QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#673409#7744. ElevatorYuanyin26WA 132ms10548kbC++172.2kb2024-10-24 22:13:592024-10-24 22:13:59

Judging History

你现在查看的是最新测评结果

  • [2024-10-24 22:13:59]
  • 评测
  • 测评结果:WA
  • 用时:132ms
  • 内存:10548kb
  • [2024-10-24 22:13:59]
  • 提交

answer

#include<iostream>
#include<vector>
#include<cstring>
#include<algorithm>
#include<cstdio>
#include<queue>
#include<string.h>
#include <string>
#include<math.h>
#include<set>
#include<unordered_map>
#include<unordered_set>
#include<map>
#include<queue>
#include<stack>
#include<functional>
using namespace std;
#define IOS ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define int long long
#define inf 1e18
const int N = 1e5+7;
const int M = 205;
const int mod = 1e9 + 7;
char* p1, * p2, buf[100000];
#define nc() (p1==p2 && (p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++)
int read()
{
	int x = 0, f = 1;
	char ch = nc();
	while (ch < 48 || ch>57)
	{
		if (ch == '-')
			f = -1;
		ch = nc();
	}
	while (ch >= 48 && ch <= 57)
		x = x * 10 + ch - 48, ch = nc();
	return x * f;
}
struct node
{
	int c;
	int w;
	int f;
};
void solve()
{
	int n, k;
	n = read();
	k = read();
	int mx = -inf;
	vector<node>x;
	vector<int>q;
	for (int i = 1; i <= n; i++)
	{
		int c, w, f;
		c = read();
		w = read();
		f = read();
		x.push_back({ c,w,f });
		q.push_back(f);
		mx = max(mx, f);
	}
	sort(q.begin(), q.end(),greater<int>());
	q.resize(unique(q.begin(), q.end()) - q.begin());

	vector<vector<int>>a(3, vector<int>(mx+1, 0));//重量为i,高度为h的数量
	for (int i = 0; i < n; i++)
	{
		int c, w, f;
		c = x[i].c, w = x[i].w, f = x[i].f;
		a[w][f] += c;
	}
	int sum = 0;
	int re = 0;
	for (auto i:q)//从最高层往下枚举
	{
		if (re)//前面电梯带走他
		{
			if (((int)re / 2) > a[2][i])//空电梯把他带走
			{
				re -= a[2][i] * 2;
				a[2][i] = 0;
			}
			else//带不完
			{
				a[2][i] -= re / 2;
				re %= 2;
			}
			if (re)//还有剩余
			{
				if (((int)re / 2) > a[1][i])//空电梯把他带走
				{
					re -= a[1][i];
					a[1][i] = 0;
				}
				else//带不完
				{
					a[1][i] -= re;
					re = 0;
				}
			}
		}
		int cnt = (a[2][i] * 2 + a[1][i]) / k;
		sum += cnt * i;
		if ((a[2][i] * 2 + a[1][i]) % k)
		{
			re += k - ((a[2][i] * 2 + a[1][i]) % k);
			sum += i;
		}
	}
	printf("%lld\n", sum);
}

signed main()
{
	int T = 1;
	cin >> T;
	while (T--)
	{
		solve();
	}
	return 0;
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 2ms
memory: 6572kb

input:

2
4 6
1 1 8
7 2 5
1 1 7
3 2 6
8 1200000
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345

output:

24
100000

result:

ok 2 lines

Test #2:

score: -100
Wrong Answer
time: 132ms
memory: 10548kb

input:

5501
8 104
5 2 3
6 2 4
5 2 3
6 2 9
8 2 4
2 1 3
7 2 4
8 2 8
1 290
3 1 1
12 12
6 1 2
1 2 2
1 1 2
1 2 4
6 1 1
1 2 5
6 1 4
4 1 4
6 2 4
6 2 5
4 2 5
4 1 4
5 334
1 1 4
1 2 3
4 2 1
5 1 1
2 1 2
13 218
5 2 3
5 1 4
1 2 1
1 2 5
3 2 2
1 1 3
4 2 2
1 2 5
2 2 1
2 1 5
3 2 1
5 2 1
1 1 4
10 260
7 2 1
5 1 1
5 2 4
6 1 6...

output:

9
1
25
4
5
7
1
3
9
6
1
10
4
10
20
7
4
1
8
5
5
7
1
3
23
6
3
3
2
2
2
3
8
1
6
6
9
12
147
7
10
2
7
7
8
6
5
6
1
7
3
5
10
7
7
10
8
1
4
2
3
9
1
5
2
9
1
6
7
7
6
13
18
8
10
4
11
9
2
8
3
5
9
3
6
5
3
2
6
1
3
2
2
1
6
9
6
3
4
8
9
9
2
6
1
2
6
7
5
2
5
21
8
1
2
3
4
9
3
4
6
5
9
6
1
7
3
7
3
2
2
8
7
3
5
9
7
10
7
3
2
4...

result:

wrong answer 3rd lines differ - expected: '23', found: '25'