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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#680365#5141. Identical ParityxyzWA 31ms3592kbC++232.2kb2024-10-26 20:50:452024-10-26 20:50:46

Judging History

你现在查看的是最新测评结果

  • [2024-10-26 20:50:46]
  • 评测
  • 测评结果:WA
  • 用时:31ms
  • 内存:3592kb
  • [2024-10-26 20:50:45]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

long long exgcd(long long a, long long b, long long &u, long long &v) { //返回gcd(a,b) 并求出解(引用带回)
	if (b == 0) {
		u = 1, v = 0;
		return a;
	}
	long long x1, y1, gcd;
	gcd = exgcd(b, a % b, x1, y1);
	u = y1, v = 1ll * x1 - 1ll * a / b * y1;
	return gcd;
}

int main() {
	int t;
	cin >> t;
	while (t--) {
		long long n, k;
		cin >> n >> k;
		long long x = n / k, y = n % k;
		long long a, b;
		a = 2 * x + 2, b = 2 * x;
		long long u, v;
		if (n % 2 == 0) {
			long long c = 1ll * k * x + y;
			long long g = __gcd(a, b);
			if (c % g != 0) {
				cout << "No" << endl;
				continue;
			}
			exgcd(a, b, u, v);
			u = 1ll * u * c / g, v = 1ll * v * c / g;
			long long t1 = b / g, t2 = a / g;

			long long k1min = -u / t1, k1max = (y - u) / t1;
			if (k1min == k1max && !(t1 * k1min + u >= 0 && t1 * k1min + u <= y)) {
				cout << "No" << endl;
				continue;
			}
			long long k2min = (v + y - k) / t2, k2max = v / t2;
			if (k2min == k2max && !(v - k2min * t2 >= 0 && y - k2min * t2 <= k - y)) {
				cout << "No" << endl;
				continue;
			}
			if (k1max >= k2min && k2max >= k1min) {
				cout << "Yes" << endl;
				continue;
			}
			if (k2max >= k1min && k1max >= k2min) {
				cout << "Yes" << endl;
				continue;
			}
			cout << "No" << endl;
		} else {
			long long c = 1ll * k * x + y - 1;
			long long g = __gcd(a, b);
			if (c % g != 0) {
				cout << "No" << endl;
				continue;
			}
			exgcd(a, b, u, v);
			u = 1ll * u * c / g, v = 1ll * v * c / g;
			long long t1 = b / g, t2 = a / g;

			long long k1min = -u / t1, k1max = (y - u) / t1;
			if (k1min == k1max && !(t1 * k1min + u >= 0 && t1 * k1min + u <= y)) {
				cout << "No" << endl;
				continue;
			}
			long long k2min = (v + y - k) / t2, k2max = v / t2;
			if (k2min == k2max && !(v - k2min * t2 >= 0 && y - k2min * t2 <= k - y)) {
				cout << "No" << endl;
				continue;
			}
			if (k1max >= k2min && k2max >= k1min) {
				cout << "Yes" << endl;
				continue;
			}
			if (k2max >= k1min && k1max >= k2min) {
				cout << "Yes" << endl;
				continue;
			}
			cout << "No" << endl;
		}
	}
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3552kb

input:

3
3 1
4 2
5 3

output:

No
Yes
Yes

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 31ms
memory: 3592kb

input:

100000
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
6 1
6 2
6 3
6 4
6 5
6 6
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11 8
11 9
11 10
11 11
12 1
...

output:

Yes
No
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
...

result:

wrong answer expected YES, found NO [24th token]