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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#671980#5141. Identical ParityRepeater#WA 9ms3716kbC++20940b2024-10-24 15:12:422024-10-24 15:12:43

Judging History

你现在查看的是最新测评结果

  • [2024-10-24 15:12:43]
  • 评测
  • 测评结果:WA
  • 用时:9ms
  • 内存:3716kb
  • [2024-10-24 15:12:42]
  • 提交

answer

#include<bits/stdc++.h>

using namespace std;

using i64 = long long;

void exgcd(i64 a, i64 b, i64& x, i64& y){
	if(b == 0){
		x = 1, y = 0;
		return;
	}
	exgcd(b, a % b, y, x);
	y -= a / b * x;
	return;
}

void solve(){
	int n, k;
	cin >> n >> k;

	int b = n / k, c = n % k;
	int a = b + 1, d = k - c;

	if(n == 1){
		cout << "Yes\n";
	}
	else if(n > 1 && k == 1){
		cout << "No\n";
	}
	else if(d % 2 == 0 && c % 2 == 0) {
		cout << "Yes\n";
	}
	else if(d % 2 == 1 && c % 2 == 1){
		cout << "Yes\n";
	}
	else if(d % 2 == 0 && c % 2 == 1){
		if(min(c - 1, d) >= n)
			cout << "Yes\n";
		else
			cout << "No\n";
	}
	else if(d % 2 == 1 && c % 2 == 0){
		if(min(c - 1, d) >= n - 1 || d == 1)
			cout << "Yes\n";
		else
			cout << "No\n";
	}

	return;
}

signed main(){
	ios::sync_with_stdio(false);
	cin.tie(nullptr);

	int t; cin >> t;
	while(t--) solve();

	return 0;
}

/*

*/

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3712kb

input:

3
3 1
4 2
5 3

output:

No
Yes
Yes

result:

ok 3 token(s): yes count is 2, no count is 1

Test #2:

score: -100
Wrong Answer
time: 9ms
memory: 3716kb

input:

100000
1 1
2 1
2 2
3 1
3 2
3 3
4 1
4 2
4 3
4 4
5 1
5 2
5 3
5 4
5 5
6 1
6 2
6 3
6 4
6 5
6 6
7 1
7 2
7 3
7 4
7 5
7 6
7 7
8 1
8 2
8 3
8 4
8 5
8 6
8 7
8 8
9 1
9 2
9 3
9 4
9 5
9 6
9 7
9 8
9 9
10 1
10 2
10 3
10 4
10 5
10 6
10 7
10 8
10 9
10 10
11 1
11 2
11 3
11 4
11 5
11 6
11 7
11 8
11 9
11 10
11 11
12 1
...

output:

Yes
No
Yes
No
Yes
No
No
Yes
No
Yes
No
Yes
Yes
Yes
No
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
No
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
No
Yes
No
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
Yes
Yes
No
Yes
No
Yes
No
Yes
No
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
No
Yes
Yes
...

result:

wrong answer expected YES, found NO [6th token]