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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#686832 | #9528. New Energy Vehicle | xianyu | RE | 1ms | 7708kb | C++14 | 1.4kb | 2024-10-29 15:56:45 | 2024-10-29 15:56:46 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n'
const int N=1e6+10,mod=998244353;
typedef pair<int,int>PII;
typedef pair<double,double>PDD;
int n,m,k;
int a[N];
PII b[N];
int s[N];
int pre[N];
void solve() {
cin>>n>>m;
int sum=0;
for(int i=1;i<=n;i++) {
cin>>a[i];
pre[i]=0;
sum+=a[i];
}
for(int i=1;i<=m;i++) {
cin>>b[i].first>>b[i].second;
}
if(b[1].first>sum) {
cout<<sum<<endl;
return;
}
int pos=0;
map<int,int>mp;
int qk=0;
int ans=0;
bool f=true;
for(int i=1;i<=m;i++) {
int len=b[i].first-b[i-1].first;
if(len>=a[b[i].second]) {
pre[a[b[i].second]]=-1;
if(qk+len>sum) {
ans=b[i].first+sum-qk;
f=false;
break;
}
qk+=len-a[b[i].second];
//cout<<qk<<endl;
}
else {
if(pre[a[b[i].second]]==-1){}
else qk-=a[b[i].second]-len;
pre[a[b[i].second]]=0;
qk=max(0LL,qk);
// cout<<qk<<endl;
}
}
//cout<<qk<<endl;
if(f)ans=b[m].first+sum-qk;
cout<<ans<<endl;
}
signed main() {
ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int T=1;
cin>>T;
while(T--) {
solve();
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 7708kb
input:
2 3 1 3 3 3 8 1 2 2 5 2 1 2 2 1
output:
12 9
result:
ok 2 lines
Test #2:
score: -100
Runtime Error
input:
6 3 2 2 2 2 6 1 7 1 2 2 3 3 2 1 6 2 2 3 2 2 5 1 7 2 9 1 2 2 3 3 2 1 6 2 1 1 999999999 1000000000 1 1 1 1000000000 1000000000 1