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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#688304#7949. K-LotterytamthegodTL 1541ms79608kbC++235.5kb2024-10-30 02:45:092024-10-30 02:45:11

Judging History

你现在查看的是最新测评结果

  • [2024-10-30 02:45:11]
  • 评测
  • 测评结果:TL
  • 用时:1541ms
  • 内存:79608kb
  • [2024-10-30 02:45:09]
  • 提交

answer

#include<bits/stdc++.h>

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

#define pb push_back
#define fi first
#define se second
using namespace std;
using ll = long long;
using ld = long double;
using ull = unsigned long long;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int maxN = 1e6 + 5;
const int mod = 1e9 + 7;
const ll oo = 1e18;
int k, m, n;
int a[maxN];
vector<vector<int>> vc;
int id[maxN];
const int base = 2335;
int pw[maxN];
map<int, int> mp;
int inv[maxN];
int poww(int k, int n)
{
    int res = 1;
    while(n)
    {
        if(n & 1) res = (1ll * res * k) % mod;
        k = (1ll * k * k) % mod;
        n /= 2;
    }
    return res;
}

void ReadInput()
{
    pw[0] = 1;
    for(int i=1; i<maxN; i++)
        pw[i] = (1ll * pw[i - 1] * base) % mod;
    cin >> k >> m >> n;
    vc.resize(m + 5, vector<int> (k + 5));
    for(int i=1; i<=m; i++)
        for(int j=1; j<=k; j++)
            cin >> vc[i][j];
    for(int i=1; i<=m; i++)
    {
        for(int j=1; j<=k; j++)
            id[vc[i][j]] = j;
        int val = 0;
        for(int j=1; j<=k; j++)
            val = (val + 1ll * id[j] * pw[j - 1] % mod) % mod;
        mp[val] = i;
    }
    vector<pair<int, int>> val;
    for(int i=1; i<=n; i++)
    {
        cin >> a[i];
        val.pb({a[i], i});
    }

    sort(val.begin(), val.end());

    for(int i=1; i<=n; i++)
        a[val[i - 1].se] = i;
    int tmp = poww(base, mod - 2);
    inv[0] = 1;
    for(int i=1; i<=n; i++)
        inv[i] = (1ll * inv[i - 1] * tmp) % mod;
}
int st[4 * maxN], lazy[4 * maxN];
inline void refind(int id)
{

    st[id] = st[id * 2] + st[id * 2 + 1];
    if(st[id] >= mod) st[id] -= mod;
}
inline void down(int id)
{
    int t = lazy[id];
    if(!t) return;
    if(t > 0)
    {
        st[id * 2] = (1ll * st[id * 2] * pw[t]) % mod;
        st[id * 2 + 1] = (1ll * st[id * 2 + 1] * pw[t]) % mod;
    }
    else if(t < 0)
    {
        st[id * 2] = (1ll * st[id * 2] * inv[-t]) % mod;
        st[id * 2 + 1] = (1ll * st[id * 2 + 1] * inv[-t]) % mod;
    }
    lazy[id * 2] += t;
    lazy[id * 2 + 1] += t;
    lazy[id] = 0;
}
void update(int id, int l, int r, int pos, int val)
{
    if(l == r && l == pos)
    {
        st[id] = val;
        return;
    }
    down(id);
    int mid = (l + r) / 2;
    if(pos <= mid) update(id * 2, l, mid, pos, val);
    else update(id * 2 + 1, mid + 1, r, pos, val);
    refind(id);
}
void range_upd(int id, int l, int r, int u, int v, int val)
{
    if(l > v || r < u) return;
    if(l >= u && r <= v)
    {
        if(val > 0) st[id] = (1ll * st[id] * pw[val]) % mod;
        else st[id] = (1ll * st[id] * inv[-val]) % mod;
        lazy[id] += val;
        return;
    }
    int mid = (l + r) / 2;
    down(id);
    range_upd(id * 2, l, mid, u, v, val);
    range_upd(id * 2 + 1, mid + 1, r, u, v, val);
    refind(id);
}
int get(int id, int l, int r, int u, int v)
{
    if(l > v || r < u) return 0;
    if(l >= u && r <= v) return st[id];
    int mid = (l + r) / 2;
    down(id);
    auto L = get(id * 2, l, mid, u, v), R = get(id * 2 + 1, mid + 1, r, u, v);
    int val = L + R;
    if(val >= mod) val -= mod;
    return val;
}
int bit[maxN];
inline void update(int pos, int val)
{
    for(; pos <= n; pos += (pos & (-pos)))
        bit[pos] += val;
}
inline int get(int pos)
{
    int res = 0;
    for(; pos; pos -= (pos & (-pos)))
        res += bit[pos];
    return res;
}
bool chk(int id, int t)
{
    vector<int> tmp;
    for(int i=t-k+1; i<=t; i++)
        tmp.pb(a[i]);
    sort(tmp.begin(), tmp.end());
    vector<int> val;
    for(int i=t-k+1; i<=t; i++)
        val.pb(upper_bound(tmp.begin(), tmp.end(), a[i]) - tmp.begin());
    for(int i=1; i<=k; i++)
        if(val[i - 1] != vc[id][i]) return false;
    return true;
}
void Solve()
{
    int cur = 0;
    int tmp = 0;
    for(int i=0; i<k; i++)
    {
        tmp += pw[i];
        if(tmp >= mod) tmp -= mod;
    }
    for(int i=1; i<=n; i++)
    {
        if(i > k)
        {
            update(1, 1, n, a[i - k], 0);
            update(a[i - k], -1);

            if(a[i - k] < a[i]) range_upd(1, 1, n, a[i - k] + 1, a[i] - 1, -1);
            else if(a[i] - k > a[i]) range_upd(1, 1, n, a[i] + 1, a[i - k], 1);
            // range_upd(1, 1, n, a[i - k] + 1, n, -1);
        }
        update(a[i], 1);
        int val = get(a[i] - 1);
        if(i <= k)
            range_upd(1, 1, n, a[i] + 1, n, 1);
        update(1, 1, n, a[i], (1ll * i * pw[val]) % mod);
        int res = st[1];
        if(i >= k)
        {
            res -= cur;
            if(res < 0) res += mod;
            if(mp[res])
            {
                if(chk(mp[res], i))
                {
                    int i = mp[res];
                    for(int j=1; j<=k; j++)
                        cout << vc[i][j] << " ";
                    return;
                }
            }
            cur += tmp;
            if(cur >= mod) cur -= mod;
        }
    }
    //  cout << 1.0 * clock() / CLOCKS_PER_SEC;return;
    cout << 0;
}
#define taskname "sol"
int32_t main()
{
    if (fopen(taskname ".inp", "r"))
    {
        freopen(taskname ".inp", "r", stdin);
        //freopen(taskname ".out", "w", stdout);
    }
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    int T = 1;
    //cin >> T;
    for(int itest=1; itest<=T; itest++)
    {
        ReadInput();
        Solve();
    }
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 11792kb

input:

3 2 10
1 2 3
1 3 2
20 35 10 7 99 53 72 33 88 16

output:

1 3 2 

result:

ok single line: '1 3 2 '

Test #2:

score: 0
Accepted
time: 6ms
memory: 9856kb

input:

4 5 10
1 2 3 4
1 2 4 3
3 4 1 2
4 1 2 3
4 2 3 1
19 31 9 1 89 48 63 30 78 12

output:

4 2 3 1 

result:

ok single line: '4 2 3 1 '

Test #3:

score: 0
Accepted
time: 7ms
memory: 11880kb

input:

3 3 7
1 3 2
2 3 1
2 1 3
11 22 33 44 55 66 77

output:

0

result:

ok single line: '0'

Test #4:

score: 0
Accepted
time: 1541ms
memory: 79608kb

input:

10000 10 1000000
1 5001 2 5002 3 5003 4 5004 5 5005 6 5006 7 5007 8 5008 9 5009 10 5010 11 5011 12 5012 13 5013 14 5014 15 5015 16 5016 17 5017 18 5018 19 5019 20 5020 21 5021 22 5022 23 5023 24 5024 25 5025 26 5026 27 5027 28 5028 29 5029 30 5030 31 5031 32 5032 33 5033 34 5034 35 5035 36 5036 37 5...

output:

1 5001 2 5002 3 5003 4 5004 5 5005 6 5006 7 5007 8 5008 9 5009 10 5010 11 5011 12 5012 13 5013 14 5014 15 5015 16 5016 17 5017 18 5018 19 5019 20 5020 21 5021 22 5022 23 5023 24 5024 25 5025 26 5026 27 5027 28 5028 29 5029 30 5030 31 5031 32 5032 33 5033 34 5034 35 5035 36 5036 37 5037 38 5038 39 50...

result:

ok single line: '1 5001 2 5002 3 5003 4 5004 5 ...4998 9998 4999 9999 5000 10000 '

Test #5:

score: -100
Time Limit Exceeded

input:

10000 10 1000000
7171 4541 8189 3253 6694 2078 7384 1786 7847 5040 953 4126 4806 3532 7875 8531 3543 2706 8565 1509 2092 4125 6110 5251 6314 4574 6726 8900 9328 8639 3990 5234 9012 5023 3289 2825 8038 3593 2249 337 6252 3831 7967 3839 2815 540 3754 1009 8772 2939 2845 5067 6587 2615 375 7252 9940 18...

output:


result: