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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#674531#7949. K-LotteryAestivateTL 1226ms152624kbC++205.9kb2024-10-25 16:18:302024-10-25 16:18:31

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你现在查看的是最新测评结果

  • [2024-10-25 16:18:31]
  • 评测
  • 测评结果：TL
  • 用时：1226ms
  • 内存：152624kb
查看
  • [2024-10-25 16:18:30]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;

#define ll long long 
#define pb push_back
#define F first 
#define S second
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx,popcnt,sse4,abm")
#pragma GCC optimize("Ofast","inline","-ffast-math")
#pragma GCC target("avx,sse2,sse3,sse4,mmx")
const ll mol=1e9+7, mol2=998244353;

const int N = 1e6+5;
ll inv[N], po[N];
ll inv2[N], po2[N];
struct Seg{
    ll seg[N*4]={0},la[N*4]={0}, seg3[N*4];
    int seg2[N*4];

    void init(int n){
        for(int i=1;i<=n*4;i++) seg[i]=0, la[i]=0, seg2[i]=0, seg3[i]=0;
    }
    void push(int ind){
        int t=la[ind];la[ind]=0;
        la[ind*2]+=t,la[ind*2+1]+=t,seg[ind*2]*=inv[t],seg[ind*2+1]*=inv[t],seg3[ind*2]*=inv2[t],seg3[ind*2+1]*=inv2[t];
        seg[ind*2]%=mol, seg[ind*2+1]%=mol;
        seg3[ind*2]%=mol2, seg3[ind*2+1]%=mol2;
    }
    void upd(int l,int r,int l1,int r1,int val,int ind){
        if(l1<=l&&r<=r1) {
            seg[ind]*=inv[val], seg[ind]%=mol;
            seg3[ind]*=inv2[val], seg3[ind]%=mol2;
            la[ind]+=val;
            return;
        }
        int mid=l+r>>1;
        if(la[ind]) push(ind);
        if(r1<=mid) upd(l,mid,l1,r1,val,ind*2);
        else if(l1>mid) upd(mid+1,r,l1,r1,val,ind*2+1);
        else{
            upd(l,mid,l1,r1,val,ind*2);upd(mid+1,r,l1,r1,val,ind*2+1);
        }
        seg[ind]=(seg[ind*2]+seg[ind*2+1])%mol;
        seg3[ind]=(seg3[ind*2]+seg3[ind*2+1])%mol2;
    }
    void u2(int l, int r, int xx, int val, int val2, int ind){
        if(l==r){
            seg[ind]=val;
            seg3[ind]=val2;
            if(val==0)
                seg2[ind]=0;
            else seg2[ind]=1;
            return;
        }
        int mid=l+r>>1;
        if(la[ind]) push(ind);
        if(xx<=mid) u2(l, mid, xx, val, val2, ind*2);
        else u2(mid+1, r, xx, val, val2, ind*2+1);
        seg[ind]=(seg[ind*2]+seg[ind*2+1])%mol;
        seg2[ind]=(seg2[ind*2]+seg2[ind*2+1]);
        seg3[ind]=(seg3[ind*2]+seg3[ind*2+1])%mol2;
    }

    ll val(int l,int r,int l1,int r1,int ind){
        if(l1>r1) return 0;
        if(l1<=l&&r<=r1) return seg[ind];
        int mid=l+r>>1;
        if(la[ind]) push(ind);
        if(r1<=mid) return val(l,mid,l1,r1,ind*2);
        else if(l1>mid) return val(mid+1,r,l1,r1,ind*2+1);
        else return (val(l,mid,l1,r1,ind*2)+val(mid+1,r,l1,r1,ind*2+1))%mol;
    }

    ll val2(int l,int r,int l1,int r1,int ind){
        if(l1>r1) return 0;
        if(l1<=l&&r<=r1) return seg3[ind];
        int mid=l+r>>1;
        if(la[ind]) push(ind);
        if(r1<=mid) return val2(l,mid,l1,r1,ind*2);
        else if(l1>mid) return val2(mid+1,r,l1,r1,ind*2+1);
        else return (val2(l,mid,l1,r1,ind*2)+val2(mid+1,r,l1,r1,ind*2+1))%mol2;
    }
    int big(int l, int r, int xx, int ind){
        if(l==r) return 0;
        int mid=l+r>>1;
        if(xx<=mid) return big(l, mid, xx, ind*2);
        else return seg2[ind*2]+big(mid+1, r, xx, ind*2+1);
    }
}iu;
const int cc = 137;
ll ff(ll g, ll h){
    ll bas=g, ans=1;
    while(h){
        if(h&1) ans*=bas, ans%=mol;
        bas*=bas, bas%=mol;
        h>>=1;
    }
    return ans;
}
ll ff2(ll g, ll h){
    ll bas=g, ans=1;
    while(h){
        if(h&1) ans*=bas, ans%=mol2;
        bas*=bas, bas%=mol2;
        h>>=1;
    }
    return ans;
}
void solve(){
    int k, m, n;
    cin>>k>>m>>n;

    po[0]=1;
    inv[0]=1;
    po2[0]=1, inv2[0]=1;
    for(int i=1;i<=n;i++) po[i]=po[i-1]*cc%mol;
    for(int i=1;i<=n;i++) po2[i]=po2[i-1]*cc%mol2;
    ll iv=ff(cc, mol-2);
    ll iv2=ff2(cc, mol2-2);
    for(int i=1;i<=n;i++) inv[i]=inv[i-1]*iv%mol;
    for(int i=1;i<=n;i++) inv2[i]=inv2[i-1]*iv2%mol2;

    map<ll, vector<int>>ans, ans2;
    for(int i=1;i<=m;i++){
        ll now=0, now2=0;
        vector<int>tot;
        for(int j=1;j<=k;j++){
            ll g;
            cin>>g;
            now2+=g*po2[j], now2%=mol2;
            now+=g*po[j], now%=mol;
            tot.pb(g);
        }
        // cout<<now<<" "<<now2<<"adfas\n";
        ans2[now2]=tot;
        ans[now]=tot;
    }

    vector<int>all, all2;
    for(int i=1;i<=n;i++){
        int g;
        cin>>g;
        all.pb(g);
    }
    all2=all;
    ll nowval=0, nowval2=0;
    iu.init(n);
    sort(all2.begin(), all2.end());
    for(int i=0;i<n;i++){
        int g=lower_bound(all2.begin(), all2.end(), all[i])-all2.begin()+1;
        if(i>=k){
            int gg=lower_bound(all2.begin(), all2.end(), all[i-k])-all2.begin()+1;
            ll vv=iu.val(1, n, gg+1, n, 1);
            ll vv2=iu.val2(1, n, gg+1, n, 1);
            nowval-=vv;
            nowval2-=vv2;
            nowval=(nowval+mol)%mol;
            nowval2=(nowval2+mol2)%mol2;
            int c2=iu.big(1, n, gg, 1);
            nowval-=(c2+1)*po[1]%mol, nowval=(nowval+mol)%mol;
            nowval2-=(c2+1)*po2[1]%mol2, nowval2=(nowval2+mol2)%mol2;
            iu.u2(1, n, gg, 0, 0, 1);
            iu.upd(1, n, 1, n, 1, 1);
            nowval*=inv[1], nowval%=mol;
            nowval2*=inv2[1], nowval2%=mol2;
        }
        int cc=iu.big(1, n, g, 1);
        ll v2=iu.val(1, n, g+1, n, 1);
        ll v22=iu.val2(1, n, g+1, n, 1);
        nowval+=v2, nowval%=mol;
        nowval2+=v22, nowval2%=mol2;
        nowval+=(cc+1)*po[min(i+1, k)], nowval%=mol;
        nowval2+=(cc+1)*po2[min(i+1, k)], nowval2%=mol2;
        iu.u2(1, n, g, po[min(i+1, k)], po2[min(i+1, k)], 1);
        // cout<<i<<" "<<nowval2<<" "<<nowval<<" "<<po[min(i+1, k)]*(cc+1)%mol<<" "<<po2[min(i+1, k)]*(cc+1)%mol2<<" "<<po[min(i+1, k)]<<"\n";
        if(i+1<k) continue;
        if(ans.count(nowval)&&ans2.count(nowval2)){
            for(int ii: ans[nowval]) cout<<ii<<" ";
            return;
        }
    }
    cout<<"0\n";
}


signed main(){
    ios::sync_with_stdio(0);cin.tie(0);
    // int t;
    // cin>>t;
    // while(t--)
    solve();
    return 0;
}
Source code, Language: C++20

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 76948kb

input:

3 2 10
1 2 3
1 3 2
20 35 10 7 99 53 72 33 88 16

output:

1 3 2

result:

ok single line: '1 3 2 '

Test #2:

score: 0
Accepted
time: 7ms
memory: 78324kb

input:

4 5 10
1 2 3 4
1 2 4 3
3 4 1 2
4 1 2 3
4 2 3 1
19 31 9 1 89 48 63 30 78 12

output:

4 2 3 1

result:

ok single line: '4 2 3 1 '

Test #3:

score: 0
Accepted
time: 0ms
memory: 77080kb

input:

3 3 7
1 3 2
2 3 1
2 1 3
11 22 33 44 55 66 77

output:

0

result:

ok single line: '0'

Test #4:

score: 0
Accepted
time: 1226ms
memory: 152624kb

input:

10000 10 1000000
1 5001 2 5002 3 5003 4 5004 5 5005 6 5006 7 5007 8 5008 9 5009 10 5010 11 5011 12 5012 13 5013 14 5014 15 5015 16 5016 17 5017 18 5018 19 5019 20 5020 21 5021 22 5022 23 5023 24 5024 25 5025 26 5026 27 5027 28 5028 29 5029 30 5030 31 5031 32 5032 33 5033 34 5034 35 5035 36 5036 37 5...

output:

1 5001 2 5002 3 5003 4 5004 5 5005 6 5006 7 5007 8 5008 9 5009 10 5010 11 5011 12 5012 13 5013 14 5014 15 5015 16 5016 17 5017 18 5018 19 5019 20 5020 21 5021 22 5022 23 5023 24 5024 25 5025 26 5026 27 5027 28 5028 29 5029 30 5030 31 5031 32 5032 33 5033 34 5034 35 5035 36 5036 37 5037 38 5038 39 50...

result:

ok single line: '1 5001 2 5002 3 5003 4 5004 5 ...4998 9998 4999 9999 5000 10000 '

Test #5:

score: -100
Time Limit Exceeded

input:

10000 10 1000000
7171 4541 8189 3253 6694 2078 7384 1786 7847 5040 953 4126 4806 3532 7875 8531 3543 2706 8565 1509 2092 4125 6110 5251 6314 4574 6726 8900 9328 8639 3990 5234 9012 5023 3289 2825 8038 3593 2249 337 6252 3831 7967 3839 2815 540 3754 1009 8772 2939 2845 5067 6587 2615 375 7252 9940 18...

output:

result:
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