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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#672087 | #9434. Italian Cuisine | bulijiojiodibuliduo# | WA | 0ms | 4068kb | C++17 | 4.4kb | 2024-10-24 15:34:59 | 2024-10-24 15:35:00 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define rep(i,a,n) for (int i=a;i<n;i++)
#define per(i,a,n) for (int i=n-1;i>=a;i--)
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define fi first
#define se second
#define SZ(x) ((int)(x).size())
typedef vector<int> VI;
typedef basic_string<int> BI;
typedef long long ll;
typedef pair<int,int> PII;
typedef long double db;
mt19937 mrand(random_device{}());
const ll mod=1000000007;
int rnd(int x) { return mrand() % x;}
ll powmod(ll a,ll b) {ll res=1;a%=mod; assert(b>=0); for(;b;b>>=1){if(b&1)res=res*a%mod;a=a*a%mod;}return res;}
ll gcd(ll a,ll b) { return b?gcd(b,a%b):a;}
// head
const db EPS = 1e-9;
const db PI = acos(-1.0);
inline int sign(db a) { return a < -EPS ? -1 : a > EPS; }
inline int cmp(db a, db b){ return sign(a-b); }
struct P {
db x, y;
P() {}
P(db _x, db _y) : x(_x), y(_y) {}
P operator+(P p) { return {x + p.x, y + p.y}; }
P operator-(P p) { return {x - p.x, y - p.y}; }
P operator*(db d) { return {x * d, y * d}; }
P operator/(db d) { return {x / d, y / d}; }
bool operator<(P p) const {
int c = cmp(x, p.x);
if (c) return c == -1;
return cmp(y, p.y) == -1;
}
bool operator==(P o) const{
return cmp(x,o.x) == 0 && cmp(y,o.y) == 0;
}
db dot(P p) { return x * p.x + y * p.y; }
db det(P p) { return x * p.y - y * p.x; }
db distTo(P p) { return (*this-p).abs(); }
db alpha() { return atan2(y, x); }
void read() { cin>>x>>y; }
void write() {cout<<"("<<x<<","<<y<<")"<<endl;}
db abs() { return sqrt(abs2());}
db abs2() { return x * x + y * y; }
P rot90() { return P(-y,x);}
P unit() { return *this/abs(); }
int quad() const { return sign(y) == 1 || (sign(y) == 0 && sign(x) >= 0); }
P rot(db an){ return {x*cos(an)-y*sin(an),x*sin(an) + y*cos(an)}; }
};
#define cross(p1,p2,p3) ((p2.x-p1.x)*(p3.y-p1.y)-(p3.x-p1.x)*(p2.y-p1.y))
#define crossOp(p1,p2,p3) sign(cross(p1,p2,p3))
bool chkLL(P p1, P p2, P q1, P q2) {
db a1 = cross(q1, q2, p1), a2 = -cross(q1, q2, p2);
return sign(a1+a2) != 0;
}
P isLL(P p1, P p2, P q1, P q2) {
db a1 = cross(q1, q2, p1), a2 = -cross(q1, q2, p2);
return (p1 * a2 + p2 * a1) / (a1 + a2);
}
bool intersect(db l1,db r1,db l2,db r2){
if(l1>r1) swap(l1,r1); if(l2>r2) swap(l2,r2);
return !( cmp(r1,l2) == -1 || cmp(r2,l1) == -1 );
}
bool isSS(P p1, P p2, P q1, P q2){
return intersect(p1.x,p2.x,q1.x,q2.x) && intersect(p1.y,p2.y,q1.y,q2.y) &&
crossOp(p1,p2,q1) * crossOp(p1,p2,q2) <= 0 && crossOp(q1,q2,p1)
* crossOp(q1,q2,p2) <= 0;
}
bool isSS_strict(P p1, P p2, P q1, P q2){
return crossOp(p1,p2,q1) * crossOp(p1,p2,q2) < 0 && crossOp(q1,q2,p1)
* crossOp(q1,q2,p2) < 0;
}
bool isMiddle(db a, db m, db b) {
return sign(a - m) == 0 || sign(b - m) == 0 || (a < m != b < m);
}
bool isMiddle(P a, P m, P b) {
return isMiddle(a.x, m.x, b.x) && isMiddle(a.y, m.y, b.y);
}
bool onSeg(P p1, P p2, P q){
return crossOp(p1,p2,q) == 0 && isMiddle(p1, q, p2);
}
bool onSeg_strict(P p1, P p2, P q){
return crossOp(p1,p2,q) == 0 && sign((q-p1).dot(p1-p2)) * sign((q-p2).dot(p1-p2)) < 0;
}
P proj(P p1, P p2, P q) {
P dir = p2 - p1;
return p1 + dir * (dir.dot(q - p1) / dir.abs2());
}
P reflect(P p1, P p2, P q){
return proj(p1,p2,q) * 2 - q;
}
db nearest(P p1,P p2,P q){
if (p1==p2) return p1.distTo(q);
P h = proj(p1,p2,q);
if(isMiddle(p1,h,p2))
return q.distTo(h);
return min(p1.distTo(q),p2.distTo(q));
}
db disSS(P p1, P p2, P q1, P q2){
if(isSS(p1,p2,q1,q2)) return 0;
return min(min(nearest(p1,p2,q1),nearest(p1,p2,q2)), min(nearest(q1,q2,p1),nearest(q1,q2,p2)));
}
const int N=1010000;
int n,xc,yc,R;
ll s[N];
void solve() {
scanf("%d",&n);
scanf("%d%d%d",&xc,&yc,&R);
P o(xc,yc);
vector<P> p(n);
rep(i,0,n) {
int x,y;
scanf("%d%d",&x,&y);
p[i]=P(x,y);
}
int r=0;
auto onleft=[&](P o,int R,P p1,P p2) {
if (crossOp(p1,p2,o)!=1) return false;
P dir=p2-p1;
return cmp((p1-o).det(dir)/dir.abs(),R)>=0;
};
rep(i,0,2*n+1) s[i+1]=s[i]+(ll)p[i%n].det(p[(i+1)%n]);
ll ans=0;
rep(l,0,n) {
if (l==r) r++;
while (onleft(o,R,p[l],p[r%n])) r++;
ll ret=s[r-1]-s[l]+(ll)p[(r-1)%n].det(p[l]);
ans=max(ans,ret);
//printf("%d %d %lld\n",l,r,ret);
}
printf("%lld\n",ans);
}
int _;
int main() {
for (scanf("%d",&_);_;_--) {
solve();
}
}
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 4068kb
input:
3 5 1 1 1 0 0 1 0 5 0 3 3 0 5 6 2 4 1 2 0 4 0 6 3 4 6 2 6 0 3 4 3 3 1 3 0 6 3 3 6 0 3
output:
5 24 0
result:
ok 3 number(s): "5 24 0"
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 3880kb
input:
1 6 0 0 499999993 197878055 -535013568 696616963 -535013568 696616963 40162440 696616963 499999993 -499999993 499999993 -499999993 -535013568
output:
286862654137719264
result:
wrong answer 1st numbers differ - expected: '0', found: '286862654137719264'