#include<iostream>
#include<vector>
#include<cstring>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<string.h>
#include <string>
#include<math.h>
#include<set>
#include<unordered_map>
#include<unordered_set>
#include<map>
#include<queue>
#include<stack>
#include<functional>
using namespace std;
#define IOS ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define int long long
#define inf 1e18
const int N = 1e5+7;
const int M = 205;
const int mod = 1e9 + 7;
const int di[4][2] = { {1,0}, { -1,0 } ,{ 0,1 },{0,-1} };//下上右左
struct node
{
	int s;
	vector<int>x;
	vector<int>y;
	bool op = 0;
}; 
bool cmp(node a, node b)
{
	return a.s > b.s;
}
void solve()
{
	int n, m;
	cin >> n >> m;
	vector<vector<int>>a(n + 2, vector<int>(m + 2, 0));
	vector<vector<bool>>vi(n + 2, vector<bool>(m + 2, 0));
	vector<node>tu(1);
	int cntqq = 0;
	function<int(int, int)>check = [&](int x, int y)->int
		{
			for (int i = 0; i < 4; i++)
					if (a[x+di[i][0]][y+di[i][1]])return a[x+di[i][0]][y+di[i][1]];
			return 0;
		};
	//连通块
	function<bool(int, int,int,int,int,int)>dfs = [&](int x1, int y1,int x2,int y2,int dx,int dy)->bool
		{
			if (a[x1 + dx][y1 + dy] == 0)
			{
				return true;//没有包含关系
			}
			vi[x2+dx][y2+dy] = 1;
			for (int i = 0; i < 4; i++)
			{
				if (a[x2 + dx + di[i][0]][y2 + dy + di[i][1]] != 0 && vi[x2 + dx + di[i][0]][y2 + dy + di[i][1] ]!= 1)
					if(dfs(x1, y1, x2, y2, dx + di[i][0], dy + di[i][1]))return true;
			}
			vi[x2 + dx][y2 + dy] = 0;
			return false;
		};
	for(int i = 1;i<=n;i++)
	{
		for (int j = 1; j <= m; j++)
		{
			char tp;
			cin >> tp;
			if (tp == '.')
			{
				int tp = check(i, j);
				if (tp)//老连通块
				{
					a[i][j] = tp;
					tu[tp].s++;
					tu[tp].x.push_back(i);
					tu[tp].y.push_back(j);
				}
				else//新连通块
				{
					node tp;
					tp.x.push_back(i), tp.y.push_back(j);
					tp.s = 1;
					tu.push_back(tp);
					a[i][j] = ++cntqq;
				}
			}
		}
	}//连通块
	sort(tu.begin() + 1, tu.end(), cmp);
	function<int(node, node)>work = [&](node a, node b)->int
		{
			for (int i = 0; i < a.x.size(); i++)
			{
				int x1 = a.x[i], y1 = a.y[i];
				
				int x2 = b.x[0], y2 = b.y[0];
				if (!dfs(x1, y1, x2, y2, 0, 0))
				{
					if (a.s == b.s)return 2;//两个都不行
					else return 1;//小的不行
				}
			}
			return 0;//无所谓
		};
	for (int i = 1; i <= cntqq; i++)
	{
		if (tu[i].op)continue;

		for (int j = i+1; j <= cntqq; j++)
		{
			int oo = work(tu[i], tu[j]);
			if (oo == 1)tu[j].op = 1;
			else if (oo == 2)tu[i].op = tu[j].op = 1;
		}
	}
	int sum = 0;
	for (int i = 1; i <= cntqq; i++)
	{
		if (!tu[i].op)sum += tu[i].s;
	}
	cout << sum << endl;
}

signed main()
{
	int T = 1;
	cin >> T;
	while (T--)
	{
		solve();
	}
	return 0;
}