            int u = q.front(); q.pop();
            _rev(i, u){
                int v = e[i].v;
                if(!num[v] && e[i].w){
                    num[v] = num[u] + 1;
                    cur[v] = head[v];
                    q.push(v);
                }
            }
        }
        return num[t];
    }
    int dfs(int u, int in){
        int out = 0;
        if(u == t) return in;
        for(int i = cur[u]; i && in; i = e[i].nxt){
            int v = e[i].v;
            cur[u] = i;
            if(e[i].w && num[v] == num[u] + 1){
                int d = dfs(v, min(e[i].w, in));
                e[i].w -= d, e[i ^ 1].w += d;
                in -= d, out += d;
            }
        }
        if(!out) num[u] = 0;
        return out;
    }
    int Dinic(){
        int Flow = 0;
        while(bfs(s, t)) Flow += dfs(s, inf);
        return Flow;
    }
}
using namespace Flow;
map<PII, PII> mp;
int main(){
    read(n, m);
    _rep(i, 1, n * 2 - 1) scanf("%s", ch[i] + 1);
    int cnt = 0;
    s = 0, t = 2 * n * m + 1;
    _rep(i, 1, n){
        _rep(j, 1, m){
            cnt += check(i, j);
            if((i + j) & 1) continue;
            if(check(i, j)){
                _rep(k, 0, 3){
                    int x = i + dx[k], y = j + dy[k];
                    if(x < 1 || x > n || y < 1 || y > m) continue;
                    if(!check(x, y) || ch[2 * i - 1][2 * j - 1] == '7' && ch[2 * x - 1][2 * y - 1] != '7' || ch[2 * i - 1][2 * j - 1] != '7' && ch[2 * x - 1][2 * y - 1] == '7') continue;
                    int u = code(i, j), v = code(x, y);
                    add(u, v + n * m, 1);
                    mp[{u, v + n * m}] = {2 * i - 1 + dx[k], 2 * j - 1 + dy[k]};
                }
            }
        }
    }
    _rep(i, 1, n * m) add(s, i, 1), add(n * m + i, t, 1);
    if((cnt & 1) || Dinic() != cnt / 2) return puts("NO"), 0;
    _rep(i, 1, 2 * n - 1) _rep(j, 1, 2 * m - 1) if(ch[i][j] == '.') ch[i][j] = '#';
    _rep(i, 1, n){
        _rep(j, 1, m){
            if(!check(i, j)) continue;
            int u = code(i, j), v = 0;
            _rev(k, u){
                if(e[k].v == s || e[k].w) continue;
                v = e[k].v;
            }
            PII cur = mp[{u, v}];
            ch[cur.fi][cur.se] = '.';
        }
    }
    puts("YES");
    _rep(i, 1, 2 * n - 1){
        _rep(j, 1, 2 * m - 1) putchar(ch[i][j]);
        puts("");
    }
    return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 1ms
memory: 10092kb

input:

3 3
2.4.3
.....
5.8.5
.....
3.5.3

output:

YES
2.4#3
#####
5#8#5
#####
3#5#3

result:

ok Correct.

Test #2:

score: 0
Accepted
time: 1ms
memory: 9796kb

input:

3 3
3.4.3
.....
5.7.5
.....
3.5.3

output:

NO

result:

ok Correct.

Test #3:

score: 0
Accepted
time: 0ms
memory: 9816kb

input:

2 2
2.2
...
2.2

output:

YES
2.2
###
2.2

result:

ok Correct.

Test #4:

score: -100
Wrong Answer
time: 0ms
memory: 9748kb

input:

2 50
2.4.4.4.4.5.5.5.5.5.5.5.5.4.5.5.4.4.5.5.5.5.4.5.5.5.5.5.4.4.5.4.5.5.5.5.5.5.5.5.5.5.5.4.4.5.5.4.5.3
...................................................................................................
2.5.5.4.4.5.5.5.4.4.5.5.5.4.5.5.5.5.5.5.5.5.4.4.4.5.5.5.5.5.5.4.4.4.5.5.5.5.5.5.5.4.4.5.5.5.5.4...

output:

YES
2#4.4#4.4#5#5#5#5#5#5#5#5#4#5#5#4.4#5#5#5#5#4#5#5#5#5#5#4.4#5#4#5#5#5#5#5#5#5#5#5#5#5#4.4#5#5#4#5#3
.#########################.#################.#################.###############################.####
2#5#5#4.4#5#5#5#4.4#5#5#5#4#5#5#5#5#5#5#5#5#4#4.4#5#5#5#5#5#5#4#4.4#5#5#5#5#5#5#5#4.4#5#5#5#5#4#...

result:

wrong answer Clue not satisfied at (1,27), non-consecutive shaded cells