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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#682845#9521. Giving Directions in Harbinhos_lyricAC ✓9ms4088kbC++141.9kb2024-10-27 17:33:272024-10-27 17:33:28

Judging History

你现在查看的是最新测评结果

  • [2024-10-27 17:33:28]
  • 评测
  • 测评结果:AC
  • 用时:9ms
  • 内存:4088kb
  • [2024-10-27 17:33:27]
  • 提交

answer

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <algorithm>
#include <bitset>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using namespace std;

using Int = long long;

template <class T1, class T2> ostream &operator<<(ostream &os, const pair<T1, T2> &a) { return os << "(" << a.first << ", " << a.second << ")"; };
template <class T> ostream &operator<<(ostream &os, const vector<T> &as) { const int sz = as.size(); os << "["; for (int i = 0; i < sz; ++i) { if (i >= 256) { os << ", ..."; break; } if (i > 0) { os << ", "; } os << as[i]; } return os << "]"; }
template <class T> void pv(T a, T b) { for (T i = a; i != b; ++i) cerr << *i << " "; cerr << endl; }
template <class T> bool chmin(T &t, const T &f) { if (t > f) { t = f; return true; } return false; }
template <class T> bool chmax(T &t, const T &f) { if (t < f) { t = f; return true; } return false; }
#define COLOR(s) ("\x1b[" s "m")


int N;
vector<char> C;
vector<int> X;

int main() {
  for (int numCases; ~scanf("%d", &numCases); ) { for (int caseId = 1; caseId <= numCases; ++caseId) {
    scanf("%d", &N);
    C.resize(N);
    X.resize(N);
    for (int i = 0; i < N; ++i) {
      scanf(" %c%d", &C[i], &X[i]);
    }
    
    printf("%d %c\n", 2*N - 1, C[0]);
    for (int i = 0; i < N; ++i) {
      if (i) {
        const string S = "ENWS";
        const int g = S.find(C[i - 1]);
        const int h = S.find(C[i]);
       const int d = (h - g) & 3;
        assert(d == 1 || d == 3);
        puts((d == 1) ? "L" : "R");
      }
      printf("Z %d\n", X[i]);
    }
  }
#ifndef LOCAL
  break;
#endif
  }
  return 0;
}

这程序好像有点Bug,我给组数据试试?

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3788kb

input:

1
2
S 2
E 1

output:

3 S
Z 2
L
Z 1

result:

ok ok (1 test case)

Test #2:

score: 0
Accepted
time: 0ms
memory: 4088kb

input:

99
4
E 6
N 1
W 2
S 8
8
W 10
N 1
E 10
S 2
E 2
N 2
W 2
S 1
9
N 5
E 4
N 7
E 6
S 9
E 8
N 4
W 6
N 7
6
N 6
E 6
N 8
W 9
S 7
E 2
8
E 6
S 9
W 5
S 4
W 6
N 4
E 5
N 9
8
N 6
W 10
N 6
W 6
S 6
E 6
S 6
E 10
10
N 7
W 3
N 5
W 5
S 8
W 10
N 6
E 9
N 8
E 8
8
W 9
N 10
E 6
S 10
E 9
S 10
W 6
N 10
4
W 5
N 1
E 5
S 1
4
W 4
S 8...

output:

7 E
Z 6
L
Z 1
L
Z 2
L
Z 8
15 W
Z 10
R
Z 1
R
Z 10
R
Z 2
L
Z 2
L
Z 2
L
Z 2
L
Z 1
17 N
Z 5
R
Z 4
L
Z 7
R
Z 6
R
Z 9
L
Z 8
L
Z 4
L
Z 6
R
Z 7
11 N
Z 6
R
Z 6
L
Z 8
L
Z 9
L
Z 7
L
Z 2
15 E
Z 6
R
Z 9
R
Z 5
L
Z 4
R
Z 6
R
Z 4
R
Z 5
L
Z 9
15 N
Z 6
L
Z 10
R
Z 6
L
Z 6
L
Z 6
L
Z 6
R
Z 6
L
Z 10
19 N
Z 7
L
Z 3
R
Z 5
...

result:

ok ok (99 test cases)

Test #3:

score: 0
Accepted
time: 9ms
memory: 3792kb

input:

10000
1
W 9
1
N 3
10
W 10
N 7
W 5
S 9
W 9
S 8
E 9
S 6
E 5
S 5
2
E 8
S 10
2
N 7
W 5
5
S 4
W 3
S 7
E 4
N 7
8
N 7
E 8
N 3
E 9
S 5
W 5
S 9
W 10
9
W 9
S 6
E 6
N 8
W 5
N 6
W 3
N 8
W 7
3
S 9
W 2
N 10
5
N 6
E 4
N 6
E 10
N 1
10
S 7
W 4
N 3
E 5
S 7
W 8
N 2
E 8
N 4
W 8
8
S 9
W 1
N 4
E 6
N 1
W 8
N 6
W 6
4
W 10
...

output:

1 W
Z 9
1 N
Z 3
19 W
Z 10
R
Z 7
L
Z 5
L
Z 9
R
Z 9
L
Z 8
L
Z 9
R
Z 6
L
Z 5
R
Z 5
3 E
Z 8
R
Z 10
3 N
Z 7
L
Z 5
9 S
Z 4
R
Z 3
L
Z 7
L
Z 4
L
Z 7
15 N
Z 7
R
Z 8
L
Z 3
R
Z 9
R
Z 5
R
Z 5
L
Z 9
R
Z 10
17 W
Z 9
L
Z 6
L
Z 6
L
Z 8
L
Z 5
R
Z 6
L
Z 3
R
Z 8
L
Z 7
5 S
Z 9
R
Z 2
R
Z 10
9 N
Z 6
R
Z 4
L
Z 6
R
Z 10
L
...

result:

ok ok (10000 test cases)

Extra Test:

score: 0
Extra Test Passed