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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#678569 | #5465. Maximum GCD | A_R_Adnan | WA | 0ms | 3736kb | C++14 | 7.7kb | 2024-10-26 15:23:36 | 2024-10-26 15:23:38 |
Judging History
answer
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define pbds tree<ll, null_type, less_equal<ll>, rb_tree_tag, tree_order_statistics_node_update>
// A.order_of_key(x) *A.find_by_order(x)
// less->sorted in ascending order and unique, greater->sorted in descending order and unique
// less_equal-> it will work as multiset and in ascending order, greater_equal->same as multiset in descending order
typedef unsigned long long ull;
#define ld long double
typedef long long ll;
#define vi vector<int>
#define vll vector<long long>
#define pii pair<int, int>
#define pll pair<ll, ll>
#define vpll vector<pll>
#define F first
#define S second
#define CY cout << "YES\n";
#define CN cout << "NO\n";
#define forr(v, n) \
vll v(n); \
for (int i = 0; i < n; i++) \
{ \
cin >> v[i]; \
}
#define rall(x) (x).rbegin(), (x).rend()
#define all(x) (x).begin(), (x).end()
#define sz(s) ((int)((s).size()))
#define torad(x) (x) * ((2 * acos(0)) / 180.0)
#define ite vector<int>::iterator
#define print(a) \
for (auto v : a) \
cout << v << " "; \
cout << "\n";
#define ASSALAMU_ALAIKOM \
ios_base::sync_with_stdio(0); \
cin.tie(0); \
cout.tie(0);
#define pb push_back
const ll inf = 1e18;
const ll minf = -1e18;
const ll mod = 1e9 + 7;
#define eps 1e-12
const double PI = acos(-1);
#define fit for (auto u : (x))
#define Max(x) *max_element(all(x))
#define Min(x) *min_element(all(x))
#define PI 2 * acos(0)
#define pob pop_back
#define set_bits(n) __builtin_popcountll(n)
// set_intersection(all(v1), all(v2), back_inserter(v));
// set_union(all(v1), all(v2), back_inserter(v));
// set_difference(all(v1), all(v2), back_inserter(v));
#define endl '\n'
// a%m is equivalent to ((a%m)+m)%m -->(it will work for both negative and positive value)
ll modulo(ll a, ll b)
{
return ((a % b) + b) % b;
}
ll log_a_to_base_b(ll a, ll b)
{
return log2(a) / log2(b);
}
void printBinary(ll num)
{
for (ll i = 63; i >= 0; i--)
cout << ((num >> i) & 1);
cout << endl;
}
bool power_of_2(ll x)
{
return x && !(x & (x - 1));
}
#define endl '\n'
ll GCD(ll x, ll y)
{
if (y == 0)
return x;
else
return GCD(y, x % y);
}
ll LCM(ll x, ll y)
{
return (x * y / (GCD(x, y)));
}
ll power(ll a, ll n)
{
ll ans = 1;
while (n)
{
if (n & 1)
{
ans = ans * a;
n--;
}
a *= a;
n /= 2;
}
return ans;
}
ll modpower(ll a, ll n, ll mod)
{
ll ans = 1;
while (n)
{
if (n & 1)
{
ans = ((ans % mod) * (a % mod)) % mod;
n--;
}
a = ((a % mod) * (a % mod)) % mod;
n /= 2;
}
return ans;
}
ll inverse(ll a, ll p)
{
return modpower(a, p - 2, p);
}
vector<bool> Sieve(ll n)
{
vector<bool> prime(n + 1, true);
for (ll p = 2; p * p <= n; p++)
{
if (prime[p] == true)
{
for (ll i = p * p; i <= n; i += p)
prime[i] = false;
}
}
return prime;
}
vll p_list;
vector<ll> sieve(ll n)
{
vector<bool> prime(n + 1, true);
for (ll p = 2; p * p <= n; p++)
{
if (prime[p] == true)
{
for (ll i = p * p; i <= n; i += p)
prime[i] = false;
}
}
for (ll i = 2; i <= n; i++)
{
if (prime[i])
p_list.pb(i);
}
return p_list;
}
vector<vll> adj;
vll vis, color;
void dfs(ll node)
{
vis[node] = 1;
cout << node << " ";
for (auto child : adj[node])
{
if (!vis[child])
dfs(child);
}
}
bool Is_Bipartite(ll node, ll clr)
{
vis[node] = 1;
color[node] = clr;
for (auto child : adj[node])
{
if (!vis[child] && Is_Bipartite(child, clr ^ 1) == false)
return false;
else if (color[node] == color[child])
return false;
}
return true;
}
bool Cycle(ll node, ll par)
{
vis[node] = 1;
for (auto child : adj[node])
{
if (!vis[child] && Cycle(child, node))
return true;
else if (child != par)
return true;
}
return false;
}
vll Sub_sz;
ll Sub_Tree_Sz(ll node)
{
ll curr_sz = 1;
vis[node] = 1;
for (auto child : adj[node])
{
if (!vis[child])
curr_sz += Sub_Tree_Sz(child);
}
Sub_sz[node] = curr_sz;
return curr_sz;
}
void bfs(ll s)
{
queue<ll> q;
vis[s] = 1;
q.push(s);
while (!q.empty())
{
ll x = q.front();
cout << x << " ";
q.pop();
for (auto child : adj[x])
{
if (!vis[child])
{
vis[child] = 1;
q.push(child);
}
}
}
}
#ifndef ONLINE_JUDGE
#define dbg(x) \
cerr << #x << " "; \
_print(x); \
cerr << endl;
#else
#define dbg(x)
#endif
void _print(ll t) { cerr << t; }
void _print(int t) { cerr << t; }
void _print(string t) { cerr << t; }
void _print(char t) { cerr << t; }
void _print(ld t) { cerr << t; }
void _print(double t) { cerr << t; }
void _print(ull t) { cerr << t; }
template <class T, class V>
void _print(pair<T, V> p);
template <class T>
void _print(vector<T> v);
template <class T>
void _print(set<T> v);
template <class T, class V>
void _print(map<T, V> v);
template <class T>
void _print(multiset<T> v);
template <class T, class V>
void _print(pair<T, V> p)
{
cerr << "{";
_print(p.F);
cerr << ",";
_print(p.S);
cerr << "}";
}
template <class T>
void _print(vector<T> v)
{
cerr << "[ ";
for (T i : v)
{
_print(i);
cerr << " ";
}
cerr << "]";
}
template <class T>
void _print(set<T> v)
{
cerr << "[ ";
for (T i : v)
{
_print(i);
cerr << " ";
}
cerr << "]";
}
template <class T>
void _print(multiset<T> v)
{
cerr << "[ ";
for (T i : v)
{
_print(i);
cerr << " ";
}
cerr << "]";
}
template <class T, class V>
void _print(map<T, V> v)
{
cerr << "[ ";
for (auto i : v)
{
_print(i);
cerr << " ";
}
cerr << "]";
}
int double_comp(double a, double b)
{
if (fabs(a - b) <= eps)
return 0;
else
return a < b ? -1 : 1;
}
int main()
{
// #ifndef ONLINE_JUDGE
// freopen("E:\\VS_C++\\input.txt", "r", stdin);
// freopen("E:\\VS_C++\\output.txt", "w+", stdout);
// freopen("E:\\VS_C++\\Erron.txt", "w", stderr);
// #endif
ASSALAMU_ALAIKOM
ll t,i,j,ans,f=0,x;
vll div;
cin >> t;
forr(v, t);
sort(all(v));
x = v[0];
for (i = 1; i <= sqrt(x); i++)
{
if (x % i == 0)
div.pb(x / i);
}
for (i = 0; i < sz(div); i++)
{
ans = div[i];
for (j=1; j < t; j++)
{
if (v[j] % ans == 0)
continue;
if (v[j] >= ans * ans)
{
f = 1;
break;
}
else
break;
}
if (f || j >= t)
break;
}
if (f || j >= t)
cout << ans << endl;
else
{
x = ceil(v[0] / 2.0);
for (i = x; i > 1; i--)
{
for (; j < t; j++)
{
if (v[j] >= i * i)
{
f = 1;
break;
}
if (v[j] % i == 0)
continue;
else
{
x = v[j] % (v[j] - i);
if (x == i)
continue;
else
break;
}
}
if (f || j >= t)
break;
}
cout << i << endl;
}
return 0;
}
详细
Test #1:
score: 0
Wrong Answer
time: 0ms
memory: 3736kb
input:
3 3 10 7
output:
2
result:
wrong answer 1st numbers differ - expected: '3', found: '2'