QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#686664 | #9528. New Energy Vehicle | comp_towels_cat | WA | 22ms | 6604kb | C++17 | 3.0kb | 2024-10-29 15:03:25 | 2024-10-29 15:03:26 |
Judging History
answer
#pragma GCC optimize(2)
#pragma GCC optimize(3,"Ofast","inline")
#include <bits/stdc++.h>
#define int long long
#define FOR(i, j, k) for(int i = (j);i <= (k);i ++)
#define ROF(i, j, k) for(int i = (j);i >= (k);i --)
#define For(i, j, k) for(int i = (j);i < (k);i ++)
#define Rof(i, j, k) for(int i = (j);i > (k);i --)
#define ull unsigned long long
#define PII pair<int,int>
#define ULL unsigned long long
#define db double
#define x first
#define y second
#define sp(x) fixed << setprecision(x)
#define all(x) x.begin(), x.end()
#define unq_all(x) x.erase(unique(all(x)), x.end())
#define M(x) x %= mod, x += mod, x %= mod
#define YES cout << "YES\n"
#define NO cout << "NO\n"
#define Yes cout << "Yes\n"
#define No cout << "No\n"
#define ANS cout << ans << '\n'
#define de(p) cout << #p << ' ' << p << '\n'
#define END(i, n) (i == n ? '\n' : ' ')
#define double long double
#define RED cout << "\033[91m"
#define GREEN cout << "\033[92m"
#define YELLOW cout << "\033[93m"
#define BLUE cout << "\033[94m"
#define MAGENTA cout << "\033[95m"
#define CYAN cout << "\033[96m"
#define RESET cout << "\033[0m"
// 红色
#define DEBUG1(x) \
RED; \
cout << #x << " : " << x << endl; \
RESET;
// 绿色
#define DEBUG2(x) \
GREEN; \
cout << #x << " : " << x << endl; \
RESET;
// 蓝色
#define DEBUG3(x) \
BLUE; \
cout << #x << " : " << x << endl; \
RESET;
// 品红
#define DEBUG4(x) \
MAGENTA; \
cout << #x << " : " << x << endl; \
RESET;
// 青色
#define DEBUG5(x) \
CYAN; \
cout << #x << " : " << x << endl; \
RESET;
// 黄色
#define DEBUG6(x) \
YELLOW; \
cout << #x << " : " << x << endl; \
RESET;
using namespace std;
const int N = 2e5 + 10, M = N * 2, INF = 1e9, mod = 998244353;
int n, m, k;
int a[N],x[N],t[N];
void solve()
{
cin >> n >> m;
FOR(i,1,n) cin >> a[i];
FOR(i,1,m) cin >> x[i] >> t[i];
int sum = 0;
int ans = 0;
FOR(i,1,n)
{
sum += a[i];
ans += a[i];
}
FOR(i,1,m)
{
int dis = x[i] - x[i - 1];
int tan = min(dis,a[t[i]]);
if (sum < dis)
{
break;
}
sum -= dis;
sum += tan;
ans += tan;
if (sum <= a[t[i]])
{
ans += a[t[i]] - sum;
sum = a[t[i]];
}
}
ANS;
}
signed main()
{
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
// auto t = clock();
int T = 1;
cin >> T;
while (T--)
{
solve();
}
// auto tt = clock();
// cout << "Time: " << 1000.0 * (tt - t) / CLOCKS_PER_SEC << "ms" << endl;
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 5692kb
input:
2 3 1 3 3 3 8 1 2 2 5 2 1 2 2 1
output:
12 9
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 5668kb
input:
6 3 2 2 2 2 6 1 7 1 2 2 3 3 2 1 6 2 2 3 2 2 5 1 7 2 9 1 2 2 3 3 2 1 6 2 1 1 999999999 1000000000 1 1 1 1000000000 1000000000 1
output:
9 11 4 11 999999999 2000000000
result:
ok 6 lines
Test #3:
score: -100
Wrong Answer
time: 22ms
memory: 6604kb
input:
10 230 8042 599 1039 69 1011 1366 824 14117 1523 806 5002 332 55 3769 996 359 1040 255 1135 3454 3609 6358 2509 3695 8785 3890 1304 3394 14611 33 89 2245 508 22 1043 10411 628 1279 714 903 585 7413 5099 845 148 4689 2110 8683 1613 143 3263 2599 110 244 3297 4742 1571 425 1822 15692 572 9397 328 1691...
output:
1464182 1555488 1235985 1503214 1488630 1544454 806511 1519932 875544 803942
result:
wrong answer 1st lines differ - expected: '1543020', found: '1464182'