QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#680347#5141. Identical ParityxyzWA 47ms3632kbC++232.3kb2024-10-26 20:47:402024-10-26 20:47:42

Judging History

你现在查看的是最新测评结果

  • [2024-10-26 20:47:42]
  • 评测
  • 测评结果:WA
  • 用时:47ms
  • 内存:3632kb
  • [2024-10-26 20:47:40]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

long long exgcd(long long a, long long b, long long &u, long long &v) { //返回gcd(a,b) 并求出解(引用带回)
	if (b == 0) {
		u = 1, v = 0;
		return a;
	}
	long long x1, y1, gcd;
	gcd = exgcd(b, a % b, x1, y1);
	u = y1, v = 1ll * x1 - 1ll * a / b * y1;
	return gcd;
}

int main() {
	int t;
	cin >> t;
	while (t--) {
		long long n, k;
		cin >> n >> k;
		long long x = n / k, y = n % k;
		long long a, b;
		a = 2 * x + 2, b = 2 * x;
		long long u, v;
		if (n % 2 == 0) {
			long long c = 1ll * k * x + y;
			if (c % a == 0 || c % b == 0) {
				cout << "Yes" << endl;
				continue;
			}
			long long g = __gcd(a, b);
			if (c % g != 0) {
				cout << "No" << endl;
				continue;
			}
			exgcd(a, b, u, v);
			u = 1ll * u * c / g, v = 1ll * v * c / g;
			long long t1 = b / g, t2 = a / g;

			long long k1min = -u / t1, k1max = (y - u) / t1;
			if (k1min == k1max && !(t1 * k1min + u >= 0 && t1 * k1min + u <= y)) {
				cout << "No" << endl;
				continue;
			}
			long long k2min = (v + y - k) / t2, k2max = v / t2;
			if (k2min == k2max && !(v - k2min * t2 >= 0 && y - k2min * t2 <= k - y)) {
				cout << "No" << endl;
				continue;
			}
			if (k1max >= k2min && k2max >= k1min) {
				cout << "Yes" << endl;
				continue;
			}
			if (k2max >= k1min && k1max >= k2min) {
				cout << "Yes" << endl;
				continue;
			}
			cout << "No" << endl;
		} else {
			long long c = 1ll * k * x + y - 1;
			if (c % a == 0 || c % b == 0) {
				cout << "Yes" << endl;
				continue;
			}
			long long g = __gcd(a, b);
			if (c % g != 0) {
				cout << "No" << endl;
				continue;
			}
			exgcd(a, b, u, v);
			u = 1ll * u * c / g, v = 1ll * v * c / g;
			long long t1 = b / g, t2 = a / g;

			long long k1min = -u / t1, k1max = (y - u) / t1;
			if (k1min == k1max && !(t1 * k1min + u >= 0 && t1 * k1min + u <= y)) {
				cout << "No" << endl;
				continue;
			}
			long long k2min = (v + y - k) / t2, k2max = v / t2;
			if (k2min == k2max && !(v - k2min * t2 >= 0 && y - k2min * t2 <= k - y)) {
				cout << "No" << endl;
				continue;
			}
			if (k1max >= k2min && k2max >= k1min) {
				cout << "Yes" << endl;
				continue;
			}
			if (k2max >= k1min && k1max >= k2min) {
				cout << "Yes" << endl;
				continue;
			}
			cout << "No" << endl;
		}
	}
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3628kb

input:

3
3 1
4 2
5 3

output:

No
Yes
Yes

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 47ms
memory: 3632kb

input:

100000
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
6 1
6 2
6 3
6 4
6 5
6 6
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11 8
11 9
11 10
11 11
12 1
...

output:

Yes
No
Yes
No
Yes
Yes
No
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
Yes
No
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
Yes
No
...

result:

wrong answer expected NO, found YES [18th token]