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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#680775#7736. Red Black TreeYoralenTL 0ms5852kbC++141.5kb2024-10-26 22:38:502024-10-26 22:38:56

Judging History

你现在查看的是最新测评结果

  • [2024-10-26 22:38:56]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:5852kb
  • [2024-10-26 22:38:50]
  • 提交

answer

#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
const int N=100005;
struct edge{int to,next;}w[N<<1];
int n,h[N],cnt,T,a[N],ar[N];
char s[N];
void Add(int x,int y){
    w[++cnt].to=y,w[cnt].next=h[x],h[x]=cnt;
}
int hd[N],ng[N],ans[N],sv[N];
struct Dlt{
	vector<int>ng,ps;
	int no=0,sg=0;
	void Init(){
		ng.clear();ps.clear();
		no=sg=0;
	}
	int val(int k){
		if(k<=ng.size())return ng[k-1];
		else if(k<=ng.size()+no)return 0;
		else return ps[ps.size()-(k-ng.size()-no)];
	}
	void Ins(int v){
		if(v<0)ng.push_back(v),sg+=v;
		if(v==0)no++;
		if(v>0)ps.push_back(v);
	}
	int size(){
		return ng.size()+no+ps.size();
	}
};
Dlt DFS(int u){
    int i,j,ln;hd[u]=a[u];
    Dlt S,F;S.Init();
    for(i=h[u];i;i=w[i].next){
        int e=w[i].to;
        F=DFS(e);hd[u]+=hd[e];
        if(!S.size())S=F,ln=F.size();
        else{
        	ln=min(ln,F.size());
        	for(j=1;j<=ln;j++)ar[j]=S.val(j)+F.val(j);
        	S.Init();int pl=1,pr=ln;
        	while(ar[pl]<0&&pl<=ln)S.Ins(ar[pl]),pl++;
        	while(ar[pr]>0&&pr>=1)S.Ins(ar[pr]),pr--;
        	S.no=pr-pl+1;
        }
    }
    if(a[u]==0)S.Ins(1);else S.Ins(-1);
    ans[u]=hd[u]+S.sg;return move(S);
}
int main(){
    int i,x;
    scanf("%d",&T);
    while(T--){
        scanf("%d",&n);scanf("%s",s+1);cnt=0;
        for(i=1;i<=n;i++)a[i]=s[i]-'0',h[i]=ng[i]=ans[i]=hd[i]=0;
        for(i=2;i<=n;i++)scanf("%d",&x),Add(x,i);DFS(1);
        for(i=1;i<=n;i++)printf("%d ",ans[i]);putchar('\n');
    }
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 5852kb

input:

2
9
101011110
1 1 3 3 3 6 2 2
4
1011
1 1 3

output:

4 1 2 0 0 0 0 0 0 
2 0 0 0 

result:

ok 2 lines

Test #2:

score: -100
Time Limit Exceeded

input:

6107
12
000000001000
1 2 3 2 5 4 4 7 3 8 11
19
1100111101111011110
1 2 1 1 4 5 2 4 3 2 2 7 10 2 11 3 15 5
7
0111110
1 1 2 2 1 5
3
000
1 1
7
1000011
1 2 3 3 5 4
7
0001001
1 1 1 3 5 3
8
00111000
1 1 3 2 5 2 7
11
11111110111
1 1 1 4 5 4 5 2 5 1
15
110101101000010
1 2 3 2 1 5 2 5 6 5 8 7 9 14
10
0101000...

output:

1 1 1 1 0 0 0 0 0 0 0 0 
6 2 0 1 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
1 0 0 0 0 0 0 
0 0 0 
0 0 0 0 0 0 0 
2 0 1 0 0 0 0 
2 1 0 0 0 0 0 0 
4 0 0 2 1 0 0 0 0 0 0 
4 3 0 0 2 0 0 0 0 0 0 0 0 0 0 
2 0 1 0 0 0 0 0 0 0 
6 5 0 1 0 0 0 0 0 0 0 1 0 0 0 0 0 
1 1 0 0 0 
5 1 0 1 0 0 0 0 0 0 0 0 0 0 
1 0 0 0 0 0 0 0 0...

result: