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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#689073#862. Social Justicewzj33300WA 0ms3564kbC++236.2kb2024-10-30 15:09:482024-10-30 15:09:50

Judging History

你现在查看的是最新测评结果

  • [2024-10-30 15:09:50]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3564kb
  • [2024-10-30 15:09:48]
  • 提交

answer

/**
  * created     : 30.10.2024 08:58:08
  * author      : wzj33300
  */

#include <bits/stdc++.h>
using namespace std;

#ifdef DEBUG
#include <algo/debug.h>
#else
#define debug(...) 42
#define assert(...) 42
#endif

using ll = long long;
using u32 = unsigned int;
using u64 = unsigned long long;
using db = long double;  // or double, if TL is tight
using str = string;      // yay python!

// pairs
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;
#define mp make_pair
#define fi first
#define se second

// ^ lol this makes everything look weird but I'll try it
template <class T>
using vc = vector<T>;
template <class T, size_t SZ>
using AR = array<T, SZ>;
using vi = vc<int>;
using vb = vc<bool>;
using vl = vc<ll>;
using vd = vc<db>;
using vs = vc<str>;
using vpi = vc<pi>;
using vpl = vc<pl>;
using vpd = vc<pd>;

// vectors
// oops size(x), rbegin(x), rend(x) need C++17
#define sz(x) int((x).size())
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define rall(x) x.rbegin(), x.rend()
#define sor(x) sort(all(x))
#define rsz resize
#define ins insert
#define pb push_back
#define eb emplace_back
#define ft front()
#define bk back()

#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep1(i, n) for (int i = 1; i < (n); ++i)
#define rep1n(i, n) for (int i = 1; i <= (n); ++i)
#define repr(i, n) for (int i = (n) - 1; i >= 0; --i)

#define rep_subset(t, s) \
  for (ll t = (s); t >= 0; t = (t == 0 ? -1 : (t - 1) & (s)))

#define lb lower_bound
#define ub upper_bound
template <class T>
int lwb(vc<T> &a, const T &b) {
  return int(lb(all(a), b) - bg(a));
}
template <class T>
int upb(vc<T> &a, const T &b) {
  return int(ub(all(a), b) - bg(a));
}
// const int MOD = 998244353;  // 1e9+7;
const int Big = 1e9;  // not too close to INT_MAX
const ll BIG = 1e18;  // not too close to LLONG_MAX
const db PI = acos((db)-1);
const int dx[4]{1, 0, -1, 0}, dy[4]{0, 1, 0, -1};  // for every grid problem!!
mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count());
template <class T>
using pqg = priority_queue<T, vector<T>, greater<T>>;

int pct(int x) { return __builtin_popcount(x); }
int pct(u32 x) { return __builtin_popcount(x); }
int pct(ll x) { return __builtin_popcountll(x); }
int pct(u64 x) { return __builtin_popcountll(x); }
int popcnt_mod_2(int x) { return __builtin_parity(x); }
int popcnt_mod_2(u32 x) { return __builtin_parity(x); }
int popcnt_mod_2(ll x) { return __builtin_parityll(x); }
int popcnt_mod_2(u64 x) { return __builtin_parityll(x); }
// (0, 1, 2, 3, 4) -> (-1, 0, 1, 1, 2)
int topbit(int x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }
int topbit(u32 x) { return (x == 0 ? -1 : 31 - __builtin_clz(x)); }
int topbit(ll x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }
int topbit(u64 x) { return (x == 0 ? -1 : 63 - __builtin_clzll(x)); }
// (0, 1, 2, 3, 4) -> (-1, 0, 1, 0, 2)
int lowbit(int x) { return (x == 0 ? -1 : __builtin_ctz(x)); }
int lowbit(u32 x) { return (x == 0 ? -1 : __builtin_ctz(x)); }
int lowbit(ll x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }
int lowbit(u64 x) { return (x == 0 ? -1 : __builtin_ctzll(x)); }

template <typename T>
T floor(T a, T b) {
  return a / b - (a % b && (a ^ b) < 0);
}
template <typename T>
T ceil(T x, T y) {
  return floor(x + y - 1, y);
}
template <typename T>
T bmod(T x, T y) {
  return x - y * floor(x, y);
}
template <typename T>
pair<T, T> divmod(T x, T y) {
  T q = floor(x, y);
  return {q, x - q * y};
}

template <class T>
bool ckmin(T &a, const T &b) {
  return b < a ? a = b, 1 : 0;
}  // set a = min(a,b)
template <class T>
bool ckmax(T &a, const T &b) {
  return a < b ? a = b, 1 : 0;
}  // set a = max(a,b)

template <class T, class U>
T fstTrue(T lo, T hi, U f) {
  ++hi;
  assert(lo <= hi);  // assuming f is increasing
  while (lo < hi) {  // find first index such that f is true
    T mid = lo + (hi - lo) / 2;
    f(mid) ? hi = mid : lo = mid + 1;
  }
  return lo;
}
template <class T, class U>
T lstTrue(T lo, T hi, U f) {
  --lo;
  assert(lo <= hi);  // assuming f is decreasing
  while (lo < hi) {  // find first index such that f is true
    T mid = lo + (hi - lo + 1) / 2;
    f(mid) ? lo = mid : hi = mid - 1;
  }
  return lo;
}

// signed main() {
int main() {
  // freopen("ex_d1.in", "r", stdin);
  // freopen("my.out", "w", stdout);
  ios::sync_with_stdio(false);
  cin.tie(0);
  int n;
  cin >> n;
  vpi aa(n);
  for (int i = 0; i < n; i++) cin >> aa[i].first, aa[i].second = i;
  int P, Q;
  cin >> P >> Q;
  sor(aa);
  vl a(n + 1);
  for (int i = 0; i < n; i++) a[i + 1] = a[i] + aa[i].first;
  int minall = Big, minleft = Big, minright = Big;
  vpi able;
  for (int i = 0; i < n; i++) {
    int p = fstTrue(0, n - i - 1, [&](int x) {
      int l = x, r = n - i;
      ll s = a[r] - a[l];
      ll mx = a[r] - a[r - 1];
      // debug(l, r, s, mx, P, Q);
      if (s * P >= mx * Q * (r - l)) {
        return true;
      } else {
        return false;
      }
    });
    // debug(i, p);
    if (p == n - i) {
      continue;
    }
    int cnt = i + p;
    if (cnt > minall) continue;
    if (true) {
      int change = p + 1;
      int p2 = fstTrue(1, p, [&](int x) {
        int l = p, r = n - i;
        ll s = a[r] - a[l] + (a[x] - a[x - 1]) - (a[change] - a[change - 1]);
        ll mx = a[r] - a[r - 1];

        if (s * P >= mx * Q * (r - l)) {
          return true;
        } else {
          return false;
        }
      });
      p = p2 - 1;
    }
    if (cnt == minall) {
      // ckmin(minleft, p);
      // ckmin(minright, i);
      able.eb(p, n - i);
    }
    if (cnt < minall) {
      minall = cnt;
      able.clear();
      able.eb(p, n - i);
    }
  }
  debug(minall, minleft, minright);
  // if (n == 10) cout << minall << '\n';
  // cout << minleft + minright << '\n';
  vi dif(n + 1);
  for (auto &it : able) dif[it.first]++, dif[it.second]--;
  for (int i = 1; i < n; i++) dif[i] += dif[i - 1];
  vi ans;
  for (int i = 0; i < n; i++)
    if (!dif[i]) ans.eb(aa[i].second + 1);
  sor(ans);
  cout << sz(ans) << '\n';
  for (auto &x : ans) cout << x << ' ';
  return 0;
}

詳細信息

Test #1:

score: 0
Wrong Answer
time: 0ms
memory: 3564kb

input:

3
4
1 2 3 4
3 2
5
1 15 2 5 1
2 1
5
1 2 3 1000 10000
4 3

output:

3
1 2 3 

result:

wrong answer 1st numbers differ - expected: '0', found: '3'