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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#67347#5099. 朝圣道_ZMF_Compile Error//C++112.1kb2022-12-10 12:01:402022-12-10 12:01:42

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你现在查看的是最新测评结果

  • [2023-08-10 23:21:45]
  • System Update: QOJ starts to keep a history of the judgings of all the submissions.
  • [2022-12-10 12:01:42]
  • 评测
  • [2022-12-10 12:01:40]
  • 提交

answer

#include<bits/stdc++.h>
#include "pilgrimage.h"
using namespace std;
//#define int long long
typedef long long ll;

ll exgcd(ll a,ll b,ll &x,ll &y)
{
    if(!b){x=1;y=0;return a;}
    ll res=exgcd(b,a%b,x,y),t;
    t=x;x=y;y=t-a/b*y;
    return res;
}
const int N = 2e6 + 9;
ll p, crt[N];
vector<int> G;
vector<ll> jc[N];
inline ll power(ll a,ll b,ll mod)
{
    ll sm;
    for(sm=1;b;b>>=1,a=a*a%mod)if(b&1)
        sm=sm*a%mod;
    return sm;
}

ll fac(ll n,ll pi,ll pk)
{
    if(!n)return 1;
    ll res=1;
    res = res * jc[pi][pk] % pk;
    res=power(res,n/pk,pk);
    res = res * jc[pi][n % pk] % pk;
    return res*fac(n/pi,pi,pk)%pk;
}

inline ll inv(ll n,ll mod)
{
    ll x,y;
    exgcd(n,mod,x,y);
    return (x+=mod)>mod?x-mod:x;
}
inline ll CR(ll mod) {return inv(p/mod,mod)%p*(p/mod)%p;}
inline ll CRT(ll b,ll mod){return b*crt[mod]%p;}

const int MAXN=11;

static ll n,m;

static ll w[MAXN];

inline ll C(ll n,ll m,ll pi,ll pk)
{
    ll up=fac(n,pi,pk),d1=fac(m,pi,pk),d2=fac(n-m,pi,pk);
    ll k=0;
    for(register ll i=n;i;i/=pi)k+=i/pi;
    for(register ll i=m;i;i/=pi)k-=i/pi;
    for(register ll i=n-m;i;i/=pi)k-=i/pi;
    return up*inv(d1,pk)%pk*inv(d2,pk)%pk*power(pi,k,pk)%pk;
}

inline ll exlucus(ll n,ll m)
{
    ll res=0,pk,tmp=p;
    for(auto v : G)
    {
    	int i = v;
        pk=1;while(tmp%i==0)pk*=i,tmp/=i;
      //  cout << i << " " << pk << endl;
        (res+=CRT(C(n,m,i,pk),pk))%=p;
    }
    return res;
}
void init(int o, int pp)
{
	p = pp;
	int tmp = p;
	for (int i = 1; i <= p; i++) crt[i] = CR(1, i);
    for (ll i = 2; i <= tmp; i++) 
    	if(tmp % i == 0)
    	{
    		G.push_back(i);
    		ll pk = 1; while(tmp % i == 0) pk *= i, tmp /= i; 
    		jc[i].push_back(1); jc[i].push_back(1); ll now = 1;
    		for (ll j = 2; j <= pk; j++) 
    		{
    			if(j % i) now = now * j % pk; 
    			jc[i].push_back(now);
    		}
		}
	return ;
}
int ask(ll n) 
{
	int inv2 = (p + 1) / 2; 
	ll ans = n % p; ans = ans * exlucus(n * 2, n) % p;
    ans = ans * power(inv2, 2 * n, p) % p;
    return (int) ans;
}

详细

answer.code: In function ‘void init(int, int)’:
answer.code:77:49: error: too many arguments to function ‘ll CR(ll)’
   77 |         for (int i = 1; i <= p; i++) crt[i] = CR(1, i);
      |                                               ~~^~~~~~
answer.code:42:11: note: declared here
   42 | inline ll CR(ll mod) {return inv(p/mod,mod)%p*(p/mod)%p;}
      |           ^~