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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#689173 | #6433. Klee in Solitary Confinement | lir_nut | WA | 14ms | 55008kb | C++14 | 1.4kb | 2024-10-30 15:40:43 | 2024-10-30 15:40:44 |
Judging History
answer
#include <iostream>
#include <cstdio>
#include <utility>
#include <algorithm>
#include <cstring>
#include <vector>
#include <map>
#include <queue>
#include <cmath>
#include <set>
#include <stack>
#define test
#ifndef test
freopen("in.in", stdin);
#endif
#define rint register int
#define ll long long
#define P pair<char, int>
const int N = 1e6+5;
using namespace std;
int arr[N], s[N * 2];
vector<int> dic[N * 2];
void solution(){
int n, k; scanf("%d%d", &n, &k);
for(int i = 1; i <= n; i++){
scanf("%d", &arr[i]);
dic[arr[i] + N].push_back(-1);
dic[arr[i] + k + N].push_back(1);
s[arr[i] + N]++;
}
int ans = 0;
for(int i = 0; i < 2 * N; i++){
int maxnum = 0, minnum = 0, mxlabel = 0, mnlabel = 0, sub = 0;
for(int j = 0; j < dic[i].size(); j++){
if(j) dic[i][j] += dic[i][j - 1];
if(dic[i][j] >= maxnum){
maxnum = dic[i][j];
mxlabel = j;
if(mxlabel > mnlabel) sub = maxnum - minnum;
}
if(dic[i][j] < minnum){
minnum = dic[i][j];
mnlabel = j;
}
}
ans = max(ans, s[i] + sub);
}
printf("%d", ans);
}
int main(){
test
int t = 1;
//scanf("%d", &t);
while (t--){
solution();
if(t) printf("\n");
}
}
詳細信息
Test #1:
score: 100
Accepted
time: 6ms
memory: 51356kb
input:
5 2 2 2 4 4 4
output:
5
result:
ok 1 number(s): "5"
Test #2:
score: 0
Accepted
time: 8ms
memory: 50768kb
input:
7 1 3 2 3 2 2 2 3
output:
6
result:
ok 1 number(s): "6"
Test #3:
score: 0
Accepted
time: 9ms
memory: 53608kb
input:
7 1 2 3 2 3 2 3 3
output:
5
result:
ok 1 number(s): "5"
Test #4:
score: 0
Accepted
time: 4ms
memory: 55008kb
input:
9 -100 -1 -2 1 2 -1 -2 1 -2 1
output:
3
result:
ok 1 number(s): "3"
Test #5:
score: -100
Wrong Answer
time: 14ms
memory: 50816kb
input:
200 121649 0 527189 -1000000 -306471 -998939 527189 -1000000 -1000000 0 527189 0 527189 0 527189 -306471 -998939 -306471 -306471 -306471 0 0 527189 527189 1000000 527189 -1000000 1000000 648838 -1000000 -998939 -998939 -998939 0 1000000 -1000000 -998939 527189 1000000 648838 -1000000 1000000 648838 ...
output:
21929
result:
wrong answer 1st numbers differ - expected: '37', found: '21929'