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#687660#9463. 基础 ABC 练习题HuTao0 0ms0kbC++142.9kb2024-10-29 20:17:272024-10-29 20:17:28

Judging History

你现在查看的是最新测评结果

  • [2024-10-29 20:17:28]
  • 评测
  • 测评结果:0
  • 用时:0ms
  • 内存:0kb
  • [2024-10-29 20:17:27]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int N = 62;

int n;
char s0[N], s1[N];
char s[N * 3];
unsigned f[N][N][N][4];

inline void Work()
{
    scanf("%d%s%s%s", &n, s0, s1, s + 1);
    // if(n != 60) return void(puts("-1"));
    for(int i = 0; i <= n; i ++ ) s0[i] ^= 48, s1[i] ^= 48;
    unsigned ans = 0;
    for(int x = 0; x <= n; x ++ )
        for(int y = 0; y <= n - x; y ++ )
        {
            if(!s0[x] || !s1[y]) continue;
            int z = n - x - y;
            // printf("*%d %d %d\n", x, y, z);
            memset(f, 0, sizeof f);
            f[0][0][0][!x << 1 | !y] = 1;
            int p = x - 1, q = y - 1;
            while(p >= 0 && !s0[p]) p -- ;
            while(q >= 0 && !s1[q]) q -- ;
            for(int i = 0; i <= n; i ++ )
                for(int j = 0; j <= min(n, i + y); j ++ )
                    for(int k = max(!i & !j, i - x); k <= min(n, j + z); k ++ )
                    {
                        if(i && (s[i + j + k] == 'A' || s[i + j + k] == '?'))
                        {
                            f[i][j][k][0] += f[i - 1][j][k][0];
                            f[i][j][k][1] += f[i - 1][j][k][1];
                            f[i][j][k][2] += f[i - 1][j][k][2];
                            f[i][j][k][3] += f[i - 1][j][k][3];
                        }
                        if(j && (s[i + j + k] == 'B' || s[i + j + k] == '?'))
                        {
                            f[i][j][k][0] += f[i][j - 1][k][0];
                            f[i][j][k][1] += f[i][j - 1][k][1];
                            f[i][j][k][2] += f[i][j - 1][k][2];
                            f[i][j][k][3] += f[i][j - 1][k][3];
                        }
                        if(k && (s[i + j + k] == 'C' || s[i + j + k] == '?'))
                        {
                            f[i][j][k][0] += f[i][j][k - 1][0];
                            f[i][j][k][1] += f[i][j][k - 1][1];
                            f[i][j][k][2] += f[i][j][k - 1][2];
                            f[i][j][k][3] += f[i][j][k - 1][3];
                        }
                        if(i - k > p)
                        {
                            f[i][j][k][2] += f[i][j][k][0];
                            f[i][j][k][3] += f[i][j][k][1];
                            f[i][j][k][0] = f[i][j][k][1] = 0;
                        }
                        if(j - i > q)
                        {
                            f[i][j][k][1] += f[i][j][k][0];
                            f[i][j][k][3] += f[i][j][k][2];
                            f[i][j][k][0] = f[i][j][k][2] = 0;
                        }
                        // printf("!%d %d %d\n", i, j, k);
                    }
            ans += f[n][n][n][3];
        }
    printf("%u\n", ans);
}

int main()
{
    int T;
    scanf("%d%*d", &T);
    while(T -- ) Work();
    return 0;
}

詳細信息

Subtask #1:

score: 0
Time Limit Exceeded

Test #1:

score: 0
Time Limit Exceeded

input:

60 1
1
11
11
ABC
2
111
111
CABABC
3
1111
1111
CAABBCBAC
4
11111
11111
BACBBACBACAC
5
111111
111111
CABCCBBAABCCBAA
6
1111111
1111111
ABABABCACBCBCCACBA
7
11111111
11111111
BCAABACBBCBBABCCAACAC
8
111111111
111111111
CCBCBBBCAABCBCAAAAACBCBA
9
1111111111
1111111111
CCCCACABCBABAABCCAABABBCBBA
10
1111...

output:


result:


Subtask #2:

score: 0
Skipped

Dependency #1:

0%

Subtask #3:

score: 0
Time Limit Exceeded

Test #22:

score: 0
Time Limit Exceeded

input:

60 3
1
11
11
???
2
111
111
??????
3
1111
1111
?????????
4
11111
11111
????????????
5
111111
111111
???????????????
6
1111111
1111111
??????????????????
7
11111111
11111111
?????????????????????
8
111111111
111111111
????????????????????????
9
1111111111
1111111111
???????????????????????????
10
1111...

output:


result:


Subtask #4:

score: 0
Skipped

Dependency #1:

0%

Subtask #5:

score: 0
Skipped

Dependency #1:

0%