QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#672097 | #7518. GCD of Pattern Matching | Forever_Young# | WA | 0ms | 3868kb | C++23 | 1.0kb | 2024-10-24 15:37:24 | 2024-10-24 15:37:26 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(int i=1;i<=n;i++)
#define pb push_back
#define mp make_pair
#define data dataa
using LL=long long;
using ULL=unsigned long long;
using LD=long double;
int main()
{
int T;
for(scanf("%d",&T);T--;)
{
int m;
char p[20];
scanf("%d%s",&m,p+1);
int n=strlen(p+1);
ULL pw[20];
pw[0]=1;
rep(i,n-1)pw[i]=pw[i-1]*m;
map<char,ULL>dic;
rep(i,n)dic[p[i]]+=pw[n-i];
ULL a[20];
int cnt=0;
a[cnt=1]=dic[p[1]];
ULL ans=a[1];
for(auto [x,y]:dic)
{
if(x==p[1])continue;
a[++cnt]=y;
ans+=y*(cnt==2?0:cnt-1);
}
if(m==2){printf("%llu\n",ans);continue;}
sort(a+1,a+cnt+1);
// for(int i=2;i<=cnt;i++)rep(j,i-1)ans=gcd(ans,a[i]-a[j]);
if(cnt<m)rep(i,cnt)ans=gcd(ans,a[i]);else ans=gcd(ans,m-1);
printf("%llu\n",ans);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3776kb
input:
5 10 ccpcccpc 10 cpcpcp 10 cpc 4 cpccpc 4 dhcp
output:
10001 10101 1 65 3
result:
ok 5 number(s): "10001 10101 1 65 3"
Test #2:
score: 0
Accepted
time: 0ms
memory: 3768kb
input:
30 2 ab 3 abc 4 abcd 5 abcde 6 abcdef 7 abcdefg 8 abcdefgh 9 abcdefghi 10 abcdefghij 11 abcdefghijk 12 abcdefghijkl 13 abcdefghijklm 14 abcdefghijklmn 15 abcdefghijklmno 16 abcdefghijklmnop 16 a 16 ab 16 abc 16 abcd 16 abcde 16 abcdef 16 abcdefg 16 abcdefgh 16 abcdefghi 16 abcdefghij 16 abcdefghijk ...
output:
2 1 3 2 5 3 7 4 9 5 11 6 13 7 15 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1
result:
ok 30 numbers
Test #3:
score: -100
Wrong Answer
time: 0ms
memory: 3868kb
input:
12 10 abccbaabc 10 abcdeedcba 10 abccbaabccba 3 abccbaabccba 4 abcddcba 4 abcddcbaabcddcba 5 online 5 onlie 6 online 3 ccc 10 ccc 16 aaaaaaaaaaaaaaaa
output:
3 11 11000011 2 3 3 2 2 1 13 111 1229782938247303441
result:
wrong answer 4th numbers differ - expected: '2920', found: '2'