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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#676821 | #906. 强连通分量 | lsj2009 | WA | 1ms | 5964kb | C++20 | 1.9kb | 2024-10-26 01:04:31 | 2024-10-26 01:04:31 |
Judging History
answer
#include<bits/stdc++.h>
//#pragma GCC optimize(3,"Ofast","inline")
//#define int long long
#define i128 __int128
#define ll long long
#define ull unsigned long long
#define uint unsigned int
#define ld double
#define PII pair<int,int>
#define INF 0x3f3f3f3f
#define INFLL 0x3f3f3f3f3f3f3f3f
#define chkmax(a,b) a=max(a,b)
#define chkmin(a,b) a=min(a,b)
#define rep(k,l,r) for(int k=l;k<=r;++k)
#define per(k,r,l) for(int k=r;k>=l;--k)
#define cl(f,x) memset(f,x,sizeof(f))
#define pcnt(x) __builtin_popcount(x)
#define lg(x) (31-__builtin_clz(x))
using namespace std;
void file_IO() {
// system("fc .out .ans");
freopen(".in","r",stdin);
freopen(".out","w",stdout);
}
bool M1;
const int N=5e5+5;
int head[N],len;
struct node {
int to,nxt;
}; node edge[N];
void add_edge(int u,int v) {
edge[++len]={v,head[u]}; head[u]=len;
}
int dfn[N],low[N],p;
vector<vector<int>> vec;
stack<int> st;
bool inst[N];
void tarjan(int u) {
low[u]=dfn[u]=++p;
st.push(u);
inst[u]=true;
for(int i=head[u];i;i=edge[i].nxt) {
int v=edge[i].to;
if(!dfn[v]) {
tarjan(v);
chkmin(low[u],low[v]);
} else if(inst[v])
chkmin(low[u],dfn[v]);
}
if(low[u]==dfn[u]) {
vector<int> t;
int x=0;
while(x!=u) {
x=st.top(); st.pop();
inst[x]=false;
t.push_back(x);
}
vec.push_back(t);
}
}
void solve() {
int n,m;
scanf("%d%d",&n,&m);
while(m--) {
int u,v;
scanf("%d%d",&u,&v);
++u; ++v;
add_edge(u,v);
}
rep(i,1,n) {
if(!dfn[i])
tarjan(i);
}
printf("%d\n",(int)vec.size());
for(auto x:vec) {
printf("%d ",(int)x.size());
for(auto u:x)
printf("%d ",u-1);
puts("");
}
}
bool M2;
signed main() {
//file_IO();
int testcase=1;
//scanf("%d",&testcase);
while(testcase--)
solve();
fprintf(stderr,"used time = %ldms\n",1000*clock()/CLOCKS_PER_SEC);
fprintf(stderr,"used memory = %lldMB\n",(&M2-&M1)/1024/1024);
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 1ms
memory: 5964kb
input:
6 7 1 4 5 2 3 0 5 5 4 1 0 3 4 2
output:
4 2 3 0 1 2 2 4 1 1 5
result:
wrong answer 5 is later than 2, but there is an edge (5, 2)